Egyptian fraction solution in c

C program for Egyptian fraction solution. Here more information.

// Include header file
#include <stdio.h>
/*
  C program for
  Egyptian fraction solution
*/
void egyptianFraction(int a, int b) {
	if ((a == 0 || b == 0)) {
		return;
	}
	if ((b >= a)) {
		// Calculate remainder
		int remainder = b % a;
		// Calculate divisor
		int divisor = b / a;
		if ((remainder != 0)) {
			divisor++;
			printf("1/%d + ",divisor);
			a = a * divisor - b;
			b = b * divisor;
			egyptianFraction(a, b);
		} else {
			// When remainder is zero
			printf("1/%d", divisor);
		}
	} else {
		// When b < a
		printf("%d + ",(a / b));
		egyptianFraction(a % b, b);
	}
}
int main() {
	// Two numbers
	int a = 7;
	int b = 53;
	egyptianFraction(a, b);
}

Output

1/8 + 1/142 + 1/30104


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