Find the frequency of a number in an array using divide and conquer
Here given code implementation process.
// C Program
// Find the frequency of a number in an array using divide and conquer
#include <stdio.h>
int countFrequency(int arr[], int low, int high, int x)
{
if (low > high)
{
return 0;
}
if (low == high)
{
if (x == arr[low])
{
// We get element
return 1;
}
return 0;
}
// Find middle element
int mid = low + ((high - low) / 2);
// Count element in left and right subtree using recursion
return countFrequency(arr, low, mid, x) +
countFrequency(arr, mid + 1, high, x);
}
int main()
{
int arr1[] = {
4 , 4 , 10 , 3 , 12 , 4 , 6 , 3
};
int arr2[] = {
8 , 20 , 16 , 10 , 6
};
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
int n = sizeof(arr1) / sizeof(arr1[0]);
int x = 3;
printf("\n %d Occurring %d times", x,
countFrequency(arr1, 0, n - 1, x));
x = 4;
printf("\n %d Occurring %d times", x,
countFrequency(arr1, 0, n - 1, x));
n = sizeof(arr2) / sizeof(arr2[0]);
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
x = 16;
printf("\n %d Occurring %d times", x,
countFrequency(arr2, 0, n - 1, x));
x = 9;
printf("\n %d Occurring %d times", x,
countFrequency(arr2, 0, n - 1, x));
return 0;
}
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
// Java Program
// Find the frequency of a number in an array using divide and conquer
public class Counting
{
public int countFrequency(int[] arr, int low, int high, int x)
{
if (low > high)
{
return 0;
}
if (low == high)
{
if (x == arr[low])
{
// We get element
return 1;
}
return 0;
}
// Find middle element
int mid = low + ((high - low) / 2);
// Count element in left and right subtree using recursion
return countFrequency(arr, low, mid, x) +
countFrequency(arr, mid + 1, high, x);
}
public static void main(String args[])
{
Counting task = new Counting();
int[] arr1 = {
4 , 4 , 10 , 3 , 12 , 4 , 6 , 3
};
int[] arr2 = {
8 , 20 , 16 , 10 , 6
};
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
int n = arr1.length;
int x = 3;
System.out.print("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
x = 4;
System.out.print("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
n = arr2.length;
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
x = 16;
System.out.print("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
x = 9;
System.out.print("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
}
}
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
// Include header file
#include <iostream>
using namespace std;
// C++ Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
public: int countFrequency(int arr[], int low, int high, int x)
{
if (low > high)
{
return 0;
}
if (low == high)
{
if (x == arr[low])
{
// We get element
return 1;
}
return 0;
}
// Find middle element
int mid = low + ((high - low) / 2);
// Count element in left and right subtree using recursion
return this->countFrequency(arr, low, mid, x) +
this->countFrequency(arr, mid + 1, high, x);
}
};
int main()
{
Counting *task = new Counting();
int arr1[] = {
4 , 4 , 10 , 3 , 12 , 4 , 6 , 3
};
int arr2[] = {
8 , 20 , 16 , 10 , 6
};
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
int n = sizeof(arr1) / sizeof(arr1[0]);
int x = 3;
cout << "\n " << x << " Occurring "
<< task->countFrequency(arr1, 0, n - 1, x) << " times";
x = 4;
cout << "\n " << x << " Occurring "
<< task->countFrequency(arr1, 0, n - 1, x) << " times";
n = sizeof(arr2) / sizeof(arr2[0]);
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
x = 16;
cout << "\n " << x << " Occurring "
<< task->countFrequency(arr2, 0, n - 1, x) << " times";
x = 9;
cout << "\n " << x << " Occurring "
<< task->countFrequency(arr2, 0, n - 1, x) << " times";
return 0;
}
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
// Include namespace system
using System;
// Csharp Program
// Find the frequency of a number in an array using divide and conquer
public class Counting
{
public int countFrequency(int[] arr,
int low,
int high,
int x)
{
if (low > high)
{
return 0;
}
if (low == high)
{
if (x == arr[low])
{
// We get element
return 1;
}
return 0;
}
// Find middle element
int mid = low + ((high - low) / 2);
// Count element in left and right subtree using recursion
return this.countFrequency(arr, low, mid, x) +
this.countFrequency(arr, mid + 1, high, x);
}
public static void Main(String[] args)
{
Counting task = new Counting();
int[] arr1 = {
4 , 4 , 10 , 3 , 12 , 4 , 6 , 3
};
int[] arr2 = {
8 , 20 , 16 , 10 , 6
};
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
int n = arr1.Length;
int x = 3;
Console.Write("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
x = 4;
Console.Write("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
n = arr2.Length;
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
x = 16;
Console.Write("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
x = 9;
Console.Write("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
}
}
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
package main
import "fmt"
// Go Program
// Find the frequency of a number in an array using divide and conquer
type Counting struct {}
func getCounting() * Counting {
var me *Counting = &Counting {}
return me
}
func(this Counting) countFrequency(arr[] int,
low int, high int, x int) int {
if low > high {
return 0
}
if low == high {
if x == arr[low] {
// We get element
return 1
}
return 0
}
// Find middle element
var mid int = low + ((high - low) / 2)
// Count element in left and right subtree using recursion
return this.countFrequency(arr, low, mid, x) +
this.countFrequency(arr, mid + 1, high, x)
}
func main() {
var task * Counting = getCounting()
var arr1 = [] int {
4,
4,
10,
3,
12,
4,
6,
3,
}
var arr2 = [] int {
8,
20,
16,
10,
6,
}
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
var n int = len(arr1)
var x int = 3
fmt.Print("\n ", x, " Occurring ",
task.countFrequency(arr1, 0, n - 1, x), " times")
x = 4
fmt.Print("\n ", x, " Occurring ",
task.countFrequency(arr1, 0, n - 1, x), " times")
n = len(arr2)
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
x = 16
fmt.Print("\n ", x, " Occurring ",
task.countFrequency(arr2, 0, n - 1, x), " times")
x = 9
fmt.Print("\n ", x, " Occurring ",
task.countFrequency(arr2, 0, n - 1, x), " times")
}
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
<?php
// Php Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
public function countFrequency($arr, $low, $high, $x)
{
if ($low > $high)
{
return 0;
}
if ($low == $high)
{
if ($x == $arr[$low])
{
// We get element
return 1;
}
return 0;
}
// Find middle element
$mid = $low + ((int)(($high - $low) / 2));
// Count element in left and right subtree using recursion
return $this->countFrequency($arr, $low, $mid, $x) +
$this->countFrequency($arr, $mid + 1, $high, $x);
}
}
function main()
{
$task = new Counting();
$arr1 = array(4, 4, 10, 3, 12, 4, 6, 3);
$arr2 = array(8, 20, 16, 10, 6);
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
$n = count($arr1);
$x = 3;
echo("\n ".$x.
" Occurring ".$task->countFrequency($arr1, 0, $n - 1, $x).
" times");
$x = 4;
echo("\n ".$x.
" Occurring ".$task->countFrequency($arr1, 0, $n - 1, $x).
" times");
$n = count($arr2);
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
$x = 16;
echo("\n ".$x.
" Occurring ".$task->countFrequency($arr2, 0, $n - 1, $x).
" times");
$x = 9;
echo("\n ".$x.
" Occurring ".$task->countFrequency($arr2, 0, $n - 1, $x).
" times");
}
main();
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
// Node JS Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
countFrequency(arr, low, high, x)
{
if (low > high)
{
return 0;
}
if (low == high)
{
if (x == arr[low])
{
// We get element
return 1;
}
return 0;
}
// Find middle element
var mid = low + (parseInt((high - low) / 2));
// Count element in left and right subtree using recursion
return this.countFrequency(arr, low, mid, x) +
this.countFrequency(arr, mid + 1, high, x);
}
}
function main()
{
var task = new Counting();
var arr1 = [4, 4, 10, 3, 12, 4, 6, 3];
var arr2 = [8, 20, 16, 10, 6];
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
var n = arr1.length;
var x = 3;
process.stdout.write("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
x = 4;
process.stdout.write("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
n = arr2.length;
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
x = 16;
process.stdout.write("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
x = 9;
process.stdout.write("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
}
main();
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
# Python 3 Program
# Find the frequency of a number in an array using divide and conquer
class Counting :
def countFrequency(self, arr, low, high, x) :
if (low > high) :
return 0
if (low == high) :
if (x == arr[low]) :
# We get element
return 1
return 0
# Find middle element
mid = low + (int((high - low) / 2))
# Count element in left and right subtree using recursion
return self.countFrequency(
arr, low, mid, x
) + self.countFrequency(
arr, mid + 1, high, x
)
def main() :
task = Counting()
arr1 = [4, 4, 10, 3, 12, 4, 6, 3]
arr2 = [8, 20, 16, 10, 6]
# arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
n = len(arr1)
x = 3
print("\n ", x ," Occurring ",
task.countFrequency(arr1, 0, n - 1, x) ," times", end = "")
x = 4
print("\n ", x ," Occurring ",
task.countFrequency(arr1, 0, n - 1, x) ," times", end = "")
n = len(arr2)
# arr2 = [8 , 20 , 16 , 10 , 6]
x = 16
print("\n ", x ," Occurring ",
task.countFrequency(arr2, 0, n - 1, x) ," times", end = "")
x = 9
print("\n ", x ," Occurring ",
task.countFrequency(arr2, 0, n - 1, x) ," times", end = "")
if __name__ == "__main__": main()
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
# Ruby Program
# Find the frequency of a number in an array using divide and conquer
class Counting
def countFrequency(arr, low, high, x)
if (low > high)
return 0
end
if (low == high)
if (x == arr[low])
# We get element
return 1
end
return 0
end
# Find middle element
mid = low + ((high - low) / 2)
# Count element in left and right subtree using recursion
return self.countFrequency(arr, low, mid, x) +
self.countFrequency(arr, mid + 1, high, x)
end
end
def main()
task = Counting.new()
arr1 = [4, 4, 10, 3, 12, 4, 6, 3]
arr2 = [8, 20, 16, 10, 6]
# arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
n = arr1.length
x = 3
print("\n ", x ," Occurring ",
task.countFrequency(arr1, 0, n - 1, x) ," times")
x = 4
print("\n ", x ," Occurring ",
task.countFrequency(arr1, 0, n - 1, x) ," times")
n = arr2.length
# arr2 = [8 , 20 , 16 , 10 , 6]
x = 16
print("\n ", x ," Occurring ",
task.countFrequency(arr2, 0, n - 1, x) ," times")
x = 9
print("\n ", x ," Occurring ",
task.countFrequency(arr2, 0, n - 1, x) ," times")
end
main()
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
// Scala Program
// Find the frequency of a number in an array using divide and conquer
class Counting()
{
def countFrequency(arr: Array[Int],
low: Int, high: Int, x: Int): Int = {
if (low > high)
{
return 0;
}
if (low == high)
{
if (x == arr(low))
{
// We get element
return 1;
}
return 0;
}
// Find middle element
var mid: Int = low + ((high - low) / 2);
// Count element in left and right subtree using recursion
return countFrequency(arr, low, mid, x) +
countFrequency(arr, mid + 1, high, x);
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: Counting = new Counting();
var arr1: Array[Int] = Array(4, 4, 10, 3, 12, 4, 6, 3);
var arr2: Array[Int] = Array(8, 20, 16, 10, 6);
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
var n: Int = arr1.length;
var x: Int = 3;
print("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
x = 4;
print("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
n = arr2.length;
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
x = 16;
print("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
x = 9;
print("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
}
}
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
import Foundation;
// Swift 4 Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
func countFrequency(_ arr: [Int],
_ low: Int,
_ high: Int,
_ x: Int) -> Int
{
if (low > high)
{
return 0;
}
if (low == high)
{
if (x == arr[low])
{
// We get element
return 1;
}
return 0;
}
// Find middle element
let mid: Int = low + ((high - low) / 2);
// Count element in left and right subtree using recursion
return self.countFrequency(arr, low, mid, x) +
self.countFrequency(arr, mid + 1, high, x);
}
}
func main()
{
let task: Counting = Counting();
let arr1: [Int] = [4, 4, 10, 3, 12, 4, 6, 3];
let arr2: [Int] = [8, 20, 16, 10, 6];
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
var n: Int = arr1.count;
var x: Int = 3;
print("\n ", x ," Occurring ",
task.countFrequency(arr1, 0, n - 1, x) ," times", terminator: "");
x = 4;
print("\n ", x ," Occurring ",
task.countFrequency(arr1, 0, n - 1, x) ," times", terminator: "");
n = arr2.count;
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
x = 16;
print("\n ", x ," Occurring ",
task.countFrequency(arr2, 0, n - 1, x) ," times", terminator: "");
x = 9;
print("\n ", x ," Occurring ",
task.countFrequency(arr2, 0, n - 1, x) ," times", terminator: "");
}
main();
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
// Kotlin Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
fun countFrequency(arr: Array < Int > ,
low: Int,
high: Int,
x: Int): Int
{
if (low > high)
{
return 0;
}
if (low == high)
{
if (x == arr[low])
{
// We get element
return 1;
}
return 0;
}
// Find middle element
val mid: Int = low + ((high - low) / 2);
// Count element in left and right subtree using recursion
return this.countFrequency(arr, low, mid, x) +
this.countFrequency(arr, mid + 1, high, x);
}
}
fun main(args: Array < String > ): Unit
{
val task: Counting = Counting();
val arr1: Array < Int > = arrayOf(4, 4, 10, 3, 12, 4, 6, 3);
val arr2: Array < Int > = arrayOf(8, 20, 16, 10, 6);
/*
arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
*/
var n: Int = arr1.count();
var x: Int = 3;
print("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
x = 4;
print("\n " + x + " Occurring " +
task.countFrequency(arr1, 0, n - 1, x) + " times");
n = arr2.count();
/*
arr2 = [8 , 20 , 16 , 10 , 6]
*/
x = 16;
print("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
x = 9;
print("\n " + x + " Occurring " +
task.countFrequency(arr2, 0, n - 1, x) + " times");
}
Output
3 Occurring 2 times
4 Occurring 3 times
16 Occurring 1 times
9 Occurring 0 times
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