Find even occurring elements in an array of limited range

Here given code implementation process.

// C Program
// Find even occurring elements in an array of limited range
// Element value between 0 to 31
#include <stdio.h>

void repeatedEvenTerm(int data[], int n)
{
	// Define some auxiliary resultant variable
	int location = 0;
	// This is used to determine number which is occurring Even number of times
	int xors = 0;
	// Loop controlling variable i
	int i = 0;
	// Execute loop through by array size
	for (i = 0; i < n; ++i)
	{
		if (data[i] < 0 || data[i] > 31)
		{
			printf("\n Limits are Exceeded ");
			return;
		}
		// Left shift of number 1 by array element 
		location = 1 << data[i];
		// Calculate xor of previous result and new bit location
		xors = xors ^ location;
	}
	// Execute loop through by array size n
	for (i = 0; i < n; ++i)
	{
		// Left shift of number 1 by array element 
		location = 1 << data[i];
		if (!(location & xors))
		{
			printf("   %d", data[i]);
			// reset position
			xors = xors ^ location;
		}
	}
}
int main(int argc, char
	const *argv[])
{
	// Define array of integer element
	int data[] = {
		7 , 8 , 9 , 1 , 7 , 2 , 5 , 9 , 7 , 0 , 3 , 9 , 5 , 0 , 1 , 7
	};
	// Get the size of array
	int n = sizeof(data) / sizeof(data[0]);
	repeatedEvenTerm(data, n);
	return 0;
}

Output

   7   1   5   0
/*
  Java program
  Find even occurring elements in an array of limited range
  Element value between 0 to 31
*/
public class Counting
{
	public void repeatedEvenTerm(int[] data, int n)
	{
		// Define some auxiliary resultant variable
		int location = 0;
		// This is used to determine number which is occurring Even number of times
		int xors = 0;
		// Loop controlling variable i
		int i = 0;
		// Execute loop through by array size
		for (i = 0; i < n; ++i)
		{
			if (data[i] < 0 || data[i] > 31)
			{
				System.out.print("\n Limits are Exceeded ");
				return;
			}
			// Left shift of number 1 by array element 
			location = 1 << data[i];
			// Calculate xor of previous result and new bit location
			xors = xors ^ location;
		}
		// Execute loop through by array size n
		for (i = 0; i < n; ++i)
		{
			// Left shift of number 1 by array element 
			location = 1 << data[i];
			if ((location & xors)==0)
			{
				System.out.print(" " + data[i]);
				// reset position
				xors = xors ^ location;
			}
		}
	}
	public static void main(String[] args)
	{
		Counting task = new Counting();
		// Define array of integer element
		int[] data = {
			7 , 8 , 9 , 1 , 7 , 2 , 5 , 9 , 7 , 0 , 3 , 9 , 5 , 0 , 1 , 7
		};
		// Get the size of array
		int n = data.length;
		task.repeatedEvenTerm(data, n);
	}
}

Output

 7 1 5 0
// Include header file
#include <iostream>
using namespace std;

/*
  C++ program
  Find even occurring elements in an array of limited range
  Element value between 0 to 31
*/
class Counting
{
	public: void repeatedEvenTerm(int data[], int n)
	{
		// Define some auxiliary resultant variable
		int location = 0;
		// This is used to determine number which is occurring Even number of times
		int xors = 0;
		// Loop controlling variable i
		int i = 0;
		// Execute loop through by array size
		for (i = 0; i < n; ++i)
		{
			if (data[i] < 0 || data[i] > 31)
			{
				cout << "\n Limits are Exceeded ";
				return;
			}
			// Left shift of number 1 by array element
			location = 1 << data[i];
			// Calculate xor of previous result and new bit location
			xors = xors ^ location;
		}
		// Execute loop through by array size n
		for (i = 0; i < n; ++i)
		{
			// Left shift of number 1 by array element
			location = 1 << data[i];
			if ((location &xors) == 0)
			{
				cout << " " << data[i];
				// reset position
				xors = xors ^ location;
			}
		}
	}
};
int main()
{
	Counting task = Counting();
	// Define array of integer element
	int data[] = {
		7 , 8 , 9 , 1 , 7 , 2 , 5 , 9 , 7 , 0 , 3 , 9 , 5 , 0 , 1 , 7
	};
	// Get the size of array
	int n = sizeof(data) / sizeof(data[0]);
	task.repeatedEvenTerm(data, n);
	return 0;
}

Output

 7 1 5 0
// Include namespace system
using System;
/*
  C# program
  Find even occurring elements in an array of limited range
  Element value between 0 to 31
*/
public class Counting
{
	public void repeatedEvenTerm(int[] data, int n)
	{
		// Define some auxiliary resultant variable
		int location = 0;
		// This is used to determine number which is occurring Even number of times
		int xors = 0;
		// Loop controlling variable i
		int i = 0;
		// Execute loop through by array size
		for (i = 0; i < n; ++i)
		{
			if (data[i] < 0 || data[i] > 31)
			{
				Console.Write("\n Limits are Exceeded ");
				return;
			}
			// Left shift of number 1 by array element
			location = 1 << data[i];
			// Calculate xor of previous result and new bit location
			xors = xors ^ location;
		}
		// Execute loop through by array size n
		for (i = 0; i < n; ++i)
		{
			// Left shift of number 1 by array element
			location = 1 << data[i];
			if ((location & xors) == 0)
			{
				Console.Write(" " + data[i]);
				// reset bit position
				xors = xors ^ location;
			}
		}
	}
	public static void Main(String[] args)
	{
		Counting task = new Counting();
		// Define array of integer element
		int[] data = {
			7 , 8 , 9 , 1 , 7 , 2 , 5 , 9 , 7 , 0 , 3 , 9 , 5 , 0 , 1 , 7
		};
		// Get the size of array
		int n = data.Length;
		task.repeatedEvenTerm(data, n);
	}
}

Output

 7 1 5 0
<?php
/*
  Php program
  Find even occurring elements in an array of limited range
  Element value between 0 to 31
*/
class Counting
{
	public	function repeatedEvenTerm( & $data, $n)
	{
		// Define some auxiliary resultant variable
		$location = 0;
		// This is used to determine number which is occurring Even number of times
		$xors = 0;
		// Loop controlling variable i
		$i = 0;
		// Execute loop through by array size
		for ($i = 0; $i < $n; ++$i)
		{
			if ($data[$i] < 0 || $data[$i] > 31)
			{
				echo "\n Limits are Exceeded ";
				return;
			}
			// Left shift of number 1 by array element
			$location = 1 << $data[$i];
			// Calculate xor of previous result and new bit location
			$xors = $xors ^ $location;
		}
		// Execute loop through by array size n
		for ($i = 0; $i < $n; ++$i)
		{
			// Left shift of number 1 by array element
			$location = 1 << $data[$i];
			if (($location & $xors) == 0)
			{
				echo " ". $data[$i];
				// reset bit position
				$xors = $xors ^ $location;
			}
		}
	}
}

function main()
{
	$task = new Counting();
	// Define array of integer element
	$data = array(7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7);
	// Get the size of array
	$n = count($data);
	$task->repeatedEvenTerm($data, $n);
}
main();

Output

 7 1 5 0
/*
  Node Js program
  Find even occurring elements in an array of limited range
  Element value between 0 to 31
*/
class Counting
{
	repeatedEvenTerm(data, n)
	{
		// Define some auxiliary resultant variable
		var location = 0;
		// This is used to determine number which is occurring Even number of times
		var xors = 0;
		// Loop controlling variable i
		var i = 0;
		// Execute loop through by array size
		for (i = 0; i < n; ++i)
		{
			if (data[i] < 0 || data[i] > 31)
			{
				process.stdout.write("\n Limits are Exceeded ");
				return;
			}
			// Left shift of number 1 by array element
			location = 1 << data[i];
			// Calculate xor of previous result and new bit location
			xors = xors ^ location;
		}
		// Execute loop through by array size n
		for (i = 0; i < n; ++i)
		{
			// Left shift of number 1 by array element
			location = 1 << data[i];
			if ((location & xors) == 0)
			{
				process.stdout.write(" " + data[i]);
				// reset bit position
				xors = xors ^ location;
			}
		}
	}
}

function main()
{
	var task = new Counting();
	// Define array of integer element
	var data = [7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7];
	// Get the size of array
	var n = data.length;
	task.repeatedEvenTerm(data, n);
}
main();

Output

 7 1 5 0
#   Python 3 program
#   Find even occurring elements in an array of limited range
#   Element value between 0 to 31

class Counting :
	def repeatedEvenTerm(self, data, n) :
		#  Define some auxiliary resultant variable
		location = 0
		#  This is used to determine number which is occurring Even number of times
		xors = 0
		#  Loop controlling variable i
		i = 0
		#  Execute loop through by list size
		while (i < n) :
			if (data[i] < 0 or data[i] > 31) :
				print("\n Limits are Exceeded ", end = "")
				return
			
			#  Left shift of number 1 by list element
			location = 1 << data[i]
			#  Calculate xor of previous result and new bit location
			xors = xors ^ location
			i += 1
		
		#  Execute loop through by list size n
		i = 0
		while (i < n) :
			#  Left shift of number 1 by list element
			location = 1 << data[i]
			if ((location & xors) == 0) :
				print(" ", data[i], end = "")
				#  reset bit position
				xors = xors ^ location
			
			i += 1
		
	

def main() :
	task = Counting()
	#  Define list of integer element
	data = [7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7]
	#  Get the size of list
	n = len(data)
	task.repeatedEvenTerm(data, n)

if __name__ == "__main__": main()

Output

  7  1  5  0
#   Ruby program
#   Find even occurring elements in an array of limited range
#   Element value between 0 to 31

class Counting 
	def repeatedEvenTerm(data, n) 
		#  Define some auxiliary resultant variable
		location = 0
		#  This is used to determine number which is occurring Even number of times
		xors = 0
		#  Loop controlling variable i
		i = 0
		#  Execute loop through by array size
		while (i < n) 
			if (data[i] < 0 || data[i] > 31) 
				print("\n Limits are Exceeded ")
				return
			end

			#  Left shift of number 1 by array element
			location = 1 << data[i]
			#  Calculate xor of previous result and new bit location
			xors = xors ^ location
			i += 1
		end

		#  Execute loop through by array size n
		i = 0
		while (i < n) 
			#  Left shift of number 1 by array element
			location = 1 << data[i]
			if ((location & xors) == 0) 
				print(" ", data[i])
				#  reset bit position
				xors = xors ^ location
			end

			i += 1
		end

	end

end

def main() 
	task = Counting.new()
	#  Define array of integer element
	data = [7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7]
	#  Get the size of array
	n = data.length
	task.repeatedEvenTerm(data, n)
end

main()

Output

 7 1 5 0
/*
  Scala program
  Find even occurring elements in an array of limited range
  Element value between 0 to 31
*/
class Counting
{
	def repeatedEvenTerm(data: Array[Int], n: Int): Unit = {
		// Define some auxiliary resultant variable
		var location: Int = 0;
		// This is used to determine number which is occurring Even number of times
		var xors: Int = 0;
		// Loop controlling variable i
		var i: Int = 0;
		// Execute loop through by array size
		while (i < n)
		{
			if (data(i) < 0 || data(i) > 31)
			{
				print("\n Limits are Exceeded ");
				return;
			}
			// Left shift of number 1 by array element
			location = 1 << data(i);
			// Calculate xor of previous result and new bit location
			xors = xors ^ location;
			i += 1;
		}
		// Execute loop through by array size n
		i = 0;
		while (i < n)
		{
			// Left shift of number 1 by array element
			location = 1 << data(i);
			if ((location & xors) == 0)
			{
				print(" " + data(i));
				// reset bit position
				xors = xors ^ location;
			}
			i += 1;
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Counting = new Counting();
		// Define array of integer element
		var data: Array[Int] = Array(7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7);
		// Get the size of array
		var n: Int = data.length;
		task.repeatedEvenTerm(data, n);
	}
}

Output

 7 1 5 0
/*
  Swift 4 program
  Find even occurring elements in an array of limited range
  Element value between 0 to 31
*/
class Counting
{
	func repeatedEvenTerm(_ data: [Int], _ n: Int)
	{
		// Define some auxiliary resultant variable
		var location: Int = 0;
		// This is used to determine number which is occurring Even number of times
		var xors: Int = 0;
		// Loop controlling variable i
		var i: Int = 0;

		// Execute loop through by array size
		while (i < n)
		{
			if (data[i] < 0 || data[i] > 31)
			{
				print("\n Limits are Exceeded ", terminator: "");
				return;
			}
			// Left shift of number 1 by array element
			location = 1 << data[i];
			// Calculate xor of previous result and new bit location
			xors = xors ^ location;
			i += 1;
		}
		// Execute loop through by array size n
		i = 0;
		while (i < n)
		{
			// Left shift of number 1 by array element
			location = 1 << data[i];
			if ((location & xors) == 0)
			{
				print(" ", data[i], terminator: "");
				// reset bit position
				xors = xors ^ location;
			}
			i += 1;
		}
	}
}
func main()
{
	let task: Counting = Counting();
	// Define array of integer element
	let data: [Int] = [7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7];
	// Get the size of array
	let n: Int = data.count;
	task.repeatedEvenTerm(data, n);
}
main();

Output

  7  1  5  0
/*
  Kotlin program
  Find even occurring elements in an array of limited range
  Element value between 0 to 31
*/
class Counting
{
	fun repeatedEvenTerm(data: Array <Int> , n: Int): Unit
	{
		// Define some auxiliary resultant variable
		var location: Int ;
		// This is used to determine number which is occurring Even number of times
		var xors: Int = 0;
		// Loop controlling variable i
		var i: Int = 0;
		
		// Execute loop through by array size
		while (i < n)
		{
			if (data[i] < 0 || data[i] > 31)
			{
				print("\n Limits are Exceeded ");
				return;
			}
			// Left shift of number 1 by array element
			location = 1 shl data[i];
			// Calculate xor of previous result and new bit location
			xors = xors xor location;
			i += 1;
		}
		// Execute loop through by array size n
		i = 0;
		while (i < n)
		{
			// Left shift of number 1 by array element
			location = 1 shl data[i];
			if ((location and xors) == 0)
			{
				print(" " + data[i]);
				// reset bit position
				xors = xors xor location;
			}
			i += 1;
		}
	}
}
fun main(args: Array < String > ): Unit
{
	var task: Counting = Counting();
	// Define array of integer element
	var data: Array <Int> = arrayOf(7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7);
	// Get the size of array
	var n: Int = data.count();
	task.repeatedEvenTerm(data, n);
}

Output

 7 1 5 0


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