Duck Number
A Duck Number is a number that contains at least one zero in it, but it's not leading zero. For example, 102 is a duck number, but 023 is not because it has a leading zero. The name "duck number" comes from the fact that the appearance of the number resembles a duck, as the zero resembles the duck's beak. Duck numbers are used in various mathematical puzzles and games.
Here given code implementation process.
/*
C Program
+ Check if a given number is Duck Number or not
*/
#include<stdio.h>
//Check that given number is duck number or not
void is_duck_number(char str_num[],int size)
{
int status = 0;
//When Numbers start with zero not a duck number
if(str_num[0]!='0')
{
//When not start to 0
for (int i = 1; i < size && status == 0; ++i)
{
if(str_num[i]=='0')
{ //When get the intermediate zero
status=1;
}
}
}
if(status==0)
{
printf("%s Is not an Duck Number \n",str_num );
}
else
{
printf("%s Is an Duck Number \n",str_num );
}
}
int main(){
int size = 0;
//Test Cases
char str_num1[]="16460";
char str_num2[]="026460";
char str_num3[]="264665";
//Get the size
size= sizeof(str_num1)/sizeof(str_num1[0])-1;
is_duck_number(str_num1,size);
size= sizeof(str_num2)/sizeof(str_num2[0])-1;
is_duck_number(str_num2,size);
size= sizeof(str_num3)/sizeof(str_num3[0])-1;
is_duck_number(str_num3,size);
return 0;
}
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
/*
C++ Program
Check if a given number is Duck Number or not
*/
#include<iostream>
#include <string.h>
using namespace std;
class MyNumber {
public:
//Check that given number is duck number or not
void is_duck_number(string str_num) {
//get length
int size = str_num.length();
bool status = false;
//When Numbers start with zero not a duck number
if (str_num[0] != '0') {
//When not start to 0
for (int i = 1; i < size && status == false; ++i) {
if (str_num[i] == '0') {
//When get the intermediate zero
status = true;
}
}
}
if (status == false) {
cout << str_num << " Is not an Duck Number \n";
} else {
cout << str_num << " Is an Duck Number \n";
}
}
};
int main() {
MyNumber obj;
//Assume Given input string
string str_num1 = "16460";
string str_num2 = "026460";
string str_num3 = "264665";
//Test Cases
obj.is_duck_number(str_num1);
obj.is_duck_number(str_num2);
obj.is_duck_number(str_num3);
return 0;
}
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
/*
Java Program
Check if a given number is Duck Number or not
*/
public class MyNumber {
//Check that given number is duck number or not
public void is_duck_number(String str_num)
{
//get length
int size = str_num.length();
Boolean status = false;
//When Numbers start with zero not a duck number
if(str_num.charAt(0)!='0')
{
//When not start to 0
for (int i = 1; i < size && status == false; ++i)
{
if(str_num.charAt(i)=='0')
{ //When get the intermediate zero
status=true;
}
}
}
if(status==false)
{
System.out.print(str_num+" Is not an Duck Number \n" );
}
else
{
System.out.print(str_num+" Is an Duck Number \n" );
}
}
public static void main(String[] args) {
MyNumber obj = new MyNumber();
//Assume Given input string
String str_num1="16460";
String str_num2="026460";
String str_num3="264665";
//Test Cases
obj.is_duck_number(str_num1);
obj.is_duck_number(str_num2);
obj.is_duck_number(str_num3);
}
}
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
/*
C# Program
Check if a given number is Duck Number or not
*/
using System;
public class MyNumber {
//Check that given number is duck number or not
public void is_duck_number(String str_num) {
//get.Length
int size = str_num.Length;
Boolean status = false;
//When Numbers start with zero not a duck number
if (str_num[0] != '0') {
//When not start to 0
for (int i = 1; i < size && status == false; ++i) {
if (str_num[i] == '0') {
//When get the intermediate zero
status = true;
}
}
}
if (status == false) {
Console.Write(str_num + " Is not an Duck Number \n");
} else {
Console.Write(str_num + " Is an Duck Number \n");
}
}
public static void Main(String[] args) {
MyNumber obj = new MyNumber();
//Assume Given input string
String str_num1 = "16460";
String str_num2 = "026460";
String str_num3 = "264665";
//Test Cases
obj.is_duck_number(str_num1);
obj.is_duck_number(str_num2);
obj.is_duck_number(str_num3);
}
}
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
<?php
/*
Php Program
Check if a given number is Duck Number or not
*/
class MyNumber {
//Check that given number is duck number or not
public function is_duck_number($str_num) {
//get length
$size = strlen($str_num);
$status = false;
//When Numbers start with zero not a duck number
if ($str_num[0] != '0') {
//When not start to 0
for ($i = 1; $i < $size && $status == false; ++$i) {
if ($str_num[$i] == '0') {
//When get the intermediate zero
$status = true;
}
}
}
if ($status == false) {
echo($str_num ." Is not an Duck Number \n");
} else {
echo($str_num ." Is an Duck Number \n");
}
}
};
function main() {
$obj = new MyNumber();
//Assume Given input string
$str_num1 = "16460";
$str_num2 = "026460";
$str_num3 = "264665";
//Test Cases
$obj->is_duck_number($str_num1);
$obj->is_duck_number($str_num2);
$obj->is_duck_number($str_num3);
}
main();
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
/*
Node Js Program
Check if a given number is Duck Number or not
*/
class MyNumber {
//Check that given number is duck number or not
is_duck_number(str_num) {
//get length
var size = str_num.length;
var status = false;
//When Numbers start with zero not a duck number
if (str_num[0] != '0') {
//When not start to 0
for (var i = 1; i < size && status == false; ++i) {
if (str_num[i] == '0') {
//When get the intermediate zero
status = true;
}
}
}
if (status == false) {
process.stdout.write(str_num + " Is not an Duck Number \n");
} else {
process.stdout.write(str_num + " Is an Duck Number \n");
}
}
}
function main(args) {
var obj = new MyNumber();
//Assume Given input string
var str_num1 = "16460";
var str_num2 = "026460";
var str_num3 = "264665";
//Test Cases
obj.is_duck_number(str_num1);
obj.is_duck_number(str_num2);
obj.is_duck_number(str_num3);
}
main();
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
# Python 3 Program
# Check if a given number is Duck Number or not
class MyNumber :
# Check that given number is duck number or not
def is_duck_number(self, str_num) :
# get length
size = len(str_num)
status = False
# When Numbers start with zero not a duck number
if (str_num[0] != '0') :
# When not start to 0
i = 1
while (i < size and status == False) :
if (str_num[i] == '0') :
# When get the intermediate zero
status = True
i += 1
if (status == False) :
print(str_num ," Is not an Duck Number \n")
else :
print(str_num ," Is an Duck Number \n")
def main() :
obj = MyNumber()
# Assume Given input string
str_num1 = "16460"
str_num2 = "026460"
str_num3 = "264665"
# Test Cases
obj.is_duck_number(str_num1)
obj.is_duck_number(str_num2)
obj.is_duck_number(str_num3)
if __name__ == "__main__":
main()
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
# Ruby Program
# Check if a given number is Duck Number or not
class MyNumber
# Check that given number is duck number or not
def is_duck_number(str_num)
# get length
size = str_num.length
status = false
# When Numbers start with zero not a duck number
if (str_num[0] != '0')
# When not start to 0
i = 1
while (i < size and status == false)
if (str_num[i] == '0')
# When get the intermediate zero
status = true
end
i += 1
end
end
if (status == false)
print(str_num ," Is not an Duck Number \n")
else
print(str_num ," Is an Duck Number \n")
end
end
end
def main()
obj = MyNumber.new()
# Assume Given input string
str_num1 = "16460"
str_num2 = "026460"
str_num3 = "264665"
# Test Cases
obj.is_duck_number(str_num1)
obj.is_duck_number(str_num2)
obj.is_duck_number(str_num3)
end
main()
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
/*
Scala Program
Check if a given number is Duck Number or not
*/
class MyNumber {
//Check that given number is duck number or not
def is_duck_number(str_num: String): Unit = {
//get length
var size: Int = str_num.length();
var status: Boolean = false;
//When Numbers start with zero not a duck number
if (str_num(0) != '0') {
//When not start to 0
var i: Int = 1;
while (i < size && status == false) {
if (str_num(i) == '0') {
//When get the intermediate zero
status = true;
}
i += 1;
}
}
if (status == false) {
print(str_num + " Is not an Duck Number \n");
} else {
print(str_num + " Is an Duck Number \n");
}
}
}
object Main {
def main(args: Array[String]): Unit = {
var obj: MyNumber = new MyNumber();
//Assume Given input string
var str_num1: String = "16460";
var str_num2: String = "026460";
var str_num3: String = "264665";
//Test Cases
obj.is_duck_number(str_num1);obj.is_duck_number(str_num2);obj.is_duck_number(str_num3);
}
}
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
/*
Swift 4 Program
Check if a given number is Duck Number or not
*/
class MyNumber {
//Check that given number is duck number or not
func is_duck_number(_ str_num: String) {
var status: Bool = false;
//When Numbers start with zero not a duck number
var index = str_num.startIndex
if (str_num[index] != "0") {
//When not start to 0
index = str_num.index(after: index)
while index != str_num.endIndex && status == false{
// Check index value
if(str_num[index]=="0")
{
status = true
}
index = str_num.index(after: index)
}
}
if (status == false) {
print(str_num ," Is not an Duck Number ");
} else {
print(str_num ," Is an Duck Number ");
}
}
}
func main() {
let obj: MyNumber = MyNumber();
//Assume Given input string
let str_num1: String = "16460";
let str_num2: String = "026460";
let str_num3: String = "264665";
//Test Cases
obj.is_duck_number(str_num1);
obj.is_duck_number(str_num2);
obj.is_duck_number(str_num3);
}
main();
Output
16460 Is an Duck Number
026460 Is not an Duck Number
264665 Is not an Duck Number
Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.
New Comment