# Egyptian fraction solution in python

Python program for Egyptian fraction solution. Here problem description and other solutions.

```
# Python 3 program for
# Egyptian fraction solution
class Fraction :
def egyptianFraction(self, a, b) :
if (a == 0 or b == 0) :
return
if (b >= a) :
# Calculate remainder
remainder = b % a
# Calculate divisor
divisor = int(b / a)
if (remainder != 0) :
divisor += 1
print("1/", divisor , end = " + ", sep = "")
a = a * divisor - b
b = b * divisor
self.egyptianFraction(a, b)
else :
# When remainder is zero
print("1/", divisor, end = "", sep = "")
else :
# When b < a
print((int(a / b)), end = " + ", sep = "")
self.egyptianFraction(a % b, b)
def main() :
task = Fraction()
# Two numbers
a = 7
b = 53
task.egyptianFraction(a, b)
if __name__ == "__main__": main()
```

**Output**

`1/8 + 1/142 + 1/30104`

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