Find the closest pair from two sorted arrays

Here given code implementation process.

``````// C Program
// Find the closest pair from two sorted arrays
#include <stdio.h>

#include <limits.h>

//Function which is display array elements
void display(int arr[], int size)
{
for (int i = 0; i < size; ++i)
{
printf("  %d", arr[i]);
}
printf("\n");
}
//Find closest pair of given element in sorted array
void closest_pair(int arr1[], int arr2[], int s1, int s2, int element)
{
//Display array elements
printf("\n Array 1 :");
display(arr1, s1);
printf(" Array 2 :");
display(arr2, s2);
//Loop controlling variables
int i = 0;
int j = s2 - 1;
//Useful resultant variable
int result = INT_MAX;
int first = -1;
int second = -1;
int difference = 0;
printf(" Closest pair of element [%d]  is : ", element);
while (i < s1 && j >= 0)
{
//Calculate difference
difference = ((arr1[i] + arr2[j]) - element);
if (difference < 0)
{
//When difference is negative
difference = -difference;
}
if (difference < result)
{
//When gets a new smallest closest pair
//Get location
first = i;
second = j;
//update resultant difference
result = difference;
}
else if (arr1[i] + arr2[j] > element)
{
//When pair sum is more than given element
//Then reduce the index of second array
j--;
}
else
{
//When resultant pair is less than given element
//Then increase the first array index
i++;
}
}
if (first != -1 && second != -1)
{
//When result are exist
printf("[(%d) + (%d)]\n", arr1[first], arr2[second]);
}
else
{
}
}
int main()
{
//Define array of integer elements
int arr1[] = {
1 , 9 , 13 , 14
};
int arr2[] = {
-5 , 0 , 1 , 8 , 9 , 13 , 14 , 21
};
//Get the size of array
int s1 = sizeof(arr1) / sizeof(arr1[0]);
int s2 = sizeof(arr2) / sizeof(arr2[0]);
int element = 7;
closest_pair(arr1, arr2, s1, s2, element);
int arr3[] = {
1 , 6 , 13 , 14
};
int arr4[] = {
2 , 5 , 11 , 13 , 20
};
//Get the size of array
s1 = sizeof(arr3) / sizeof(arr3[0]);
s2 = sizeof(arr4) / sizeof(arr4[0]);
element = 10;
closest_pair(arr3, arr4, s1, s2, element);
return 0;
}``````

Output

`````` Array 1 :  1  9  13  14
Array 2 :  -5  0  1  8  9  13  14  21
Closest pair of element [7]  is : [(13) + (-5)]

Array 1 :  1  6  13  14
Array 2 :  2  5  11  13  20
Closest pair of element [10]  is : [(6) + (5)]``````
``````// Java Program
// Find the closest pair from two sorted arrays
class MyArray
{
//Function which is display array elements
public void display(int[] arr, int size)
{
for (int i = 0; i < size; ++i)
{
System.out.print(" " + arr[i]);
}
System.out.print("\n");
}
//Find closest pair of given element in sorted array
public void closest_pair(int[] arr1, int[] arr2, int s1, int s2, int element)
{
System.out.print("\n Array 1 :");
display(arr1, s1);
System.out.print(" Array 2 :");
display(arr2, s2);
//Loop controlling variables
int i = 0;
int j = s2 - 1;
//Useful resultant variable
int result = Integer.MAX_VALUE;
int first = -1;
int second = -1;
int difference = 0;
System.out.print(" Closest pair of element [" + element + "] is : ");
while (i < s1 && j >= 0)
{
//Calculate difference
difference = ((arr1[i] + arr2[j]) - element);
if (difference < 0)
{
//When difference is negative
difference = -difference;
}
if (difference < result)
{
//When gets a new smallest closest pair
//Get location
first = i;
second = j;
//update resultant difference
result = difference;
}
else if (arr1[i] + arr2[j] > element)
{
//When pair sum is more than given element
//Then reduce the index of second array
j--;
}
else
{
//When resultant pair is less than given element
//Then increase the first array index
i++;
}
}
if (first != -1 && second != -1)
{
System.out.print("[(" + arr1[first] + ") + (" + arr2[second] + ")]\n");
}
else
{
}
}
public static void main(String[] args)
{
MyArray obj = new MyArray();
//Define array of integer elements
int[] arr1 = {
1,
9,
13,
14
};
int[] arr2 = {
-5,
0,
1,
8,
9,
13,
14,
21
};
//Get the size of array
int s1 = arr1.length;
int s2 = arr2.length;
int element = 7;
obj.closest_pair(arr1, arr2, s1, s2, element);
int[] arr3 = {
1,
6,
13,
14
};
int[] arr4 = {
2,
5,
11,
13,
20
};
//Get the size of array
s1 = arr3.length;
s2 = arr3.length;
element = 10;
obj.closest_pair(arr3, arr4, s1, s2, element);
}
}``````

Output

`````` Array 1 : 1 9 13 14
Array 2 : -5 0 1 8 9 13 14 21
Closest pair of element [7] is : [(13) + (-5)]

Array 1 : 1 6 13 14
Array 2 : 2 5 11 13
Closest pair of element [10] is : [(6) + (5)]``````
``````//Include header file
#include <iostream>

#include<limits.h>

using namespace std;
// C++ Program
// Find the closest pair from two sorted arrays
class MyArray
{
public:
//Function which is display array elements
void display(int arr[], int size)
{
for (int i = 0; i < size; ++i)
{
cout << " " << arr[i];
}
cout << "\n";
}
//Find closest pair of given element in sorted array
void closest_pair(int arr1[], int arr2[], int s1, int s2, int element)
{
cout << "\n Array 1 :";
this->display(arr1, s1);
cout << " Array 2 :";
this->display(arr2, s2);
//Loop controlling variables
int i = 0;
int j = s2 - 1;
//Useful resultant variable
int result = INT_MAX;
int first = -1;
int second = -1;
int difference = 0;
cout << " Closest pair of element [" << element << "] is : ";
while (i < s1 && j >= 0)
{
//Calculate difference
difference = ((arr1[i] + arr2[j]) - element);
if (difference < 0)
{
//When difference is negative
difference = -difference;
}
if (difference < result)
{
//When gets a new smallest closest pair
//Get location
first = i;
second = j;
//update resultant difference
result = difference;
}
else if (arr1[i] + arr2[j] > element)
{
//When pair sum is more than given element
//Then reduce the index of second array
j--;
}
else
{
//When resultant pair is less than given element
//Then increase the first array index
i++;
}
}
if (first != -1 && second != -1)
{
cout << "[(" << arr1[first] << ") + (" << arr2[second] << ")]\n";
}
else
{
}
}
};
int main()
{
MyArray obj = MyArray();
int arr1[] = {
1 , 9 , 13 , 14
};
int arr2[] = {
-5 , 0 , 1 , 8 , 9 , 13 , 14 , 21
};
//Get the size of array
int s1 = sizeof(arr1) / sizeof(arr1[0]);
int s2 = sizeof(arr2) / sizeof(arr2[0]);
int element = 7;
obj.closest_pair(arr1, arr2, s1, s2, element);
int arr3[] = {
1 , 6 , 13 , 14
};
int arr4[] = {
2 , 5 , 11 , 13 , 20
};
//Get the size of array
s1 = sizeof(arr3) / sizeof(arr3[0]);
s2 = sizeof(arr3) / sizeof(arr3[0]);
element = 10;
obj.closest_pair(arr3, arr4, s1, s2, element);
return 0;
}``````

Output

`````` Array 1 : 1 9 13 14
Array 2 : -5 0 1 8 9 13 14 21
Closest pair of element [7] is : [(13) + (-5)]

Array 1 : 1 6 13 14
Array 2 : 2 5 11 13
Closest pair of element [10] is : [(6) + (5)]``````
``````//Include namespace system
using System;
// C# Program
// Find the closest pair from two sorted arrays
class MyArray
{
//Function which is display array elements
public void display(int[] arr, int size)
{
for (int i = 0; i < size; ++i)
{
Console.Write(" " + arr[i]);
}
Console.Write("\n");
}
//Find closest pair of given element in sorted array
public void closest_pair(int[] arr1, int[] arr2, int s1, int s2, int element)
{
Console.Write("\n Array 1 :");
display(arr1, s1);
Console.Write(" Array 2 :");
display(arr2, s2);
//Loop controlling variables
int i = 0;
int j = s2 - 1;
//Useful resultant variable
int result = int.MaxValue;
int first = -1;
int second = -1;
int difference = 0;
Console.Write(" Closest pair of element [" + element + "] is : ");
while (i < s1 && j >= 0)
{
//Calculate difference
difference = ((arr1[i] + arr2[j]) - element);
if (difference < 0)
{
//When difference is negative
difference = -difference;
}
if (difference < result)
{
//When gets a new smallest closest pair
//Get location
first = i;
second = j;
//update resultant difference
result = difference;
}
else if (arr1[i] + arr2[j] > element)
{
//When pair sum is more than given element
//Then reduce the index of second array
j--;
}
else
{
//When resultant pair is less than given element
//Then increase the first array index
i++;
}
}
if (first != -1 && second != -1)
{
Console.Write("[(" + arr1[first] + ") + (" + arr2[second] + ")]\n");
}
else
{
}
}
public static void Main(String[] args)
{
MyArray obj = new MyArray();
int[] arr1 = {
1 , 9 , 13 , 14
};
int[] arr2 = {
-5 , 0 , 1 , 8 , 9 , 13 , 14 , 21
};
//Get the size of array
int s1 = arr1.Length;
int s2 = arr2.Length;
int element = 7;
obj.closest_pair(arr1, arr2, s1, s2, element);
int[] arr3 = {
1 , 6 , 13 , 14
};
int[] arr4 = {
2 , 5 , 11 , 13 , 20
};
//Get the size of array
s1 = arr3.Length;
s2 = arr3.Length;
element = 10;
obj.closest_pair(arr3, arr4, s1, s2, element);
}
}``````

Output

`````` Array 1 : 1 9 13 14
Array 2 : -5 0 1 8 9 13 14 21
Closest pair of element [7] is : [(13) + (-5)]

Array 1 : 1 6 13 14
Array 2 : 2 5 11 13
Closest pair of element [10] is : [(6) + (5)]``````
``````<?php
// Php Program
// Find the closest pair from two sorted arrays
class MyArray
{
//Function which is display array elements
public	function display( \$arr, \$size)
{
for (\$i = 0; \$i < \$size; ++\$i)
{
echo " ". \$arr[\$i];
}
echo "\n";
}
//Find closest pair of given element in sorted array
public	function closest_pair( \$arr1, \$arr2, \$s1, \$s2, \$element)
{
echo "\n Array 1 :";
\$this->display(\$arr1, \$s1);
echo " Array 2 :";
\$this->display(\$arr2, \$s2);
//Loop controlling variables
\$i = 0;
\$j = \$s2 - 1;
//Useful resultant variable
\$result = PHP_INT_MAX;
\$first = -1;
\$second = -1;
\$difference = 0;
echo " Closest pair of element [". \$element ."] is : ";
while (\$i < \$s1 && \$j >= 0)
{
//Calculate difference
\$difference = ((\$arr1[\$i] + \$arr2[\$j]) - \$element);
if (\$difference < 0)
{
//When difference is negative
\$difference = -\$difference;
}
if (\$difference < \$result)
{
//When gets a new smallest closest pair
//Get location
\$first = \$i;
\$second = \$j;
//update resultant difference
\$result = \$difference;
}
else if (\$arr1[\$i] + \$arr2[\$j] > \$element)
{
//When pair sum is more than given element
//Then reduce the index of second array
\$j--;
}
else
{
//When resultant pair is less than given element
//Then increase the first array index
\$i++;
}
}
if (\$first != -1 && \$second != -1)
{
echo "[(". \$arr1[\$first] .") + (". \$arr2[\$second] .")]\n";
}
else
{
}
}
}

function main()
{
\$obj = new MyArray();
//Define array of integer elements
\$arr1 = array(1, 9, 13, 14);
\$arr2 = array(-5, 0, 1, 8, 9, 13, 14, 21);
//Get the size of array
\$s1 = count(\$arr1);
\$s2 = count(\$arr2);
\$element = 7;
\$obj->closest_pair(\$arr1, \$arr2, \$s1, \$s2, \$element);
\$arr3 = array(1, 6, 13, 14);
\$arr4 = array(2, 5, 11, 13, 20);
//Get the size of array
\$s1 = count(\$arr3);
\$s2 = count(\$arr3);
\$element = 10;
\$obj->closest_pair(\$arr3, \$arr4, \$s1, \$s2, \$element);
}
main();``````

Output

`````` Array 1 : 1 9 13 14
Array 2 : -5 0 1 8 9 13 14 21
Closest pair of element [7] is : [(13) + (-5)]

Array 1 : 1 6 13 14
Array 2 : 2 5 11 13
Closest pair of element [10] is : [(6) + (5)]``````
``````// Node Js Program
// Find the closest pair from two sorted arrays
class MyArray
{
//Function which is display array elements
display(arr, size)
{
for (var i = 0; i < size; ++i)
{
process.stdout.write(" " + arr[i]);
}
process.stdout.write("\n");
}
//Find closest pair of given element in sorted array
closest_pair(arr1, arr2, s1, s2, element)
{
process.stdout.write("\n Array 1 :");
this.display(arr1, s1);
process.stdout.write(" Array 2 :");
this.display(arr2, s2);
//Loop controlling variables
var i = 0;
var j = s2 - 1;
//Useful resultant variable
var result = Number.MAX_VALUE;
var first = -1;
var second = -1;
var difference = 0;
process.stdout.write(" Closest pair of element [" + element + "] is : ");
while (i < s1 && j >= 0)
{
//Calculate difference
difference = ((arr1[i] + arr2[j]) - element);
if (difference < 0)
{
//When difference is negative
difference = -difference;
}
if (difference < result)
{
//When gets a new smallest closest pair
//Get location
first = i;
second = j;
//update resultant difference
result = difference;
}
else if (arr1[i] + arr2[j] > element)
{
//When pair sum is more than given element
//Then reduce the index of second array
j--;
}
else
{
//When resultant pair is less than given element
//Then increase the first array index
i++;
}
}
if (first != -1 && second != -1)
{
process.stdout.write("[(" + arr1[first] + ") + (" + arr2[second] + ")]\n");
}
else
{
}
}
}

function main()
{
var obj = new MyArray();
//Define array of integer elements
var arr1 = [1, 9, 13, 14];
var arr2 = [-5, 0, 1, 8, 9, 13, 14, 21];
//Get the size of array
var s1 = arr1.length;
var s2 = arr2.length;
var element = 7;
obj.closest_pair(arr1, arr2, s1, s2, element);
var arr3 = [1, 6, 13, 14];
var arr4 = [2, 5, 11, 13, 20];
//Get the size of array
s1 = arr3.length;
s2 = arr3.length;
element = 10;
obj.closest_pair(arr3, arr4, s1, s2, element);
}
main();``````

Output

`````` Array 1 : 1 9 13 14
Array 2 : -5 0 1 8 9 13 14 21
Closest pair of element [7] is : [(13) + (-5)]

Array 1 : 1 6 13 14
Array 2 : 2 5 11 13
Closest pair of element [10] is : [(6) + (5)]``````
``````import sys
#  Python 3 Program
#  Find the closest pair from two sorted arrays
class MyArray :
# Function which is display array elements
def display(self, arr, size) :
i = 0
while (i < size) :
print(" ", arr[i], end = "")
i += 1

print("\n", end = "")

# Find closest pair of given element in sorted array
def closest_pair(self, arr1, arr2, s1, s2, element) :
print("\n Array 1 :", end = "")
self.display(arr1, s1)
print(" Array 2 :", end = "")
self.display(arr2, s2)
# Loop controlling variables
i = 0
j = s2 - 1
# Useful resultant variable
result = sys.maxsize
first = -1
second = -1
difference = 0
print(" Closest pair of element [", element ,"] is : ", end = "")
while (i < s1 and j >= 0) :
# Calculate difference
difference = ((arr1[i] + arr2[j]) - element)
if (difference < 0) :
# When difference is negative
difference = -difference

if (difference < result) :
# When gets a new smallest closest pair
# Get location
first = i
second = j
# update resultant difference
result = difference

elif(arr1[i] + arr2[j] > element) :
# When pair sum is more than given element
# Then reduce the index of second array
j -= 1
else :
# When resultant pair is less than given element
# Then increase the first array index
i += 1

if (first != -1 and second != -1) :
print("[(", arr1[first] ,") + (", arr2[second] ,")]\n", end = "")
else :

def main() :
obj = MyArray()
# Define array of integer elements
arr1 = [1, 9, 13, 14]
arr2 = [-5, 0, 1, 8, 9, 13, 14, 21]
# Get the size of array
s1 = len(arr1)
s2 = len(arr2)
element = 7
obj.closest_pair(arr1, arr2, s1, s2, element)
arr3 = [1, 6, 13, 14]
arr4 = [2, 5, 11, 13, 20]
# Get the size of array
s1 = len(arr3)
s2 = len(arr3)
element = 10
obj.closest_pair(arr3, arr4, s1, s2, element)

if __name__ == "__main__": main()``````

Output

`````` Array 1 :  1  9  13  14
Array 2 :  -5  0  1  8  9  13  14  21
Closest pair of element [ 7 ] is : [( 13 ) + ( -5 )]

Array 1 :  1  6  13  14
Array 2 :  2  5  11  13
Closest pair of element [ 10 ] is : [( 6 ) + ( 5 )]``````
``````#  Ruby Program
#  Find the closest pair from two sorted arrays
class MyArray

# Function which is display array elements
def display(arr, size)

i = 0
while (i < size)

print(" ", arr[i])
i += 1
end
print("\n")
end
# Find closest pair of given element in sorted array
def closest_pair(arr1, arr2, s1, s2, element)

print("\n Array 1 :")
self.display(arr1, s1)
print(" Array 2 :")
self.display(arr2, s2)
# Loop controlling variables
i = 0
j = s2 - 1
# Useful resultant variable
result = (2 ** (0. size * 8 - 2))
first = -1
second = -1
difference = 0
print(" Closest pair of element [", element ,"] is : ")
while (i < s1 && j >= 0)

# Calculate difference
difference = ((arr1[i] + arr2[j]) - element)
if (difference < 0)

# When difference is negative
difference = -difference
end
if (difference < result)

# When gets a new smallest closest pair
# Get location
first = i
second = j
# update resultant difference
result = difference
elsif(arr1[i] + arr2[j] > element)

# When pair sum is more than given element
# Then reduce the index of second array
j -= 1
else

# When resultant pair is less than given element
# Then increase the first array index
i += 1
end
end
if (first != -1 && second != -1)

print("[(", arr1[first] ,") + (", arr2[second] ,")]\n")
else

end
end
end
def main()

obj = MyArray.new()
# Define array of integer elements
arr1 = [1, 9, 13, 14]
arr2 = [-5, 0, 1, 8, 9, 13, 14, 21]
# Get the size of array
s1 = arr1.length
s2 = arr2.length
element = 7
obj.closest_pair(arr1, arr2, s1, s2, element)
arr3 = [1, 6, 13, 14]
arr4 = [2, 5, 11, 13, 20]
# Get the size of array
s1 = arr3.length
s2 = arr3.length
element = 10
obj.closest_pair(arr3, arr4, s1, s2, element)
end
main()``````

Output

`````` Array 1 : 1 9 13 14
Array 2 : -5 0 1 8 9 13 14 21
Closest pair of element [7] is : [(13) + (-5)]

Array 1 : 1 6 13 14
Array 2 : 2 5 11 13
Closest pair of element [10] is : [(6) + (5)]
``````
``````// Scala Program
// Find the closest pair from two sorted arrays
class MyArray
{
//Function which is display array elements
def display(arr: Array[Int], size: Int): Unit = {
var i: Int = 0;
while (i < size)
{
print(" " + arr(i));
i += 1;
}
print("\n");
}
//Find closest pair of given element in sorted array
def closest_pair(arr1: Array[Int], arr2: Array[Int], s1: Int, s2: Int, element: Int): Unit = {
print("\n Array 1 :");
display(arr1, s1);
print(" Array 2 :");
display(arr2, s2);
//Loop controlling variables
var i: Int = 0;
var j: Int = s2 - 1;
//Useful resultant variable
var result: Int = Int.MaxValue;
var first: Int = -1;
var second: Int = -1;
var difference: Int = 0;
print(" Closest pair of element [" + element + "] is : ");
while (i < s1 && j >= 0)
{
//Calculate difference
difference = ((arr1(i) + arr2(j)) - element);
if (difference < 0)
{
//When difference is negative
difference = -difference;
}
if (difference < result)
{
//When gets a new smallest closest pair
//Get location
first = i;
second = j;
//update resultant difference
result = difference;
}
else if (arr1(i) + arr2(j) > element)
{
//When pair sum is more than given element
//Then reduce the index of second array
j -= 1;
}
else
{
//When resultant pair is less than given element
//Then increase the first array index
i += 1;
}
}
if (first != -1 && second != -1)
{
print("[(" + arr1(first) + ") + (" + arr2(second) + ")]\n");
}
else
{
}
}
}
object Main
{
def main(args: Array[String]): Unit = {
var obj: MyArray = new MyArray();
//Define array of integer elements
var arr1: Array[Int] = Array(1, 9, 13, 14);
var arr2: Array[Int] = Array(-5, 0, 1, 8, 9, 13, 14, 21);
//Get the size of array
var s1: Int = arr1.length;
var s2: Int = arr2.length;
var element: Int = 7;
obj.closest_pair(arr1, arr2, s1, s2, element);
var arr3: Array[Int] = Array(1, 6, 13, 14);
var arr4: Array[Int] = Array(2, 5, 11, 13, 20);
//Get the size of array
s1 = arr3.length;
s2 = arr3.length;
element = 10;
obj.closest_pair(arr3, arr4, s1, s2, element);
}
}``````

Output

`````` Array 1 : 1 9 13 14
Array 2 : -5 0 1 8 9 13 14 21
Closest pair of element [7] is : [(13) + (-5)]

Array 1 : 1 6 13 14
Array 2 : 2 5 11 13
Closest pair of element [10] is : [(6) + (5)]``````
``````// Swift Program
// Find the closest pair from two sorted arrays
class MyArray
{
//Function which is display array elements
func display(_ arr: [Int], _ size: Int)
{
var i: Int = 0;
while (i < size)
{
print(" ", arr[i], terminator: "");
i += 1;
}
print("\n", terminator: "");
}
//Find closest pair of given element in sorted array
func closest_pair(_ arr1: [Int], _ arr2: [Int], _ s1: Int, _ s2: Int, _ element: Int)
{
print("\n Array 1 :", terminator: "");
self.display(arr1, s1);
print(" Array 2 :", terminator: "");
self.display(arr2, s2);
//Loop controlling variables
var i: Int = 0;
var j: Int = s2 - 1;
//Useful resultant variable
var result: Int = Int.max;
var first: Int = -1;
var second: Int = -1;
var difference: Int = 0;
print(" Closest pair of element [", element ,"] is : ", terminator: "");
while (i < s1 && j >= 0)
{
//Calculate difference
difference = ((arr1[i] + arr2[j]) - element);
if (difference < 0)
{
//When difference is negative
difference = -difference;
}
if (difference < result)
{
//When gets a new smallest closest pair
//Get location
first = i;
second = j;
//update resultant difference
result = difference;
}
else if (arr1[i] + arr2[j] > element)
{
//When pair sum is more than given element
//Then reduce the index of second array
j -= 1;
}
else
{
//When resultant pair is less than given element
//Then increase the first array index
i += 1;
}
}
if (first != -1 && second != -1)
{
print("[(", arr1[first] ,") + (", arr2[second] ,")]\n", terminator: "");
}
else
{
}
}
}
func main()
{
let obj: MyArray = MyArray();
//Define array of integer elements
let arr1: [Int] = [1, 9, 13, 14];
let arr2: [Int] = [-5, 0, 1, 8, 9, 13, 14, 21];
//Get the size of array
var s1: Int = arr1.count;
var s2: Int = arr2.count;
var element: Int = 7;
obj.closest_pair(arr1, arr2, s1, s2, element);
let arr3: [Int] = [1, 6, 13, 14];
let arr4: [Int] = [2, 5, 11, 13, 20];
//Get the size of array
s1 = arr3.count;
s2 = arr3.count;
element = 10;
obj.closest_pair(arr3, arr4, s1, s2, element);
}
main();``````

Output

`````` Array 1 :  1  9  13  14
Array 2 :  -5  0  1  8  9  13  14  21
Closest pair of element [ 7 ] is : [( 13 ) + ( -5 )]

Array 1 :  1  6  13  14
Array 2 :  2  5  11  13
Closest pair of element [ 10 ] is : [( 6 ) + ( 5 )]``````

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