Efficiently find the power of number

Here given code implementation process.

// C program for
// Efficiently find the power of number
#include <stdio.h>

// Find the power of given base and exponent
float power(float base, int exponent)
{
	if (exponent == 0)
	{
		// When exponent zero
		return 1;
	}
	// finding the power using recursion
	float auxiliary = power(base, exponent / 2);
	if (exponent % 2 == 0)
	{
		return auxiliary *auxiliary;
	}
	else if (exponent > 0)
	{
		// When exponent greater than zero
		return base *auxiliary *auxiliary;
	}
	else
	{
		// When exponent less than zero
		return (auxiliary *auxiliary) / base;
	}
}
// Handle request to display calculate power result
void calculatePow(float base, int exponent)
{
	// Display given data
	printf("\n Given Base : %f", base);
	printf("\n Given exponent : %d", exponent);
	// Display calculated result
	printf("\n Result : %f\n", power(base, exponent));
}
int main()
{
	// Test Case
	calculatePow(3.5, 4);
	calculatePow(5, -3);
	calculatePow(5, 3);
	return 0;
}

Output

 Given Base : 3.500000
 Given exponent : 4
 Result : 150.062500

 Given Base : 5.000000
 Given exponent : -3
 Result : 0.008000

 Given Base : 5.000000
 Given exponent : 3
 Result : 125.000000
// Java Program 
// Efficiently find the power of number
public class PowerNumber
{
	// Find the power of given base and exponent
	public float power(float base, int exponent)
	{
		if (exponent == 0)
		{
			// When exponent zero
			return 1;
		}
		// finding the power using recursion
		float auxiliary = power(base, exponent / 2);
		if (exponent % 2 == 0)
		{
			return auxiliary * auxiliary;
		}
		else if (exponent > 0)
		{
			// When exponent greater than zero
			return base * auxiliary * auxiliary;
		}
		else
		{
			// When exponent less than zero
			return (auxiliary * auxiliary) / base;
		}
	}
	// Handle request to display calculate power result
	public void calculatePow(float base, int exponent)
	{
		// Display given data
		System.out.print("\n Given Base : " + base);
		System.out.print("\n Given exponent : " + exponent);
		// Display calculated result
		System.out.print("\n Result : " + power(base, exponent) + "\n");
	}
	public static void main(String[] args)
	{
		PowerNumber task = new PowerNumber();
		// Test Case
		task.calculatePow(3.5f, 4);
		task.calculatePow(5, -3);
		task.calculatePow(5, 3);
	}
}

Output

 Given Base : 3.5
 Given exponent : 4
 Result : 150.0625

 Given Base : 5.0
 Given exponent : -3
 Result : 0.008

 Given Base : 5.0
 Given exponent : 3
 Result : 125.0
// Include header file
#include <iostream>
using namespace std;

// C++ Program
// Efficiently find the power of number

class PowerNumber
{
	public:
		// Find the power of given base and exponent
		float power(float base, int exponent)
		{
			if (exponent == 0)
			{
				// When exponent zero
				return 1;
			}
			// finding the power using recursion
			float auxiliary = this->power(base, exponent / 2);
			if (exponent % 2 == 0)
			{
				return auxiliary *auxiliary;
			}
			else if (exponent > 0)
			{
				// When exponent greater than zero
				return base *auxiliary *auxiliary;
			}
			else
			{
				// When exponent less than zero
				return (auxiliary *auxiliary) / base;
			}
		}
	// Handle request to display calculate power result
	void calculatePow(float base, int exponent)
	{
		// Display given data
		cout << "\n Given Base : " << base;
		cout << "\n Given exponent : " << exponent;
		// Display calculated result
		cout << "\n Result : " << this->power(base, exponent) << "\n";
	}
};
int main()
{
	PowerNumber task = PowerNumber();
	// Test Case
	task.calculatePow(3.5f, 4);
	task.calculatePow(5, -3);
	task.calculatePow(5, 3);
	return 0;
}

Output

 Given Base : 3.5
 Given exponent : 4
 Result : 150.062

 Given Base : 5
 Given exponent : -3
 Result : 0.008

 Given Base : 5
 Given exponent : 3
 Result : 125
// Include namespace system
using System;

// C# Program
// Efficiently find the power of number

public class PowerNumber
{
	// Find the power of given base and exponent
	public float power(float b, int exponent)
	{
		if (exponent == 0)
		{
			// When exponent zero
			return 1;
		}
		// finding the power using recursion
		float auxiliary = power(b, exponent / 2);
		if (exponent % 2 == 0)
		{
			return auxiliary * auxiliary;
		}
		else if (exponent > 0)
		{
			// When exponent greater than zero
			return b * auxiliary * auxiliary;
		}
		else
		{
			// When exponent less than zero
			return (auxiliary * auxiliary) / b;
		}
	}
	// Handle request to display calculate power result
	public void calculatePow(float b, int exponent)
	{
		// Display given data
		Console.Write("\n Given Base : " + b);
		Console.Write("\n Given exponent : " + exponent);
		// Display calculated result
		Console.Write("\n Result : " + power(b, exponent) + "\n");
	}
	public static void Main(String[] args)
	{
		PowerNumber task = new PowerNumber();
		// Test Case
		task.calculatePow(3.5f, 4);
		task.calculatePow(5, -3);
		task.calculatePow(5, 3);
	}
}

Output

 Given Base : 3.5
 Given exponent : 4
 Result : 150.0625

 Given Base : 5
 Given exponent : -3
 Result : 0.008

 Given Base : 5
 Given exponent : 3
 Result : 125
<?php
// Php Program
// Efficiently find the power of number
class PowerNumber
{
	// Find the power of given base and exponent
	public	function power($base, $exponent)
	{
		if ($exponent == 0)
		{
			// When exponent zero
			return 1;
		}
		// finding the power using recursion
		$auxiliary = $this->power($base, ($exponent / 2));
		if ($exponent % 2 == 0)
		{
			return $auxiliary * $auxiliary;
		}
		else if ($exponent > 0)
		{
			// When exponent greater than zero
			return $base * $auxiliary * $auxiliary;
		}
		else
		{
			// When exponent less than zero
			return (($auxiliary * $auxiliary) / $base);
		}
	}
	// Handle request to display calculate power result
	public	function calculatePow($base, $exponent)
	{
		// Display given data
		echo "\n Given Base : ". $base;
		echo "\n Given exponent : ". $exponent;
		// Display calculated result
		echo "\n Result : ". $this->power($base, $exponent) ."\n";
	}
}

function main()
{
	$task = new PowerNumber();
	$task->calculatePow(3.5, 4);
	$task->calculatePow(5, -3);
	$task->calculatePow(5, 3);
}
main();

Output

 Given Base : 3.5
 Given exponent : 4
 Result : 150.0625

 Given Base : 5
 Given exponent : -3
 Result : 0.008

 Given Base : 5
 Given exponent : 3
 Result : 125
#  Python 3 Program 
#  Efficiently find the power of number
class PowerNumber :
	#  Find the power of given base and exponent
	def power(self, base, exponent) :
		if (exponent == 0) :
			#  When exponent zero
			return 1
		
		#  finding the power using recursion
		auxiliary = self.power(base, int(exponent / 2))
		if (exponent % 2 == 0) :
			return auxiliary * auxiliary
		
		elif(exponent > 0) :
			#  When exponent greater than zero
			return base * auxiliary * auxiliary
		else :
			#  When exponent less than zero
			return ((auxiliary * auxiliary) / base)
		
	
	#  Handle request to display calculate power result
	def calculatePow(self, base, exponent) :
		#  Display given data
		print("\n Given Base : ", base, end = "")
		print("\n Given exponent : ", exponent, end = "")
		#  Display calculated result
		print("\n Result : ", self.power(base,exponent) )
	

def main() :
	task = PowerNumber()
	#  Test Case
	task.calculatePow(3.5, 4)
	task.calculatePow(5, -3)
	task.calculatePow(5, 3)

if __name__ == "__main__": main()

Output

 Given Base :  3.5
 Given exponent :  4
 Result :  150.0625

 Given Base :  5
 Given exponent :  -3
 Result :  0.008000000000000002

 Given Base :  5
 Given exponent :  3
 Result :  125
// Node Js Program
// Efficiently find the power of number
class PowerNumber
{
	// Find the power of given base and exponent
	power(base, exponent)
	{
		if (exponent == 0)
		{
			// When exponent zero
			return 1;
		}
		// finding the power using recursion
		var auxiliary = this.power(base, parseInt(exponent / 2));
		if (exponent % 2 == 0)
		{
			return auxiliary * auxiliary;
		}
		else if (exponent > 0)
		{
			// When exponent greater than zero
			return base * auxiliary * auxiliary;
		}
		else
		{
			// When exponent less than zero
			return ((auxiliary * auxiliary) / base);
		}
	}
	// Handle request to display calculate power result
	calculatePow(base, exponent)
	{
		// Display given data
		process.stdout.write("\n Given Base : " + base);
		process.stdout.write("\n Given exponent : " + exponent);
		// Display calculated result
		process.stdout.write("\n Result : " + this.power(base, exponent) + "\n");
	}
}

function main()
{
	var task = new PowerNumber();
	// Test Case
	task.calculatePow(3.5, 4);
	task.calculatePow(5, -3);
	task.calculatePow(5, 3);
}
main();

Output

 Given Base : 3.5
 Given exponent : 4
 Result : 150.0625

 Given Base : 5
 Given exponent : -3
 Result : 0.008000000000000002

 Given Base : 5
 Given exponent : 3
 Result : 125
#  Ruby Program 
#  Efficiently find the power of number
class PowerNumber 
	#  Find the power of given base and exponent
	def power(base, exponent) 
		if (exponent == 0) 
			#  When exponent zero
			return 1
		end

		#  finding the power using recursion
		auxiliary = self.power(base, (exponent / 2).ceil)
		if (exponent % 2 == 0) 
			return auxiliary * auxiliary
		elsif(exponent > 0) 
			#  When exponent greater than zero
			return base * auxiliary * auxiliary
		else 
			#  When exponent less than zero
			return (auxiliary * auxiliary) / base
		end

	end

	#  Handle request to display calculate power result
	def calculatePow(base, exponent) 
		
	
		#  Display given data
		print("\n Given Base : ", base)
		print("\n Given exponent : ", exponent)
		#  Display calculated result
		print("\n Result : ", self.power(base, exponent) ,"\n")
	end

end

def main() 
	task = PowerNumber.new()
	#  Test Case
	task.calculatePow(3.5, 4)
	task.calculatePow(5, 3)

end

main()

Output

 Given Base : 3.5
 Given exponent : 4
 Result : 150.0625

 Given Base : 5
 Given exponent : 3
 Result : 125
// Swift 4 Program
// Efficiently find the power of number
class PowerNumber
{
	// Find the power of given base and exponent
	func power(_ base: Double, _ exponent: Int)->Double
	{
		if (exponent == 0)
		{
			// When exponent zero
			return 1;
		}
		// finding the power using recursion
		let auxiliary: Double = self.power(base, exponent / 2);
		if (exponent % 2 == 0)
		{
			return auxiliary * auxiliary;
		}
		else if (exponent > 0)
		{
			// When exponent greater than zero
			return base * auxiliary * auxiliary;
		}
		else
		{
			// When exponent less than zero
			return (auxiliary * auxiliary) / base;
		}
	}
	// Handle request to display calculate power result
	func calculatePow(_ base: Double, _ exponent: Int)
	{
		// Display given data
		print("\n Given Base : ", base, terminator: "");
		print("\n Given exponent : ", exponent, terminator: "");
		// Display calculated result
		print("\n Result : ", self.power(base,exponent) );
	}
}
func main()
{
	let task: PowerNumber = PowerNumber();
	// Test Case
	task.calculatePow(3.5, 4);
	task.calculatePow(5, -3);
	task.calculatePow(5, 3);
}
main();

Output

 Given Base :  3.5
 Given exponent :  4
 Result :  150.0625

 Given Base :  5.0
 Given exponent :  -3
 Result :  0.008

 Given Base :  5.0
 Given exponent :  3
 Result :  125.0
// Scala Program
// Efficiently find the power of number
class PowerNumber
{
	// Find the power of given base and exponent
	def power(base: Float, exponent: Int): Float = {
		if (exponent == 0)
		{
			// When exponent zero
			return 1;
		}
		// finding the power using recursion
		var auxiliary: Float = this.power(base, (exponent / 2));
		if (exponent % 2 == 0)
		{
			return auxiliary * auxiliary;
		}
		else if (exponent > 0)
		{
			// When exponent greater than zero
			return base * auxiliary * auxiliary;
		}
		else
		{
			// When exponent less than zero
			return ((auxiliary * auxiliary) / base);
		}
	}
	// Handle request to display calculate power result
	def calculatePow(base: Float, exponent: Int): Unit = {
		// Display given data
		print("\n Given Base : " + base);
		print("\n Given exponent : " + exponent);
		// Display calculated result
		print("\n Result : " + this.power(base, exponent) + "\n");
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: PowerNumber = new PowerNumber();
		// Test Case
		task.calculatePow(3.5f, 4);
		task.calculatePow(5, -3);
		task.calculatePow(5, 3);
	}
}

Output

 Given Base : 3.5
 Given exponent : 4
 Result : 150.0625

 Given Base : 5.0
 Given exponent : -3
 Result : 0.008

 Given Base : 5.0
 Given exponent : 3
 Result : 125.0
// Kotlin Program
// Efficiently find the power of number
class PowerNumber
{
	// Find the power of given base and exponent
	fun power(base: Float, exponent: Int): Float
	{
		if (exponent == 0)
		{
			// When exponent zero
			return 1.0f;
		}
		// finding the power using recursion
		var auxiliary: Float = this.power(base, exponent / 2);
		if (exponent % 2 == 0)
		{
			return auxiliary * auxiliary;
		}
		else if (exponent > 0)
		{
			
			// When exponent greater than zero
			return base * auxiliary * auxiliary;
		}
		else
		{
			
			// When exponent less than zero
			return (auxiliary * auxiliary) / base;
		}
	}
	// Handle request to display calculate power result
	fun calculatePow(base: Float, exponent: Int): Unit
	{
		// Display given data
		print("\n Given Base : " + base);
		print("\n Given exponent : " + exponent);
		// Display calculated result
		print("\n Result : " + this.power(base, exponent) + "\n");
	}
}
fun main(args: Array < String > ): Unit
{
	var task: PowerNumber = PowerNumber();
	// Test Case
	task.calculatePow(3.5f, 4);
	task.calculatePow(5f, -3);
	task.calculatePow(5f, 3);
}

Output

 Given Base : 3.5
 Given exponent : 4
 Result : 150.0625

 Given Base : 5.0
 Given exponent : -3
 Result : 0.008

 Given Base : 5.0
 Given exponent : 3
 Result : 125.0

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