« Previous Next »

Find the frequency of a number in an array using divide and conquer

Here given code implementation process.

// C Program
// Find the frequency of a number in an array using divide and conquer
#include <stdio.h>

int countFrequency(int arr[], int low, int high, int x)
{
    if (low > high)
    {
        return 0;
    }
    if (low == high)
    {
        if (x == arr[low])
        {
            // We get element
            return 1;
        }
        return 0;
    }
    // Find middle element
    int mid = low + ((high - low) / 2);
    // Count element in left and right subtree using recursion
    return countFrequency(arr, low, mid, x) + 
      countFrequency(arr, mid + 1, high, x);
}
int main()
{
    int arr1[] = {
        4 , 4 , 10 , 3 , 12 , 4 , 6 , 3
    };
    int arr2[] = {
        8 , 20 , 16 , 10 , 6
    };
    /*
        arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
    */
    int n = sizeof(arr1) / sizeof(arr1[0]);
    int x = 3;
    printf("\n %d Occurring %d times", x, 
           countFrequency(arr1, 0, n - 1, x));
    x = 4;
    printf("\n %d Occurring %d times", x, 
           countFrequency(arr1, 0, n - 1, x));
    n = sizeof(arr2) / sizeof(arr2[0]);
    /*
        arr2 = [8 , 20 , 16 , 10 , 6]
    */
    x = 16;
    printf("\n %d Occurring %d times", x, 
           countFrequency(arr2, 0, n - 1, x));
    x = 9;
    printf("\n %d Occurring %d times", x, 
           countFrequency(arr2, 0, n - 1, x));
    return 0;
}

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

// Java Program 
// Find the frequency of a number in an array using divide and conquer
public class Counting
{
	public int countFrequency(int[] arr, int low, int high, int x)
	{
		if (low > high)
		{
			return 0;
		}
		if (low == high)
		{
			if (x == arr[low])
			{
				// We get element
				return 1;
			}
			return 0;
		}
		// Find middle element
		int mid = low + ((high - low) / 2);
		// Count element in left and right subtree using recursion
		return countFrequency(arr, low, mid, x) + 
			countFrequency(arr, mid + 1, high, x);
	}
	public static void main(String args[])
	{
		Counting task = new Counting();
		int[] arr1 =  {
			4 , 4 , 10 , 3 , 12 , 4 , 6 , 3
		};
		int[] arr2 =  {
			8 , 20 , 16 , 10 , 6
		};
		/*
		    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
		*/
		int n = arr1.length;
		int x = 3;
		System.out.print("\n " + x + " Occurring " + 
                         task.countFrequency(arr1, 0, n - 1, x) + " times");
		x = 4;
		System.out.print("\n " + x + " Occurring " + 
                         task.countFrequency(arr1, 0, n - 1, x) + " times");
		n = arr2.length;
		/*
		    arr2 = [8 , 20 , 16 , 10 , 6]
		*/
		x = 16;
		System.out.print("\n " + x + " Occurring " + 
                         task.countFrequency(arr2, 0, n - 1, x) + " times");
		x = 9;
		System.out.print("\n " + x + " Occurring " + 
                         task.countFrequency(arr2, 0, n - 1, x) + " times");
	}
}

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

// Include header file
#include <iostream>

using namespace std;
// C++ Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
	public: int countFrequency(int arr[], int low, int high, int x)
	{
		if (low > high)
		{
			return 0;
		}
		if (low == high)
		{
			if (x == arr[low])
			{
				// We get element
				return 1;
			}
			return 0;
		}
		// Find middle element
		int mid = low + ((high - low) / 2);
		// Count element in left and right subtree using recursion
		return this->countFrequency(arr, low, mid, x) + 
          this->countFrequency(arr, mid + 1, high, x);
	}
};
int main()
{
	Counting *task = new Counting();
	int arr1[] = {
		4 , 4 , 10 , 3 , 12 , 4 , 6 , 3
	};
	int arr2[] = {
		8 , 20 , 16 , 10 , 6
	};
	/*
	    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
	*/
	int n = sizeof(arr1) / sizeof(arr1[0]);
	int x = 3;
	cout << "\n " << x << " Occurring " 
  		 << task->countFrequency(arr1, 0, n - 1, x) << " times";
	x = 4;
	cout << "\n " << x << " Occurring " 
  		 << task->countFrequency(arr1, 0, n - 1, x) << " times";
	n = sizeof(arr2) / sizeof(arr2[0]);
	/*
	    arr2 = [8 , 20 , 16 , 10 , 6]
	*/
	x = 16;
	cout << "\n " << x << " Occurring " 
         << task->countFrequency(arr2, 0, n - 1, x) << " times";
	x = 9;
	cout << "\n " << x << " Occurring " 
         << task->countFrequency(arr2, 0, n - 1, x) << " times";
	return 0;
}

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

// Include namespace system
using System;
// Csharp Program
// Find the frequency of a number in an array using divide and conquer
public class Counting
{
	public int countFrequency(int[] arr, 
    int low, 
    int high, 
    int x)
	{
		if (low > high)
		{
			return 0;
		}
		if (low == high)
		{
			if (x == arr[low])
			{
				// We get element
				return 1;
			}
			return 0;
		}
		// Find middle element
		int mid = low + ((high - low) / 2);
		// Count element in left and right subtree using recursion
		return this.countFrequency(arr, low, mid, x) + 
          this.countFrequency(arr, mid + 1, high, x);
	}
	public static void Main(String[] args)
	{
		Counting task = new Counting();
		int[] arr1 = {
			4 , 4 , 10 , 3 , 12 , 4 , 6 , 3
		};
		int[] arr2 = {
			8 , 20 , 16 , 10 , 6
		};
		/*
		    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
		*/
		int n = arr1.Length;
		int x = 3;
		Console.Write("\n " + x + " Occurring " + 
                      task.countFrequency(arr1, 0, n - 1, x) + " times");
		x = 4;
		Console.Write("\n " + x + " Occurring " + 
                      task.countFrequency(arr1, 0, n - 1, x) + " times");
		n = arr2.Length;
		/*
		    arr2 = [8 , 20 , 16 , 10 , 6]
		*/
		x = 16;
		Console.Write("\n " + x + " Occurring " + 
                      task.countFrequency(arr2, 0, n - 1, x) + " times");
		x = 9;
		Console.Write("\n " + x + " Occurring " + 
                      task.countFrequency(arr2, 0, n - 1, x) + " times");
	}
}

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

package main
import "fmt"
// Go Program
// Find the frequency of a number in an array using divide and conquer
type Counting struct {}
func getCounting() * Counting {
	var me *Counting = &Counting {}
	return me
}
func(this Counting) countFrequency(arr[] int, 
	low int, high int, x int) int {
	if low > high {
		return 0
	}
	if low == high {
		if x == arr[low] {
			// We get element
			return 1
		}
		return 0
	}
	// Find middle element
	var mid int = low + ((high - low) / 2)
	// Count element in left and right subtree using recursion
	return this.countFrequency(arr, low, mid, x) + 
	this.countFrequency(arr, mid + 1, high, x)
}
func main() {
	var task * Counting = getCounting()
	var arr1 = [] int {
		4,
		4,
		10,
		3,
		12,
		4,
		6,
		3,
	}
	var arr2 = [] int {
		8,
		20,
		16,
		10,
		6,
	}
	/*
	    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
	*/
	var n int = len(arr1)
	var x int = 3
	fmt.Print("\n ", x, " Occurring ", 
		task.countFrequency(arr1, 0, n - 1, x), " times")
	x = 4
	fmt.Print("\n ", x, " Occurring ", 
		task.countFrequency(arr1, 0, n - 1, x), " times")
	n = len(arr2)
	/*
	    arr2 = [8 , 20 , 16 , 10 , 6]
	*/
	x = 16
	fmt.Print("\n ", x, " Occurring ", 
		task.countFrequency(arr2, 0, n - 1, x), " times")
	x = 9
	fmt.Print("\n ", x, " Occurring ", 
		task.countFrequency(arr2, 0, n - 1, x), " times")
}

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

<?php
// Php Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
	public	function countFrequency($arr, $low, $high, $x)
	{
		if ($low > $high)
		{
			return 0;
		}
		if ($low == $high)
		{
			if ($x == $arr[$low])
			{
				// We get element
				return 1;
			}
			return 0;
		}
		// Find middle element
		$mid = $low + ((int)(($high - $low) / 2));
		// Count element in left and right subtree using recursion
		return $this->countFrequency($arr, $low, $mid, $x) + 
          $this->countFrequency($arr, $mid + 1, $high, $x);
	}
}

function main()
{
	$task = new Counting();
	$arr1 = array(4, 4, 10, 3, 12, 4, 6, 3);
	$arr2 = array(8, 20, 16, 10, 6);
	/*
	    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
	*/
	$n = count($arr1);
	$x = 3;
	echo("\n ".$x.
		" Occurring ".$task->countFrequency($arr1, 0, $n - 1, $x).
		" times");
	$x = 4;
	echo("\n ".$x.
		" Occurring ".$task->countFrequency($arr1, 0, $n - 1, $x).
		" times");
	$n = count($arr2);
	/*
	    arr2 = [8 , 20 , 16 , 10 , 6]
	*/
	$x = 16;
	echo("\n ".$x.
		" Occurring ".$task->countFrequency($arr2, 0, $n - 1, $x).
		" times");
	$x = 9;
	echo("\n ".$x.
		" Occurring ".$task->countFrequency($arr2, 0, $n - 1, $x).
		" times");
}
main();

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

// Node JS Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
	countFrequency(arr, low, high, x)
	{
		if (low > high)
		{
			return 0;
		}
		if (low == high)
		{
			if (x == arr[low])
			{
				// We get element
				return 1;
			}
			return 0;
		}
		// Find middle element
		var mid = low + (parseInt((high - low) / 2));
		// Count element in left and right subtree using recursion
		return this.countFrequency(arr, low, mid, x) + 
          this.countFrequency(arr, mid + 1, high, x);
	}
}

function main()
{
	var task = new Counting();
	var arr1 = [4, 4, 10, 3, 12, 4, 6, 3];
	var arr2 = [8, 20, 16, 10, 6];
	/*
	    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
	*/
	var n = arr1.length;
	var x = 3;
	process.stdout.write("\n " + x + " Occurring " + 
                         task.countFrequency(arr1, 0, n - 1, x) + " times");
	x = 4;
	process.stdout.write("\n " + x + " Occurring " + 
                         task.countFrequency(arr1, 0, n - 1, x) + " times");
	n = arr2.length;
	/*
	    arr2 = [8 , 20 , 16 , 10 , 6]
	*/
	x = 16;
	process.stdout.write("\n " + x + " Occurring " + 
                         task.countFrequency(arr2, 0, n - 1, x) + " times");
	x = 9;
	process.stdout.write("\n " + x + " Occurring " + 
                         task.countFrequency(arr2, 0, n - 1, x) + " times");
}
main();

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

#  Python 3 Program
#  Find the frequency of a number in an array using divide and conquer
class Counting :
	def countFrequency(self, arr, low, high, x) :
		if (low > high) :
			return 0
		
		if (low == high) :
			if (x == arr[low]) :
				#  We get element
				return 1
			
			return 0
		
		#  Find middle element
		mid = low + (int((high - low) / 2))
		#  Count element in left and right subtree using recursion
		return self.countFrequency(
          arr, low, mid, x
        ) + self.countFrequency(
          arr, mid + 1, high, x
        )
	

def main() :
	task = Counting()
	arr1 = [4, 4, 10, 3, 12, 4, 6, 3]
	arr2 = [8, 20, 16, 10, 6]
	#    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
	n = len(arr1)
	x = 3
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr1, 0, n - 1, x) ," times", end = "")
	x = 4
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr1, 0, n - 1, x) ," times", end = "")
	n = len(arr2)
	#    arr2 = [8 , 20 , 16 , 10 , 6]
	x = 16
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr2, 0, n - 1, x) ," times", end = "")
	x = 9
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr2, 0, n - 1, x) ," times", end = "")

if __name__ == "__main__": main()

Output

  3  Occurring  2  times
  4  Occurring  3  times
  16  Occurring  1  times
  9  Occurring  0  times

#  Ruby Program
#  Find the frequency of a number in an array using divide and conquer
class Counting 
	def countFrequency(arr, low, high, x) 
		if (low > high) 
			return 0
		end

		if (low == high) 
			if (x == arr[low]) 
				#  We get element
				return 1
			end

			return 0
		end

		#  Find middle element
		mid = low + ((high - low) / 2)
		#  Count element in left and right subtree using recursion
		return self.countFrequency(arr, low, mid, x) + 
          self.countFrequency(arr, mid + 1, high, x)
	end

end

def main() 
	task = Counting.new()
	arr1 = [4, 4, 10, 3, 12, 4, 6, 3]
	arr2 = [8, 20, 16, 10, 6]
	#    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
	n = arr1.length
	x = 3
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr1, 0, n - 1, x) ," times")
	x = 4
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr1, 0, n - 1, x) ," times")
	n = arr2.length
	#    arr2 = [8 , 20 , 16 , 10 , 6]
	x = 16
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr2, 0, n - 1, x) ," times")
	x = 9
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr2, 0, n - 1, x) ," times")
end

main()

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

// Scala Program
// Find the frequency of a number in an array using divide and conquer
class Counting()
{
	def countFrequency(arr: Array[Int], 
      low: Int, high: Int, x: Int): Int = {
		if (low > high)
		{
			return 0;
		}
		if (low == high)
		{
			if (x == arr(low))
			{
				// We get element
				return 1;
			}
			return 0;
		}
		// Find middle element
		var mid: Int = low + ((high - low) / 2);
		// Count element in left and right subtree using recursion
		return countFrequency(arr, low, mid, x) + 
          countFrequency(arr, mid + 1, high, x);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Counting = new Counting();
		var arr1: Array[Int] = Array(4, 4, 10, 3, 12, 4, 6, 3);
		var arr2: Array[Int] = Array(8, 20, 16, 10, 6);
		/*
		    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
		*/
		var n: Int = arr1.length;
		var x: Int = 3;
		print("\n " + x + " Occurring " + 
              task.countFrequency(arr1, 0, n - 1, x) + " times");
		x = 4;
		print("\n " + x + " Occurring " + 
              task.countFrequency(arr1, 0, n - 1, x) + " times");
		n = arr2.length;
		/*
		    arr2 = [8 , 20 , 16 , 10 , 6]
		*/
		x = 16;
		print("\n " + x + " Occurring " + 
              task.countFrequency(arr2, 0, n - 1, x) + " times");
		x = 9;
		print("\n " + x + " Occurring " + 
              task.countFrequency(arr2, 0, n - 1, x) + " times");
	}
}

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

import Foundation;
// Swift 4 Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
	func countFrequency(_ arr: [Int], 
    _ low: Int, 
    	_ high: Int, 
      		_ x: Int) -> Int
	{
		if (low > high)
		{
			return 0;
		}
		if (low == high)
		{
			if (x == arr[low])
			{
				// We get element
				return 1;
			}
			return 0;
		}
		// Find middle element
		let mid: Int = low + ((high - low) / 2);
		// Count element in left and right subtree using recursion
		return self.countFrequency(arr, low, mid, x) + 
          self.countFrequency(arr, mid + 1, high, x);
	}
}
func main()
{
	let task: Counting = Counting();
	let arr1: [Int] = [4, 4, 10, 3, 12, 4, 6, 3];
	let arr2: [Int] = [8, 20, 16, 10, 6];
	/*
	    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
	*/
	var n: Int = arr1.count;
	var x: Int = 3;
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr1, 0, n - 1, x) ," times", terminator: "");
	x = 4;
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr1, 0, n - 1, x) ," times", terminator: "");
	n = arr2.count;
	/*
	    arr2 = [8 , 20 , 16 , 10 , 6]
	*/
	x = 16;
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr2, 0, n - 1, x) ," times", terminator: "");
	x = 9;
	print("\n ", x ," Occurring ", 
          task.countFrequency(arr2, 0, n - 1, x) ," times", terminator: "");
}
main();

Output

  3  Occurring  2  times
  4  Occurring  3  times
  16  Occurring  1  times
  9  Occurring  0  times

// Kotlin Program
// Find the frequency of a number in an array using divide and conquer
class Counting
{
	fun countFrequency(arr: Array < Int > , 
                        low: Int, 
                        high: Int, 
                        x: Int): Int
	{
		if (low > high)
		{
			return 0;
		}
		if (low == high)
		{
			if (x == arr[low])
			{
				// We get element
				return 1;
			}
			return 0;
		}
		// Find middle element
		val mid: Int = low + ((high - low) / 2);
		// Count element in left and right subtree using recursion
		return this.countFrequency(arr, low, mid, x) + 
          this.countFrequency(arr, mid + 1, high, x);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: Counting = Counting();
	val arr1: Array < Int > = arrayOf(4, 4, 10, 3, 12, 4, 6, 3);
	val arr2: Array < Int > = arrayOf(8, 20, 16, 10, 6);
	/*
	    arr1 = [ 4, 4, 10 , 3 , 12 ,4 , 6 , 3]
	*/
	var n: Int = arr1.count();
	var x: Int = 3;
	print("\n " + x + " Occurring " + 
          task.countFrequency(arr1, 0, n - 1, x) + " times");
	x = 4;
	print("\n " + x + " Occurring " + 
          task.countFrequency(arr1, 0, n - 1, x) + " times");
	n = arr2.count();
	/*
	    arr2 = [8 , 20 , 16 , 10 , 6]
	*/
	x = 16;
	print("\n " + x + " Occurring " + 
          task.countFrequency(arr2, 0, n - 1, x) + " times");
	x = 9;
	print("\n " + x + " Occurring " + 
          task.countFrequency(arr2, 0, n - 1, x) + " times");
}

Output

 3 Occurring 2 times
 4 Occurring 3 times
 16 Occurring 1 times
 9 Occurring 0 times

« Previous Next »

Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.