# Find even occurring elements in an array of limited range

Here given code implementation process.

```
// C Program
// Find even occurring elements in an array of limited range
// Element value between 0 to 31
#include <stdio.h>
void repeatedEvenTerm(int data[], int n)
{
// Define some auxiliary resultant variable
int location = 0;
// This is used to determine number which is occurring Even number of times
int xors = 0;
// Loop controlling variable i
int i = 0;
// Execute loop through by array size
for (i = 0; i < n; ++i)
{
if (data[i] < 0 || data[i] > 31)
{
printf("\n Limits are Exceeded ");
return;
}
// Left shift of number 1 by array element
location = 1 << data[i];
// Calculate xor of previous result and new bit location
xors = xors ^ location;
}
// Execute loop through by array size n
for (i = 0; i < n; ++i)
{
// Left shift of number 1 by array element
location = 1 << data[i];
if (!(location & xors))
{
printf(" %d", data[i]);
// reset position
xors = xors ^ location;
}
}
}
int main(int argc, char
const *argv[])
{
// Define array of integer element
int data[] = {
7 , 8 , 9 , 1 , 7 , 2 , 5 , 9 , 7 , 0 , 3 , 9 , 5 , 0 , 1 , 7
};
// Get the size of array
int n = sizeof(data) / sizeof(data[0]);
repeatedEvenTerm(data, n);
return 0;
}
```

#### Output

` 7 1 5 0`

```
/*
Java program
Find even occurring elements in an array of limited range
Element value between 0 to 31
*/
public class Counting
{
public void repeatedEvenTerm(int[] data, int n)
{
// Define some auxiliary resultant variable
int location = 0;
// This is used to determine number which is occurring Even number of times
int xors = 0;
// Loop controlling variable i
int i = 0;
// Execute loop through by array size
for (i = 0; i < n; ++i)
{
if (data[i] < 0 || data[i] > 31)
{
System.out.print("\n Limits are Exceeded ");
return;
}
// Left shift of number 1 by array element
location = 1 << data[i];
// Calculate xor of previous result and new bit location
xors = xors ^ location;
}
// Execute loop through by array size n
for (i = 0; i < n; ++i)
{
// Left shift of number 1 by array element
location = 1 << data[i];
if ((location & xors)==0)
{
System.out.print(" " + data[i]);
// reset position
xors = xors ^ location;
}
}
}
public static void main(String[] args)
{
Counting task = new Counting();
// Define array of integer element
int[] data = {
7 , 8 , 9 , 1 , 7 , 2 , 5 , 9 , 7 , 0 , 3 , 9 , 5 , 0 , 1 , 7
};
// Get the size of array
int n = data.length;
task.repeatedEvenTerm(data, n);
}
}
```

#### Output

` 7 1 5 0`

```
// Include header file
#include <iostream>
using namespace std;
/*
C++ program
Find even occurring elements in an array of limited range
Element value between 0 to 31
*/
class Counting
{
public: void repeatedEvenTerm(int data[], int n)
{
// Define some auxiliary resultant variable
int location = 0;
// This is used to determine number which is occurring Even number of times
int xors = 0;
// Loop controlling variable i
int i = 0;
// Execute loop through by array size
for (i = 0; i < n; ++i)
{
if (data[i] < 0 || data[i] > 31)
{
cout << "\n Limits are Exceeded ";
return;
}
// Left shift of number 1 by array element
location = 1 << data[i];
// Calculate xor of previous result and new bit location
xors = xors ^ location;
}
// Execute loop through by array size n
for (i = 0; i < n; ++i)
{
// Left shift of number 1 by array element
location = 1 << data[i];
if ((location &xors) == 0)
{
cout << " " << data[i];
// reset position
xors = xors ^ location;
}
}
}
};
int main()
{
Counting task = Counting();
// Define array of integer element
int data[] = {
7 , 8 , 9 , 1 , 7 , 2 , 5 , 9 , 7 , 0 , 3 , 9 , 5 , 0 , 1 , 7
};
// Get the size of array
int n = sizeof(data) / sizeof(data[0]);
task.repeatedEvenTerm(data, n);
return 0;
}
```

#### Output

` 7 1 5 0`

```
// Include namespace system
using System;
/*
C# program
Find even occurring elements in an array of limited range
Element value between 0 to 31
*/
public class Counting
{
public void repeatedEvenTerm(int[] data, int n)
{
// Define some auxiliary resultant variable
int location = 0;
// This is used to determine number which is occurring Even number of times
int xors = 0;
// Loop controlling variable i
int i = 0;
// Execute loop through by array size
for (i = 0; i < n; ++i)
{
if (data[i] < 0 || data[i] > 31)
{
Console.Write("\n Limits are Exceeded ");
return;
}
// Left shift of number 1 by array element
location = 1 << data[i];
// Calculate xor of previous result and new bit location
xors = xors ^ location;
}
// Execute loop through by array size n
for (i = 0; i < n; ++i)
{
// Left shift of number 1 by array element
location = 1 << data[i];
if ((location & xors) == 0)
{
Console.Write(" " + data[i]);
// reset bit position
xors = xors ^ location;
}
}
}
public static void Main(String[] args)
{
Counting task = new Counting();
// Define array of integer element
int[] data = {
7 , 8 , 9 , 1 , 7 , 2 , 5 , 9 , 7 , 0 , 3 , 9 , 5 , 0 , 1 , 7
};
// Get the size of array
int n = data.Length;
task.repeatedEvenTerm(data, n);
}
}
```

#### Output

` 7 1 5 0`

```
<?php
/*
Php program
Find even occurring elements in an array of limited range
Element value between 0 to 31
*/
class Counting
{
public function repeatedEvenTerm( & $data, $n)
{
// Define some auxiliary resultant variable
$location = 0;
// This is used to determine number which is occurring Even number of times
$xors = 0;
// Loop controlling variable i
$i = 0;
// Execute loop through by array size
for ($i = 0; $i < $n; ++$i)
{
if ($data[$i] < 0 || $data[$i] > 31)
{
echo "\n Limits are Exceeded ";
return;
}
// Left shift of number 1 by array element
$location = 1 << $data[$i];
// Calculate xor of previous result and new bit location
$xors = $xors ^ $location;
}
// Execute loop through by array size n
for ($i = 0; $i < $n; ++$i)
{
// Left shift of number 1 by array element
$location = 1 << $data[$i];
if (($location & $xors) == 0)
{
echo " ". $data[$i];
// reset bit position
$xors = $xors ^ $location;
}
}
}
}
function main()
{
$task = new Counting();
// Define array of integer element
$data = array(7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7);
// Get the size of array
$n = count($data);
$task->repeatedEvenTerm($data, $n);
}
main();
```

#### Output

` 7 1 5 0`

```
/*
Node Js program
Find even occurring elements in an array of limited range
Element value between 0 to 31
*/
class Counting
{
repeatedEvenTerm(data, n)
{
// Define some auxiliary resultant variable
var location = 0;
// This is used to determine number which is occurring Even number of times
var xors = 0;
// Loop controlling variable i
var i = 0;
// Execute loop through by array size
for (i = 0; i < n; ++i)
{
if (data[i] < 0 || data[i] > 31)
{
process.stdout.write("\n Limits are Exceeded ");
return;
}
// Left shift of number 1 by array element
location = 1 << data[i];
// Calculate xor of previous result and new bit location
xors = xors ^ location;
}
// Execute loop through by array size n
for (i = 0; i < n; ++i)
{
// Left shift of number 1 by array element
location = 1 << data[i];
if ((location & xors) == 0)
{
process.stdout.write(" " + data[i]);
// reset bit position
xors = xors ^ location;
}
}
}
}
function main()
{
var task = new Counting();
// Define array of integer element
var data = [7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7];
// Get the size of array
var n = data.length;
task.repeatedEvenTerm(data, n);
}
main();
```

#### Output

` 7 1 5 0`

```
# Python 3 program
# Find even occurring elements in an array of limited range
# Element value between 0 to 31
class Counting :
def repeatedEvenTerm(self, data, n) :
# Define some auxiliary resultant variable
location = 0
# This is used to determine number which is occurring Even number of times
xors = 0
# Loop controlling variable i
i = 0
# Execute loop through by list size
while (i < n) :
if (data[i] < 0 or data[i] > 31) :
print("\n Limits are Exceeded ", end = "")
return
# Left shift of number 1 by list element
location = 1 << data[i]
# Calculate xor of previous result and new bit location
xors = xors ^ location
i += 1
# Execute loop through by list size n
i = 0
while (i < n) :
# Left shift of number 1 by list element
location = 1 << data[i]
if ((location & xors) == 0) :
print(" ", data[i], end = "")
# reset bit position
xors = xors ^ location
i += 1
def main() :
task = Counting()
# Define list of integer element
data = [7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7]
# Get the size of list
n = len(data)
task.repeatedEvenTerm(data, n)
if __name__ == "__main__": main()
```

#### Output

` 7 1 5 0`

```
# Ruby program
# Find even occurring elements in an array of limited range
# Element value between 0 to 31
class Counting
def repeatedEvenTerm(data, n)
# Define some auxiliary resultant variable
location = 0
# This is used to determine number which is occurring Even number of times
xors = 0
# Loop controlling variable i
i = 0
# Execute loop through by array size
while (i < n)
if (data[i] < 0 || data[i] > 31)
print("\n Limits are Exceeded ")
return
end
# Left shift of number 1 by array element
location = 1 << data[i]
# Calculate xor of previous result and new bit location
xors = xors ^ location
i += 1
end
# Execute loop through by array size n
i = 0
while (i < n)
# Left shift of number 1 by array element
location = 1 << data[i]
if ((location & xors) == 0)
print(" ", data[i])
# reset bit position
xors = xors ^ location
end
i += 1
end
end
end
def main()
task = Counting.new()
# Define array of integer element
data = [7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7]
# Get the size of array
n = data.length
task.repeatedEvenTerm(data, n)
end
main()
```

#### Output

` 7 1 5 0`

```
/*
Scala program
Find even occurring elements in an array of limited range
Element value between 0 to 31
*/
class Counting
{
def repeatedEvenTerm(data: Array[Int], n: Int): Unit = {
// Define some auxiliary resultant variable
var location: Int = 0;
// This is used to determine number which is occurring Even number of times
var xors: Int = 0;
// Loop controlling variable i
var i: Int = 0;
// Execute loop through by array size
while (i < n)
{
if (data(i) < 0 || data(i) > 31)
{
print("\n Limits are Exceeded ");
return;
}
// Left shift of number 1 by array element
location = 1 << data(i);
// Calculate xor of previous result and new bit location
xors = xors ^ location;
i += 1;
}
// Execute loop through by array size n
i = 0;
while (i < n)
{
// Left shift of number 1 by array element
location = 1 << data(i);
if ((location & xors) == 0)
{
print(" " + data(i));
// reset bit position
xors = xors ^ location;
}
i += 1;
}
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: Counting = new Counting();
// Define array of integer element
var data: Array[Int] = Array(7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7);
// Get the size of array
var n: Int = data.length;
task.repeatedEvenTerm(data, n);
}
}
```

#### Output

` 7 1 5 0`

```
/*
Swift 4 program
Find even occurring elements in an array of limited range
Element value between 0 to 31
*/
class Counting
{
func repeatedEvenTerm(_ data: [Int], _ n: Int)
{
// Define some auxiliary resultant variable
var location: Int = 0;
// This is used to determine number which is occurring Even number of times
var xors: Int = 0;
// Loop controlling variable i
var i: Int = 0;
// Execute loop through by array size
while (i < n)
{
if (data[i] < 0 || data[i] > 31)
{
print("\n Limits are Exceeded ", terminator: "");
return;
}
// Left shift of number 1 by array element
location = 1 << data[i];
// Calculate xor of previous result and new bit location
xors = xors ^ location;
i += 1;
}
// Execute loop through by array size n
i = 0;
while (i < n)
{
// Left shift of number 1 by array element
location = 1 << data[i];
if ((location & xors) == 0)
{
print(" ", data[i], terminator: "");
// reset bit position
xors = xors ^ location;
}
i += 1;
}
}
}
func main()
{
let task: Counting = Counting();
// Define array of integer element
let data: [Int] = [7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7];
// Get the size of array
let n: Int = data.count;
task.repeatedEvenTerm(data, n);
}
main();
```

#### Output

` 7 1 5 0`

```
/*
Kotlin program
Find even occurring elements in an array of limited range
Element value between 0 to 31
*/
class Counting
{
fun repeatedEvenTerm(data: Array <Int> , n: Int): Unit
{
// Define some auxiliary resultant variable
var location: Int ;
// This is used to determine number which is occurring Even number of times
var xors: Int = 0;
// Loop controlling variable i
var i: Int = 0;
// Execute loop through by array size
while (i < n)
{
if (data[i] < 0 || data[i] > 31)
{
print("\n Limits are Exceeded ");
return;
}
// Left shift of number 1 by array element
location = 1 shl data[i];
// Calculate xor of previous result and new bit location
xors = xors xor location;
i += 1;
}
// Execute loop through by array size n
i = 0;
while (i < n)
{
// Left shift of number 1 by array element
location = 1 shl data[i];
if ((location and xors) == 0)
{
print(" " + data[i]);
// reset bit position
xors = xors xor location;
}
i += 1;
}
}
}
fun main(args: Array < String > ): Unit
{
var task: Counting = Counting();
// Define array of integer element
var data: Array <Int> = arrayOf(7, 8, 9, 1, 7, 2, 5, 9, 7, 0, 3, 9, 5, 0, 1, 7);
// Get the size of array
var n: Int = data.count();
task.repeatedEvenTerm(data, n);
}
```

#### Output

` 7 1 5 0`

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