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Find all array elements whose digit sum are equal to perfect number

Here given code implementation process.

/*
    Java program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/
public class PerfectNumber
{
    public int digitSum(int num)
    {
        int n = num;

        int result = 0;

        // Calculate digit sum
        while (n != 0)
        {
            // Add last digit
            result += (n % 10);

            // Remove last digit
            n = n / 10;
        }
        return result;
    }
    // Check given number is perfect or not
    public boolean isPerfectNo(int n)
    {
        if (n < 0)
        {
            return false;
        }
        int sum = 0;

        // Calculate sum of divisors of given n
        for (int i = (n / 2); i >= 1; i--)
        {
            if (n % i == 0)
            {
                sum += i;
            }
        }
        if (sum == n)
        {
            // When number is perfect number
            return true;
        }
        else
        {
            return false;
        }
    }
    public void findPerfectNo(int[] arr, int n)
    {
        boolean result = false;

        for (int i = 0; i < n; ++i)
        {
            if (arr[i] > 0 && isPerfectNo(digitSum(arr[i])))
            {
                // When array element is perfect number
                System.out.print("  " + arr[i]);

                // Active result indicator
                result = true;
            }
        }
        if (result == false)
        {
            System.out.print("\n None \n");
        }
    }
    public static void main(String[] args)
    {
        PerfectNumber task = new PerfectNumber();
        int[] arr = {
            5 , 231 , 4 , 60 , -34 , 4888
        };
        int n = arr.length;
        /*
            arr = [5, 231, 4, 60, -34, 4888]
            --------------------------------
            2 + 3 + 1     = 6
            6 + 0         = 6
            4 + 8 + 8 + 8 = 28
            
            Result : [231,60,4888]
        */
        task.findPerfectNo(arr, n);
    }
}

Output

  231  60  4888
/*
    C program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/
#include <stdio.h>


    int digitSum(int num)
    {
        int n = num;

        int result = 0;

        // Calculate digit sum
        while (n != 0)
        {
            // Add last digit
            result += (n % 10);

            // Remove last digit
            n = n / 10;
        }
        return result;
    }
    // Check given number is perfect or not
    int isPerfectNo(int n)
    {
        if (n < 0)
        {
            return 0;
        }
        int sum = 0;

        // Calculate sum of divisors of given n
        for (int i = (n / 2); i >= 1; i--)
        {
            if (n % i == 0)
            {
                sum += i;
            }
        }
        if (sum == n)
        {
            // When number is perfect number
            return 1;
        }
        else
        {
            return 0;
        }
    }
    void findPerfectNo(int arr[], int n)
    {
        int result = 0;

        for (int i = 0; i < n; ++i)
        {
            if (arr[i] > 0 && isPerfectNo(digitSum(arr[i])))
            {
                // When array element is perfect number
                printf("  %d", arr[i]);

                // Active result indicator
                result = 1;
            }
        }
        if (result == 0)
        {
            printf("\n None \n");
        }
    }
int main(int argc, char const *argv[])
{
        int arr[] = 
        {
            5 , 231 , 4 , 60 , -34 , 4888
        };
        int n = sizeof(arr) / sizeof(arr[0]);
        /*
            arr = [5, 231, 4, 60, -34, 4888]
            --------------------------------
            2 + 3 + 1     = 6
            6 + 0         = 6
            4 + 8 + 8 + 8 = 28
            
            Result : [231,60,4888]
        */
        findPerfectNo(arr, n);    
        return 0;
}

Output

  231  60  4888
// Include header file
#include <iostream>

using namespace std;
/*
    C++ program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/
class PerfectNumber
{
	public: int digitSum(int num)
	{
		int n = num;
		int result = 0;
		// Calculate digit sum
		while (n != 0)
		{
			// Add last digit
			result += (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	// Check given number is perfect or not
	bool isPerfectNo(int n)
	{
		if (n < 0)
		{
			return false;
		}
		int sum = 0;
		// Calculate sum of divisors of given n
		for (int i = (n / 2); i >= 1; i--)
		{
			if (n % i == 0)
			{
				sum += i;
			}
		}
		if (sum == n)
		{
			// When number is perfect number
			return true;
		}
		else
		{
			return false;
		}
	}
	void findPerfectNo(int arr[], int n)
	{
		bool result = false;
		for (int i = 0; i < n; ++i)
		{
			if (arr[i] > 0 && 
                this->isPerfectNo(this->digitSum(arr[i])))
			{
				// When array element is perfect number
				cout << "  " << arr[i];
				// Active result indicator
				result = true;
			}
		}
		if (result == false)
		{
			cout << "\n None \n";
		}
	}
};
int main()
{
	PerfectNumber *task = new PerfectNumber();
	int arr[] = {
		5 , 231 , 4 , 60 , -34 , 4888
	};
	int n = sizeof(arr) / sizeof(arr[0]);
	/*
	    arr = [5, 231, 4, 60, -34, 4888]
	    --------------------------------
	    2 + 3 + 1     = 6
	    6 + 0         = 6
	    4 + 8 + 8 + 8 = 28

	    Result : [231,60,4888]
	        
	*/
	task->findPerfectNo(arr, n);
	return 0;
}

Output

  231  60  4888
// Include namespace system
using System;
/*
    Csharp program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/
public class PerfectNumber
{
	public int digitSum(int num)
	{
		int n = num;
		int result = 0;
		// Calculate digit sum
		while (n != 0)
		{
			// Add last digit
			result += (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	// Check given number is perfect or not
	public Boolean isPerfectNo(int n)
	{
		if (n < 0)
		{
			return false;
		}
		int sum = 0;
		// Calculate sum of divisors of given n
		for (int i = (n / 2); i >= 1; i--)
		{
			if (n % i == 0)
			{
				sum += i;
			}
		}
		if (sum == n)
		{
			// When number is perfect number
			return true;
		}
		else
		{
			return false;
		}
	}
	public void findPerfectNo(int[] arr, int n)
	{
		Boolean result = false;
		for (int i = 0; i < n; ++i)
		{
			if (arr[i] > 0 && 
                this.isPerfectNo(this.digitSum(arr[i])))
			{
				// When array element is perfect number
				Console.Write("  " + arr[i]);
				// Active result indicator
				result = true;
			}
		}
		if (result == false)
		{
			Console.Write("\n None \n");
		}
	}
	public static void Main(String[] args)
	{
		PerfectNumber task = new PerfectNumber();
		int[] arr = {
			5 , 231 , 4 , 60 , -34 , 4888
		};
		int n = arr.Length;
		/*
		    arr = [5, 231, 4, 60, -34, 4888]
		    --------------------------------
		    2 + 3 + 1     = 6
		    6 + 0         = 6
		    4 + 8 + 8 + 8 = 28

		    Result : [231,60,4888]
		        
		*/
		task.findPerfectNo(arr, n);
	}
}

Output

  231  60  4888
package main
import "fmt"
/*
    Go program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/

func digitSum(num int) int {
	var n int = num
	var result int = 0
	// Calculate digit sum
	for (n != 0) {
		// Add last digit
		result += (n % 10)
		// Remove last digit
		n = n / 10
	}
	return result
}
// Check given number is perfect or not
func isPerfectNo(n int) bool {
	if n < 0 {
		return false
	}
	var sum int = 0
	// Calculate sum of divisors of given n
	for i :=(n / 2) ; i >= 1 ; i-- {
		if n % i == 0 {
			sum += i
		}
	}
	if sum == n {
		// When number is perfect number
		return true
	} else {
		return false
	}
}
func findPerfectNo(arr[] int, n int) {
	var result bool = false
	for i := 0 ; i < n ; i++ {
		if arr[i] > 0 && 
			isPerfectNo(digitSum(arr[i])) {
			// When array element is perfect number
			fmt.Print("  ", arr[i])
			// Active result indicator
			result = true
		}
	}
	if result == false {
		fmt.Print("\n None \n")
	}
}
func main() {
	
	var arr = [] int { 5 , 231 , 4 , 60 , - 34 , 4888}
	var n int = len(arr)
	/*
	    arr = [5, 231, 4, 60, -34, 4888]
	    --------------------------------
	    2 + 3 + 1     = 6
	    6 + 0         = 6
	    4 + 8 + 8 + 8 = 28

	    Result : [231,60,4888]
	        
	*/
	findPerfectNo(arr, n)
}

Output

  231  60  4888
<?php
/*
    Php program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/
class PerfectNumber
{
	public	function digitSum($num)
	{
		$n = $num;
		$result = 0;
		// Calculate digit sum
		while ($n != 0)
		{
			// Add last digit
			$result += ($n % 10);
			// Remove last digit
			$n = (int)($n / 10);
		}
		return $result;
	}
	// Check given number is perfect or not
	public	function isPerfectNo($n)
	{
		if ($n < 0)
		{
			return false;
		}
		$sum = 0;
		// Calculate sum of divisors of given n
		for ($i = ((int)($n / 2)); $i >= 1; $i--)
		{
			if ($n % $i == 0)
			{
				$sum += $i;
			}
		}
		if ($sum == $n)
		{
			// When number is perfect number
			return true;
		}
		else
		{
			return false;
		}
	}
	public	function findPerfectNo($arr, $n)
	{
		$result = false;
		for ($i = 0; $i < $n; ++$i)
		{
			if ($arr[$i] > 0 && 
                $this->isPerfectNo($this->digitSum($arr[$i])))
			{
				// When array element is perfect number
				echo("  ".$arr[$i]);
				// Active result indicator
				$result = true;
			}
		}
		if ($result == false)
		{
			echo("\n None \n");
		}
	}
}

function main()
{
	$task = new PerfectNumber();
	$arr = array(5, 231, 4, 60, -34, 4888);
	$n = count($arr);
	/*
	    arr = [5, 231, 4, 60, -34, 4888]
	    --------------------------------
	    2 + 3 + 1     = 6
	    6 + 0         = 6
	    4 + 8 + 8 + 8 = 28

	    Result : [231,60,4888]
	        
	*/
	$task->findPerfectNo($arr, $n);
}
main();

Output

  231  60  4888
/*
    Node JS program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/
class PerfectNumber
{
	digitSum(num)
	{
		var n = num;
		var result = 0;
		// Calculate digit sum
		while (n != 0)
		{
			// Add last digit
			result += (n % 10);
			// Remove last digit
			n = parseInt(n / 10);
		}
		return result;
	}
	// Check given number is perfect or not
	isPerfectNo(n)
	{
		if (n < 0)
		{
			return false;
		}
		var sum = 0;
		// Calculate sum of divisors of given n
		for (var i = (parseInt(n / 2)); i >= 1; i--)
		{
			if (n % i == 0)
			{
				sum += i;
			}
		}
		if (sum == n)
		{
			// When number is perfect number
			return true;
		}
		else
		{
			return false;
		}
	}
	findPerfectNo(arr, n)
	{
		var result = false;
		for (var i = 0; i < n; ++i)
		{
			if (arr[i] > 0 && 
                this.isPerfectNo(this.digitSum(arr[i])))
			{
				// When array element is perfect number
				process.stdout.write("  " + arr[i]);
				// Active result indicator
				result = true;
			}
		}
		if (result == false)
		{
			process.stdout.write("\n None \n");
		}
	}
}

function main()
{
	var task = new PerfectNumber();
	var arr = [5, 231, 4, 60, -34, 4888];
	var n = arr.length;
	/*
	    arr = [5, 231, 4, 60, -34, 4888]
	    --------------------------------
	    2 + 3 + 1     = 6
	    6 + 0         = 6
	    4 + 8 + 8 + 8 = 28

	    Result : [231,60,4888]
	        
	*/
	task.findPerfectNo(arr, n);
}
main();

Output

  231  60  4888
#    Python 3 program for
#    Find all array elements whose digit sum 
#    are equal to perfect number
class PerfectNumber :
	def digitSum(self, num) :
		n = num
		result = 0
		#  Calculate digit sum
		while (n != 0) :
			#  Add last digit
			result += (n % 10)
			#  Remove last digit
			n = int(n / 10)
		
		return result
	
	#  Check given number is perfect or not
	def isPerfectNo(self, n) :
		if (n < 0) :
			return False
		
		sum = 0
		i = (int(n / 2))
		#  Calculate sum of divisors of given n
		while (i >= 1) :
			if (n % i == 0) :
				sum += i
			
			i -= 1
		
		if (sum == n) :
			#  When number is perfect number
			return True
		else :
			return False
		
	
	def findPerfectNo(self, arr, n) :
		result = False
		i = 0
		while (i < n) :
			if (arr[i] > 0 and self.isPerfectNo(self.digitSum(arr[i]))) :
				#  When list element is perfect number
				print("  ", arr[i], end = "")
				#  Active result indicator
				result = True
			
			i += 1
		
		if (result == False) :
			print("\n None ")
		
	

def main() :
	task = PerfectNumber()
	arr = [5, 231, 4, 60, -34, 4888]
	n = len(arr)
	#    arr = [5, 231, 4, 60, -34, 4888]
	#    --------------------------------
	#    2 + 3 + 1     = 6
	#    6 + 0         = 6
	#    4 + 8 + 8 + 8 = 28
	#    Result : [231,60,4888]
	task.findPerfectNo(arr, n)

if __name__ == "__main__": main()

Output

   231   60   4888
#    Ruby program for
#    Find all array elements whose digit sum 
#    are equal to perfect number
class PerfectNumber 
	def digitSum(num) 
		n = num
		result = 0
		#  Calculate digit sum
		while (n != 0) 
			#  Add last digit
			result += (n % 10)
			#  Remove last digit
			n = n / 10
		end

		return result
	end

	#  Check given number is perfect or not
	def isPerfectNo(n) 
		if (n < 0) 
			return false
		end

		sum = 0
		i = (n / 2)
		#  Calculate sum of divisors of given n
		while (i >= 1) 
			if (n % i == 0) 
				sum += i
			end

			i -= 1
		end

		if (sum == n) 
			#  When number is perfect number
			return true
		else
 
			return false
		end

	end

	def findPerfectNo(arr, n) 
		result = false
		i = 0
		while (i < n) 
			if (arr[i] > 0 && self.isPerfectNo(self.digitSum(arr[i]))) 
				#  When array element is perfect number
				print("  ", arr[i])
				#  Active result indicator
				result = true
			end

			i += 1
		end

		if (result == false) 
			print("\n None \n")
		end

	end

end

def main() 
	task = PerfectNumber.new()
	arr = [5, 231, 4, 60, -34, 4888]
	n = arr.length
	#    arr = [5, 231, 4, 60, -34, 4888]
	#    --------------------------------
	#    2 + 3 + 1     = 6
	#    6 + 0         = 6
	#    4 + 8 + 8 + 8 = 28
	#    Result : [231,60,4888]
	task.findPerfectNo(arr, n)
end

main()

Output

  231  60  4888
/*
    Scala program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/
class PerfectNumber()
{
	def digitSum(num: Int): Int = {
		var n: Int = num;
		var result: Int = 0;
		// Calculate digit sum
		while (n != 0)
		{
			// Add last digit
			result += (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	// Check given number is perfect or not
	def isPerfectNo(n: Int): Boolean = {
		if (n < 0)
		{
			return false;
		}
		var sum: Int = 0;
		var i: Int = (n / 2);
		// Calculate sum of divisors of given n
		while (i >= 1)
		{
			if (n % i == 0)
			{
				sum += i;
			}
			i -= 1;
		}
		if (sum == n)
		{
			// When number is perfect number
			return true;
		}
		else
		{
			return false;
		}
	}
	def findPerfectNo(arr: Array[Int], n: Int): Unit = {
		var result: Boolean = false;
		var i: Int = 0;
		while (i < n)
		{
			if (arr(i) > 0 && isPerfectNo(digitSum(arr(i))))
			{
				// When array element is perfect number
				print("  " + arr(i));
				// Active result indicator
				result = true;
			}
			i += 1;
		}
		if (result == false)
		{
			print("\n None \n");
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: PerfectNumber = new PerfectNumber();
		var arr: Array[Int] = Array(5, 231, 4, 60, -34, 4888);
		var n: Int = arr.length;
		/*
		    arr = [5, 231, 4, 60, -34, 4888]
		    --------------------------------
		    2 + 3 + 1     = 6
		    6 + 0         = 6
		    4 + 8 + 8 + 8 = 28

		    Result : [231,60,4888]
		        
		*/
		task.findPerfectNo(arr, n);
	}
}

Output

  231  60  4888
import Foundation;
/*
    Swift 4 program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/
class PerfectNumber
{
	func digitSum(_ num: Int) -> Int
	{
		var n: Int = num;
		var result: Int = 0;
		// Calculate digit sum
		while (n  != 0)
		{
			// Add last digit
			result += (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	// Check given number is perfect or not
	func isPerfectNo(_ n: Int) -> Bool
	{
		if (n < 0)
		{
			return false;
		}
		var sum: Int = 0;
		var i: Int = (n / 2);
		// Calculate sum of divisors of given n
		while (i >= 1)
		{
			if (n % i == 0)
			{
				sum += i;
			}
			i -= 1;
		}
		if (sum == n)
		{
			// When number is perfect number
			return true;
		}
		else
		{
			return false;
		}
	}
	func findPerfectNo(_ arr: [Int], _ n: Int)
	{
		var result: Bool = false;
		var i: Int = 0;
		while (i < n)
		{
			if (arr[i] > 0 && self.isPerfectNo(self.digitSum(arr[i])))
			{
				// When array element is perfect number
				print("  ", arr[i], terminator: "");
				// Active result indicator
				result = true;
			}
			i += 1;
		}
		if (result == false)
		{
			print("\n None ");
		}
	}
}
func main()
{
	let task: PerfectNumber = PerfectNumber();
	let arr: [Int] = [5, 231, 4, 60, -34, 4888];
	let n: Int = arr.count;
	/*
	    arr = [5, 231, 4, 60, -34, 4888]
	    --------------------------------
	    2 + 3 + 1     = 6
	    6 + 0         = 6
	    4 + 8 + 8 + 8 = 28

	    Result : [231,60,4888]
	        
	*/
	task.findPerfectNo(arr, n);
}
main();

Output

   231   60   4888
/*
    Kotlin program for
    Find all array elements whose digit sum 
    are equal to perfect number
*/
class PerfectNumber
{
	fun digitSum(num: Int): Int
	{
		var n: Int = num;
		var result: Int = 0;
		// Calculate digit sum
		while (n != 0)
		{
			// Add last digit
			result += (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	// Check given number is perfect or not
	fun isPerfectNo(n: Int): Boolean
	{
		if (n < 0)
		{
			return false;
		}
		var sum: Int = 0;
		var i: Int = (n / 2);
		// Calculate sum of divisors of given n
		while (i >= 1)
		{
			if (n % i == 0)
			{
				sum += i;
			}
			i -= 1;
		}
		if (sum == n)
		{
			// When number is perfect number
			return true;
		}
		else
		{
			return false;
		}
	}
	fun findPerfectNo(arr: Array < Int > , n: Int): Unit
	{
		var result: Boolean = false;
		var i: Int = 0;
		while (i < n)
		{
			if (arr[i] > 0 && this.isPerfectNo(this.digitSum(arr[i])))
			{
				// When array element is perfect number
				print("  " + arr[i]);
				// Active result indicator
				result = true;
			}
			i += 1;
		}
		if (result == false)
		{
			print("\n None \n");
		}
	}
}
fun main(args: Array < String > ): Unit
{
	val task: PerfectNumber = PerfectNumber();
	val arr: Array < Int > = arrayOf(5, 231, 4, 60, -34, 4888);
	val n: Int = arr.count();
	/*
	    arr = [5, 231, 4, 60, -34, 4888]
	    --------------------------------
	    2 + 3 + 1     = 6
	    6 + 0         = 6
	    4 + 8 + 8 + 8 = 28

	    Result : [231,60,4888]
	        
	*/
	task.findPerfectNo(arr, n);
}

Output

  231  60  4888
Last updated on by Kalkicode




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