Egyptian fraction solution in python

Python program for Egyptian fraction solution. Here problem description and other solutions.

#  Python 3 program for
#  Egyptian fraction solution
class Fraction :
	def egyptianFraction(self, a, b) :
		if (a == 0 or b == 0) :
			return
		
		if (b >= a) :
			#  Calculate remainder
			remainder = b % a
			#  Calculate divisor
			divisor = int(b / a)
			if (remainder != 0) :
				divisor += 1
				print("1/", divisor , end = " + ", sep = "")
				a = a * divisor - b
				b = b * divisor
				self.egyptianFraction(a, b)
			else :
				#  When remainder is zero
				print("1/", divisor, end = "", sep = "")
			
		else :
			#  When b < a
			print((int(a / b)), end = " + ", sep = "")
			self.egyptianFraction(a % b, b)
		
	

def main() :
	task = Fraction()
	#  Two numbers
	a = 7
	b = 53
	task.egyptianFraction(a, b)

if __name__ == "__main__": main()

Output

1/8 + 1/142 + 1/30104


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