# Egyptian fraction solution in ruby

Ruby program for Egyptian fraction solution. Here problem description and other solutions.

```
# Ruby program for
# Egyptian fraction solution
class Fraction
def egyptianFraction(a, b)
if (a == 0 || b == 0)
return
end
if (b >= a)
# Calculate remainder
remainder = b % a
# Calculate divisor
divisor = b / a
if (remainder != 0)
divisor += 1
print("1/", divisor ," + ")
a = a * divisor - b
b = b * divisor
self.egyptianFraction(a, b)
else
# When remainder is zero
print("1/", divisor)
end
else
# When b < a
print((a / b) ," + ")
self.egyptianFraction(a % b, b)
end
end
end
def main()
task = Fraction.new()
# Two numbers
a = 7
b = 53
task.egyptianFraction(a, b)
end
main()
```

**Output**

`1/8 + 1/142 + 1/30104`

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