Find kth element in two sorted arrays

Here given code implementation process.

// C Program 
// Find kth element in two sorted arrays
#include <stdio.h>

// Find kth sorted element which is exists in combination of given two arrays
void findElement(int arr1[], int arr2[], int n1, int n2, int k)
{
	if (k <= 0 || k > n1 + n2)
	{
		// When given element are not valid (outside of range)
		printf(" %d-th element not exist \n", k);
	}
	else
	{
		// Loop controlling variable
		int a = 0;
		int b = 0;
		// Define some useful resultant variables
		int counter = 0;
		int result = 0;
		int flag = 0;
		// Find kth element
		while (flag == 0 && (a < n1 || b < n2))
		{
			// element counter
			counter++;
			if (a < n1 && b < n2)
			{
				// When exists both array elements
				if (arr1[a] < arr2[b])
				{
					if (counter == k)
					{
						// When we get result
						result = arr1[a];
						flag = 1;
					}
					a++;
				}
				else
				{
					if (counter == k)
					{
						// When we get result
						result = arr2[b];
						flag = 1;
					}
					b++;
				}
			}
			else if (a < n1)
			{
				if (counter == k)
				{
					// When we get result
					result = arr1[a];
					flag = 1;
				}
				a++;
			}
			else
			{
				if (counter == k)
				{
					// When we get result
					result = arr2[b];
					flag = 1;
				}
				b++;
			}
		}
		// Display result
		printf(" %d-th element is : %d\n", k, result);
	}
}
int main(int argc, char const *argv[])
{
	// Given sorted arrays of integer elements
	int arr1[] = {
		3 , 6 , 8 , 9 , 10 , 14 , 21
	};
	int arr2[] = {
		-1 , 4 , 5 , 12
	};
	// Get the size
	int n1 = sizeof(arr1) / sizeof(arr1[0]);
	int n2 = sizeof(arr2) / sizeof(arr2[0]);
	/*
	    // When combining the elements of sorted array
		[-1,3,4,5,6,8,9,10,12,14,21]
	*/
	// Find 4th element
	findElement(arr1, arr2, n1, n2, 4);
	// Find 7th element
	findElement(arr1, arr2, n1, n2, 7);
	// Find 10th element
	findElement(arr1, arr2, n1, n2, 10);
	// Find 1st element
	findElement(arr1, arr2, n1, n2, 1);
	return 0;
}

Output

 4-th element is : 5
 7-th element is : 9
 10-th element is : 14
 1-th element is : -1
/*
  Java Program for
  Find kth element in two sorted arrays
*/
class Search
{
	// Find kth sorted element which is exists in combination of given two arrays
	public void findElement(int[] arr1, int[] arr2, int n1, int n2, int k)
	{
		if (k <= 0 || k > n1 + n2)
		{
			// When given element are not valid (outside of range)
			System.out.print( k + "-th element not exist \n");
		}
		else
		{
			// Loop controlling variable
			int a = 0;
			int b = 0;
			// Define some useful resultant variables
			int counter = 0;
			int result = 0;
			int flag = 0;
			// Find kth element
			while (flag == 0 && (a < n1 || b < n2))
			{
				// element counter
				counter++;
				if (a < n1 && b < n2)
				{
					// When exists both array elements
					if (arr1[a] < arr2[b])
					{
						if (counter == k)
						{
							// When we get result
							result = arr1[a];
							flag = 1;
						}
						a++;
					}
					else
					{
						if (counter == k)
						{
							// When we get result
							result = arr2[b];
							flag = 1;
						}
						b++;
					}
				}
				else if (a < n1)
				{
					if (counter == k)
					{
						// When we get result
						result = arr1[a];
						flag = 1;
					}
					a++;
				}
				else
				{
					if (counter == k)
					{
						// When we get result
						result = arr2[b];
						flag = 1;
					}
					b++;
				}
			}
			// Display result
			System.out.print(" " + k + "-th element is : " + result + "\n");
		}
	}
	public static void main(String[] args)
	{
		Search task = new Search();
		// Given sorted arrays of integer elements
		int[] arr1 = {
			3 , 6 , 8 , 9 , 10 , 14 , 21
		};
		int[] arr2 = {
			-1 , 4 , 5 , 12
		};
		// Get the size
		int n1 = arr1.length;
		int n2 = arr2.length;
		/*
		    // When combining the elements of sorted array
		    [-1,3,4,5,6,8,9,10,12,14,21]
		*/
		// Find 4th element
		task.findElement(arr1, arr2, n1, n2, 4);
		// Find 7th element
		task.findElement(arr1, arr2, n1, n2, 7);
		// Find 10th element
		task.findElement(arr1, arr2, n1, n2, 10);
		// Find 1st element
		task.findElement(arr1, arr2, n1, n2, 1);
	}
}

Output

 4-th element is : 5
 7-th element is : 9
 10-th element is : 14
 1-th element is : -1
// Include header file
#include <iostream>

using namespace std;
/*
  C++ Program for
  Find kth element in two sorted arrays
*/
class Search
{
	public:
		// Find kth sorted element which is exists in combination of given two arrays
		void findElement(int arr1[], int arr2[], int n1, int n2, int k)
		{
			if (k <= 0 || k > n1 + n2)
			{
				// When given element are not valid (outside of range)
				cout << k << "-th element not exist \n";
			}
			else
			{
				// Loop controlling variable
				int a = 0;
				int b = 0;
				// Define some useful resultant variables
				int counter = 0;
				int result = 0;
				int flag = 0;
				// Find kth element
				while (flag == 0 && (a < n1 || b < n2))
				{
					// element counter
					counter++;
					if (a < n1 && b < n2)
					{
						// When exists both array elements
						if (arr1[a] < arr2[b])
						{
							if (counter == k)
							{
								// When we get result
								result = arr1[a];
								flag = 1;
							}
							a++;
						}
						else
						{
							if (counter == k)
							{
								// When we get result
								result = arr2[b];
								flag = 1;
							}
							b++;
						}
					}
					else if (a < n1)
					{
						if (counter == k)
						{
							// When we get result
							result = arr1[a];
							flag = 1;
						}
						a++;
					}
					else
					{
						if (counter == k)
						{
							// When we get result
							result = arr2[b];
							flag = 1;
						}
						b++;
					}
				}
				// Display result
				cout << " " << k << "-th element is : " << result << "\n";
			}
		}
};
int main()
{
	Search task = Search();
	// Given sorted arrays of integer elements
	int arr1[] = {
		3 , 6 , 8 , 9 , 10 , 14 , 21
	};
	int arr2[] = {
		-1 , 4 , 5 , 12
	};
	// Get the size
	int n1 = sizeof(arr1) / sizeof(arr1[0]);
	int n2 = sizeof(arr2) / sizeof(arr2[0]);
	/*
		When combining the elements of sorted array
	    [-1,3,4,5,6,8,9,10,12,14,21]

	*/
	// Find 4th element
	task.findElement(arr1, arr2, n1, n2, 4);
	// Find 7th element
	task.findElement(arr1, arr2, n1, n2, 7);
	// Find 10th element
	task.findElement(arr1, arr2, n1, n2, 10);
	// Find 1st element
	task.findElement(arr1, arr2, n1, n2, 1);
	return 0;
}

Output

 4-th element is : 5
 7-th element is : 9
 10-th element is : 14
 1-th element is : -1
// Include namespace system
using System;
/*
  C# Program for
  Find kth element in two sorted arrays
*/
public class Search
{
	// Find kth sorted element which is exists in combination of given two arrays
	public void findElement(int[] arr1, int[] arr2, int n1, int n2, int k)
	{
		if (k <= 0 || k > n1 + n2)
		{
			// When given element are not valid (outside of range)
			Console.Write(k + "-th element not exist \n");
		}
		else
		{
			// Loop controlling variable
			int a = 0;
			int b = 0;
			// Define some useful resultant variables
			int counter = 0;
			int result = 0;
			int flag = 0;
			// Find kth element
			while (flag == 0 && (a < n1 || b < n2))
			{
				// element counter
				counter++;
				if (a < n1 && b < n2)
				{
					// When exists both array elements
					if (arr1[a] < arr2[b])
					{
						if (counter == k)
						{
							// When we get result
							result = arr1[a];
							flag = 1;
						}
						a++;
					}
					else
					{
						if (counter == k)
						{
							// When we get result
							result = arr2[b];
							flag = 1;
						}
						b++;
					}
				}
				else if (a < n1)
				{
					if (counter == k)
					{
						// When we get result
						result = arr1[a];
						flag = 1;
					}
					a++;
				}
				else
				{
					if (counter == k)
					{
						// When we get result
						result = arr2[b];
						flag = 1;
					}
					b++;
				}
			}
			// Display result
			Console.Write(" " + k + "-th element is : " + result + "\n");
		}
	}
	public static void Main(String[] args)
	{
		Search task = new Search();
		// Given sorted arrays of integer elements
		int[] arr1 = {
			3 , 6 , 8 , 9 , 10 , 14 , 21
		};
		int[] arr2 = {
			-1 , 4 , 5 , 12
		};
		// Get the size
		int n1 = arr1.Length;
		int n2 = arr2.Length;
		/*
			When combining the elements of sorted array
		    [-1,3,4,5,6,8,9,10,12,14,21]

		*/
		// Find 4th element
		task.findElement(arr1, arr2, n1, n2, 4);
		// Find 7th element
		task.findElement(arr1, arr2, n1, n2, 7);
		// Find 10th element
		task.findElement(arr1, arr2, n1, n2, 10);
		// Find 1st element
		task.findElement(arr1, arr2, n1, n2, 1);
	}
}

Output

 4-th element is : 5
 7-th element is : 9
 10-th element is : 14
 1-th element is : -1
<?php
/*
  Php Program for
  Find kth element in two sorted arrays
*/
class Search
{
	// Find kth sorted element which is exists in combination of given two arrays
	public	function findElement( $arr1, $arr2, $n1, $n2, $k)
	{
		if ($k <= 0 || $k > $n1 + $n2)
		{
			// When given element are not valid (outside of range)
			echo $k ."-th element not exist \n";
		}
		else
		{
			// Loop controlling variable
			$a = 0;
			$b = 0;
			// Define some useful resultant variables
			$counter = 0;
			$result = 0;
			$flag = 0;
			// Find kth element
			while ($flag == 0 && ($a < $n1 || $b < $n2))
			{
				// element counter
				$counter++;
				if ($a < $n1 && $b < $n2)
				{
					// When exists both array elements
					if ($arr1[$a] < $arr2[$b])
					{
						if ($counter == $k)
						{
							// When we get result
							$result = $arr1[$a];
							$flag = 1;
						}
						$a++;
					}
					else
					{
						if ($counter == $k)
						{
							// When we get result
							$result = $arr2[$b];
							$flag = 1;
						}
						$b++;
					}
				}
				else if ($a < $n1)
				{
					if ($counter == $k)
					{
						// When we get result
						$result = $arr1[$a];
						$flag = 1;
					}
					$a++;
				}
				else
				{
					if ($counter == $k)
					{
						// When we get result
						$result = $arr2[$b];
						$flag = 1;
					}
					$b++;
				}
			}
			// Display result
			echo " ". $k ."-th element is : ". $result ."\n";
		}
	}
}

function main()
{
	$task = new Search();
	// Given sorted arrays of integer elements
	$arr1 = array(3, 6, 8, 9, 10, 14, 21);
	$arr2 = array(-1, 4, 5, 12);
	// Get the size
	$n1 = count($arr1);
	$n2 = count($arr2);
	/*
		When combining the elements of sorted array
	    [-1,3,4,5,6,8,9,10,12,14,21]

	*/
	// Find 4th element
	$task->findElement($arr1, $arr2, $n1, $n2, 4);
	// Find 7th element
	$task->findElement($arr1, $arr2, $n1, $n2, 7);
	// Find 10th element
	$task->findElement($arr1, $arr2, $n1, $n2, 10);
	// Find 1st element
	$task->findElement($arr1, $arr2, $n1, $n2, 1);
}
main();

Output

 4-th element is : 5
 7-th element is : 9
 10-th element is : 14
 1-th element is : -1
/*
  Node Js Program for
  Find kth element in two sorted arrays
*/
class Search
{
	// Find kth sorted element which is exists in combination of given two arrays
	findElement(arr1, arr2, n1, n2, k)
	{
		if (k <= 0 || k > n1 + n2)
		{
			// When given element are not valid (outside of range)
			process.stdout.write(k + "-th element not exist \n");
		}
		else
		{
			// Loop controlling variable
			var a = 0;
			var b = 0;
			// Define some useful resultant variables
			var counter = 0;
			var result = 0;
			var flag = 0;
			// Find kth element
			while (flag == 0 && (a < n1 || b < n2))
			{
				// element counter
				counter++;
				if (a < n1 && b < n2)
				{
					// When exists both array elements
					if (arr1[a] < arr2[b])
					{
						if (counter == k)
						{
							// When we get result
							result = arr1[a];
							flag = 1;
						}
						a++;
					}
					else
					{
						if (counter == k)
						{
							// When we get result
							result = arr2[b];
							flag = 1;
						}
						b++;
					}
				}
				else if (a < n1)
				{
					if (counter == k)
					{
						// When we get result
						result = arr1[a];
						flag = 1;
					}
					a++;
				}
				else
				{
					if (counter == k)
					{
						// When we get result
						result = arr2[b];
						flag = 1;
					}
					b++;
				}
			}
			// Display result
			process.stdout.write(" " + k + "-th element is : " + result + "\n");
		}
	}
}

function main()
{
	var task = new Search();
	// Given sorted arrays of integer elements
	var arr1 = [3, 6, 8, 9, 10, 14, 21];
	var arr2 = [-1, 4, 5, 12];
	// Get the size
	var n1 = arr1.length;
	var n2 = arr2.length;
	/*
		When combining the elements of sorted array
	    [-1,3,4,5,6,8,9,10,12,14,21]
	*/
	// Find 4th element
	task.findElement(arr1, arr2, n1, n2, 4);
	// Find 7th element
	task.findElement(arr1, arr2, n1, n2, 7);
	// Find 10th element
	task.findElement(arr1, arr2, n1, n2, 10);
	// Find 1st element
	task.findElement(arr1, arr2, n1, n2, 1);
}
main();

Output

 4-th element is : 5
 7-th element is : 9
 10-th element is : 14
 1-th element is : -1
#   Python 3 Program for
#   Find kth element in two sorted arrays

class Search :
	#  Find kth sorted element which is exists in combination of given two arrays
	def findElement(self, arr1, arr2, n1, n2, k) :
		if (k <= 0 or k > n1 + n2) :
			#  When given element are not valid (outside of range)
			print(k ,"-th element not exist ")
		else :
			#  Loop controlling variable
			a = 0
			b = 0
			#  Define some useful resultant variables
			counter = 0
			result = 0
			flag = 0
			#  Find kth element
			while (flag == 0 and(a < n1 or b < n2)) :
				#  element counter
				counter += 1
				if (a < n1 and b < n2) :
					#  When exists both array elements
					if (arr1[a] < arr2[b]) :
						if (counter == k) :
							#  When we get result
							result = arr1[a]
							flag = 1
						
						a += 1
					else :
						if (counter == k) :
							#  When we get result
							result = arr2[b]
							flag = 1
						
						b += 1
					
				
				elif(a < n1) :
					if (counter == k) :
						#  When we get result
						result = arr1[a]
						flag = 1
					
					a += 1
				else :
					if (counter == k) :
						#  When we get result
						result = arr2[b]
						flag = 1
					
					b += 1
				
			
			#  Display result
			print(" ", k ,"-th element is : ", result )
		
	

def main() :
	task = Search()
	#  Given sorted arrays of integer elements
	arr1 = [3, 6, 8, 9, 10, 14, 21]
	arr2 = [-1, 4, 5, 12]
	#  Get the size
	n1 = len(arr1)
	n2 = len(arr2)
	# 
	# 	When combining the elements of sorted array
	#     [-1,3,4,5,6,8,9,10,12,14,21]
	
	#  Find 4th element
	task.findElement(arr1, arr2, n1, n2, 4)
	#  Find 7th element
	task.findElement(arr1, arr2, n1, n2, 7)
	#  Find 10th element
	task.findElement(arr1, arr2, n1, n2, 10)
	#  Find 1st element
	task.findElement(arr1, arr2, n1, n2, 1)

if __name__ == "__main__": main()

Output

  4 -th element is :  5
  7 -th element is :  9
  10 -th element is :  14
  1 -th element is :  -1
#   Ruby Program for
#   Find kth element in two sorted arrays

class Search 
	#  Find kth sorted element which is exists in combination of given two arrays
	def findElement(arr1, arr2, n1, n2, k) 
		if (k <= 0 || k > n1 + n2) 
			#  When given element are not valid (outside of range)
			print(k ,"-th element not exist \n")
		else 
			#  Loop controlling variable
			a = 0
			b = 0
			#  Define some useful resultant variables
			counter = 0
			result = 0
			flag = 0
			#  Find kth element
			while (flag == 0 && (a < n1 || b < n2)) 
				#  element counter
				counter += 1
				if (a < n1 && b < n2) 
					#  When exists both array elements
					if (arr1[a] < arr2[b]) 
						if (counter == k) 
							#  When we get result
							result = arr1[a]
							flag = 1
						end

						a += 1
					else 
						if (counter == k) 
							#  When we get result
							result = arr2[b]
							flag = 1
						end

						b += 1
					end

				elsif(a < n1) 
					if (counter == k) 
						#  When we get result
						result = arr1[a]
						flag = 1
					end

					a += 1
				else 
					if (counter == k) 
						#  When we get result
						result = arr2[b]
						flag = 1
					end

					b += 1
				end

			end

			#  Display result
			print(" ", k ,"-th element is : ", result ,"\n")
		end

	end

end

def main() 
	task = Search.new()
	#  Given sorted arrays of integer elements
	arr1 = [3, 6, 8, 9, 10, 14, 21]
	arr2 = [-1, 4, 5, 12]
	#  Get the size
	n1 = arr1.length
	n2 = arr2.length
	# 
	# 	When combining the elements of sorted array
	#     [-1,3,4,5,6,8,9,10,12,14,21]
	
	#  Find 4th element
	task.findElement(arr1, arr2, n1, n2, 4)
	#  Find 7th element
	task.findElement(arr1, arr2, n1, n2, 7)
	#  Find 10th element
	task.findElement(arr1, arr2, n1, n2, 10)
	#  Find 1st element
	task.findElement(arr1, arr2, n1, n2, 1)
end

main()

Output

 4-th element is : 5
 7-th element is : 9
 10-th element is : 14
 1-th element is : -1
/*
  Scala Program for
  Find kth element in two sorted arrays
*/
class Search
{
	// Find kth sorted element which is exists in combination of given two arrays
	def findElement(arr1: Array[Int], arr2: Array[Int], n1: Int, n2: Int, k: Int): Unit = {
		if (k <= 0 || k > n1 + n2)
		{
			// When given element are not valid (outside of range)
			print(" "+k + "-th element not exist \n");
		}
		else
		{
			// Loop controlling variable
			var a: Int = 0;
			var b: Int = 0;
			// Define some useful resultant variables
			var counter: Int = 0;
			var result: Int = 0;
			var flag: Int = 0;
			// Find kth element
			while (flag == 0 && (a < n1 || b < n2))
			{
				// element counter
				counter += 1;
				if (a < n1 && b < n2)
				{
					// When exists both array elements
					if (arr1(a) < arr2(b))
					{
						if (counter == k)
						{
							// When we get result
							result = arr1(a);
							flag = 1;
						}
						a += 1;
					}
					else
					{
						if (counter == k)
						{
							// When we get result
							result = arr2(b);
							flag = 1;
						}
						b += 1;
					}
				}
				else if (a < n1)
				{
					if (counter == k)
					{
						// When we get result
						result = arr1(a);
						flag = 1;
					}
					a += 1;
				}
				else
				{
					if (counter == k)
					{
						// When we get result
						result = arr2(b);
						flag = 1;
					}
					b += 1;
				}
			}
			// Display result
			print(" " + k + "-th element is : " + result + "\n");
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Search = new Search();
		// Given sorted arrays of integer elements
		var arr1: Array[Int] = Array(3, 6, 8, 9, 10, 14, 21);
		var arr2: Array[Int] = Array(-1, 4, 5, 12);
		// Get the size
		var n1: Int = arr1.length;
		var n2: Int = arr2.length;
		/*
			When combining the elements of sorted array
		    [-1,3,4,5,6,8,9,10,12,14,21]
		*/
		// Find 4th element
		task.findElement(arr1, arr2, n1, n2, 4);
		// Find 7th element
		task.findElement(arr1, arr2, n1, n2, 7);
		// Find 10th element
		task.findElement(arr1, arr2, n1, n2, 10);
		// Find 1st element
		task.findElement(arr1, arr2, n1, n2, 1);
	}
}

Output

 4-th element is : 5
 7-th element is : 9
 10-th element is : 14
 1-th element is : -1
/*
  Swift 4 Program for
  Find kth element in two sorted arrays
*/
class Search
{
	// Find kth sorted element which is exists in combination of given two arrays
	func findElement(_ arr1: [Int], _ arr2: [Int], _ n1: Int, _ n2: Int, _ k: Int)
	{
		if (k <= 0 || k > n1 + n2)
		{
			// When given element are not valid (outside of range)
			print(k ,"-th element not exist ");
		}
		else
		{
			// Loop controlling variable
			var a: Int = 0;
			var b: Int = 0;
			// Define some useful resultant variables
			var counter: Int = 0;
			var result: Int = 0;
			var flag: Int = 0;
			// Find kth element
			while (flag == 0 && (a < n1 || b < n2))
			{
				// element counter
				counter += 1;
				if (a < n1 && b < n2)
				{
					// When exists both array elements
					if (arr1[a] < arr2[b])
					{
						if (counter == k)
						{
							// When we get result
							result = arr1[a];
							flag = 1;
						}
						a += 1;
					}
					else
					{
						if (counter == k)
						{
							// When we get result
							result = arr2[b];
							flag = 1;
						}
						b += 1;
					}
				}
				else if (a < n1)
				{
					if (counter == k)
					{
						// When we get result
						result = arr1[a];
						flag = 1;
					}
					a += 1;
				}
				else
				{
					if (counter == k)
					{
						// When we get result
						result = arr2[b];
						flag = 1;
					}
					b += 1;
				}
			}
			// Display result
			print(" ", k ,"-th element is : ", result );
		}
	}
}
func main()
{
	let task: Search = Search();
	// Given sorted arrays of integer elements
	let arr1: [Int] = [3, 6, 8, 9, 10, 14, 21];
	let arr2: [Int] = [-1, 4, 5, 12];
	// Get the size
	let n1: Int = arr1.count;
	let n2: Int = arr2.count;
	/*
		When combining the elements of sorted array
	    [-1,3,4,5,6,8,9,10,12,14,21]
	*/
	// Find 4th element
	task.findElement(arr1, arr2, n1, n2, 4);
	// Find 7th element
	task.findElement(arr1, arr2, n1, n2, 7);
	// Find 10th element
	task.findElement(arr1, arr2, n1, n2, 10);
	// Find 1st element
	task.findElement(arr1, arr2, n1, n2, 1);
}
main();

Output

  4 -th element is :  5
  7 -th element is :  9
  10 -th element is :  14
  1 -th element is :  -1
/*
  Kotlin Program for
  Find kth element in two sorted arrays
*/
class Search
{
	// Find kth sorted element which is exists in combination of given two arrays
	fun findElement(arr1: Array < Int > , arr2: Array<Int> , n1: Int, n2: Int, k: Int): Unit
	{
		if (k <= 0 || k > n1 + n2)
		{
			// When given element are not valid (outside of range)
			print(" "+ k + "-th element not exist \n");
		}
		else
		{
			// Loop controlling variable
			var a: Int = 0;
			var b: Int = 0;
			// Define some useful resultant variables
			var counter: Int = 0;
			var result: Int = 0;
			var flag: Int = 0;
			// Find kth element
			while (flag == 0 && (a < n1 || b < n2))
			{
				// element counter
				counter += 1;
				if (a < n1 && b < n2)
				{
					// When exists both array elements
					if (arr1[a] < arr2[b])
					{
						if (counter == k)
						{
							// When we get result
							result = arr1[a];
							flag = 1;
						}
						a += 1;
					}
					else
					{
						if (counter == k)
						{
							// When we get result
							result = arr2[b];
							flag = 1;
						}
						b += 1;
					}
				}
				else if (a < n1)
				{
					if (counter == k)
					{
						// When we get result
						result = arr1[a];
						flag = 1;
					}
					a += 1;
				}
				else
				{
					if (counter == k)
					{
						// When we get result
						result = arr2[b];
						flag = 1;
					}
					b += 1;
				}
			}
			// Display result
			print(" " + k + "-th element is : " + result + "\n");
		}
	}
}
fun main(args: Array < String > ): Unit
{
	var task: Search = Search();
	// Given sorted arrays of integer elements
	var arr1: Array <Int> = arrayOf(3, 6, 8, 9, 10, 14, 21);
	var arr2: Array <Int> = arrayOf(-1, 4, 5, 12);
	// Get the size
	var n1: Int = arr1.count();
	var n2: Int = arr2.count();
	/*
		When combining the elements of sorted array
	    [-1,3,4,5,6,8,9,10,12,14,21]
	*/
	// Find 4th element
	task.findElement(arr1, arr2, n1, n2, 4);
	// Find 7th element
	task.findElement(arr1, arr2, n1, n2, 7);
	// Find 10th element
	task.findElement(arr1, arr2, n1, n2, 10);
	// Find 1st element
	task.findElement(arr1, arr2, n1, n2, 1);
}

Output

 4-th element is : 5
 7-th element is : 9
 10-th element is : 14
 1-th element is : -1


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