Divide a string into n equal parts
Here given code implementation process.
/*
C program for
Divide a string into n equal parts
*/
#include <stdio.h>
#include <string.h>
void nEqualPartition(char *text, int n)
{
// Get the length of given text
int length = strlen(text);
// Display Given text
printf("\n Given text : %s ", text);
// Display partition size
printf("\n Partition size : %d \n ", n);
if (length == 0 || n <= 0 || (length % n) != 0)
{
// When of partition not possible
printf("\n Equal partition not possible of size %d", n);
}
else
{
// Get length of each part
int part = length / n;
// Display result
for (int i = 0; i < length; ++i)
{
printf("%c", text[i]);
if ((i + 1) % part == 0)
{
// Separate the result by new line
printf("\n ");
}
}
}
}
int main(int argc, char
const *argv[])
{
char *text = "abcdefghijklmnopqrst";
// partition n = 4
nEqualPartition(text, 4);
// partition n = 5
nEqualPartition(text, 5);
// partition n = 3
nEqualPartition(text, 3);
return 0;
}
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
// Java program for
// Divide a string into n equal parts
public class Partition
{
public void nEqualPartition(String text, int n)
{
// Get the length of given text
int length = text.length();
// Display Given text
System.out.print("\n Given text : " + text);
// Display partition size
System.out.print("\n Partition size : " + n + " \n ");
if (length == 0 || n <= 0 || (length % n) != 0)
{
// When of partition not possible
System.out.print("\n Equal partition not possible of size " + n);
}
else
{
// Get length of each part
int part = length / n;
// Display result
for (int i = 0; i < length; ++i)
{
System.out.print(text.charAt(i));
if ((i + 1) % part == 0)
{
// Separate the result by new line
System.out.print("\n ");
}
}
}
}
public static void main(String[] args)
{
Partition task = new Partition();
String text = "abcdefghijklmnopqrst";
// partition n = 4
task.nEqualPartition(text, 4);
// partition n = 5
task.nEqualPartition(text, 5);
// partition n = 3
task.nEqualPartition(text, 3);
}
}
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
// Include header file
#include <iostream>
#include <string>
using namespace std;
// C++ program for
// Divide a string into n equal parts
class Partition
{
public: void nEqualPartition(string text, int n)
{
// Get the length of given text
int length = text.length();
// Display Given text
cout << "\n Given text : " << text;
// Display partition size
cout << "\n Partition size : " << n << " \n ";
if (length == 0 || n <= 0 || (length % n) != 0)
{
// When of partition not possible
cout << "\n Equal partition not possible of size " << n;
}
else
{
// Get length of each part
int part = length / n;
// Display result
for (int i = 0; i < length; ++i)
{
cout << text[i];
if ((i + 1) % part == 0)
{
// Separate the result by new line
cout << "\n ";
}
}
}
}
};
int main()
{
Partition *task = new Partition();
string text = "abcdefghijklmnopqrst";
// partition n = 4
task->nEqualPartition(text, 4);
// partition n = 5
task->nEqualPartition(text, 5);
// partition n = 3
task->nEqualPartition(text, 3);
return 0;
}
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
// Include namespace system
using System;
// Csharp program for
// Divide a string into n equal parts
public class Partition
{
public void nEqualPartition(String text, int n)
{
// Get the length of given text
int length = text.Length;
// Display Given text
Console.Write("\n Given text : " + text);
// Display partition size
Console.Write("\n Partition size : " + n + " \n ");
if (length == 0 || n <= 0 || (length % n) != 0)
{
// When of partition not possible
Console.Write("\n Equal partition not possible of size " + n);
}
else
{
// Get length of each part
int part = length / n;
// Display result
for (int i = 0; i < length; ++i)
{
Console.Write(text[i]);
if ((i + 1) % part == 0)
{
// Separate the result by new line
Console.Write("\n ");
}
}
}
}
public static void Main(String[] args)
{
Partition task = new Partition();
String text = "abcdefghijklmnopqrst";
// partition n = 4
task.nEqualPartition(text, 4);
// partition n = 5
task.nEqualPartition(text, 5);
// partition n = 3
task.nEqualPartition(text, 3);
}
}
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
package main
import "fmt"
// Go program for
// Divide a string into n equal parts
func nEqualPartition(text string, n int) {
// Get the length of given text
var length int = len(text)
// Display Given text
fmt.Print("\n Given text : ", text)
// Display partition size
fmt.Print("\n Partition size : ", n, " \n ")
if length == 0 || n <= 0 || (length % n) != 0 {
// When of partition not possible
fmt.Print("\n Equal partition not possible of size ", n)
} else {
// Get length of each part
var part int = length / n
// Display result
for i := 0 ; i < length ; i++ {
fmt.Print(string(text[i]))
if (i + 1) % part == 0 {
// Separate the result by new line
fmt.Print("\n ")
}
}
}
}
func main() {
var text string = "abcdefghijklmnopqrst"
// partition n = 4
nEqualPartition(text, 4)
// partition n = 5
nEqualPartition(text, 5)
// partition n = 3
nEqualPartition(text, 3)
}
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
<?php
// Php program for
// Divide a string into n equal parts
class Partition
{
public function nEqualPartition($text, $n)
{
// Get the length of given text
$length = strlen($text);
// Display Given text
echo("\n Given text : ".$text);
// Display partition size
echo("\n Partition size : ".$n.
" \n ");
if ($length == 0 || $n <= 0 || ($length % $n) != 0)
{
// When of partition not possible
echo("\n Equal partition not possible of size ".$n);
}
else
{
// Get length of each part
$part = (int)($length / $n);
// Display result
for ($i = 0; $i < $length; ++$i)
{
echo($text[$i]);
if (($i + 1) % $part == 0)
{
// Separate the result by new line
echo("\n ");
}
}
}
}
}
function main()
{
$task = new Partition();
$text = "abcdefghijklmnopqrst";
// partition n = 4
$task->nEqualPartition($text, 4);
// partition n = 5
$task->nEqualPartition($text, 5);
// partition n = 3
$task->nEqualPartition($text, 3);
}
main();
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
// Node JS program for
// Divide a string into n equal parts
class Partition
{
nEqualPartition(text, n)
{
// Get the length of given text
var length = text.length;
// Display Given text
process.stdout.write("\n Given text : " + text);
// Display partition size
process.stdout.write("\n Partition size : " + n + " \n ");
if (length == 0 || n <= 0 || (length % n) != 0)
{
// When of partition not possible
process.stdout.write("\n Equal partition not possible of size " + n);
}
else
{
// Get length of each part
var part = parseInt(length / n);
// Display result
for (var i = 0; i < length; ++i)
{
process.stdout.write(text.charAt(i));
if ((i + 1) % part == 0)
{
// Separate the result by new line
process.stdout.write("\n ");
}
}
}
}
}
function main()
{
var task = new Partition();
var text = "abcdefghijklmnopqrst";
// partition n = 4
task.nEqualPartition(text, 4);
// partition n = 5
task.nEqualPartition(text, 5);
// partition n = 3
task.nEqualPartition(text, 3);
}
main();
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
# Python 3 program for
# Divide a string into n equal parts
class Partition :
def nEqualPartition(self, text, n) :
# Get the length of given text
length = len(text)
# Display Given text
print("\n Given text : ", text, end = "")
# Display partition size
print("\n Partition size : ", n ," \n ", end = "")
if (length == 0 or n <= 0 or(length % n) != 0) :
# When of partition not possible
print("\n Equal partition not possible of size ", n, end = "")
else :
# Get length of each part
part = int(length / n)
i = 0
# Display result
while (i < length) :
print(text[i], end = "")
if ((i + 1) % part == 0) :
# Separate the result by new line
print("\n ", end = "")
i += 1
def main() :
task = Partition()
text = "abcdefghijklmnopqrst"
# partition n = 4
task.nEqualPartition(text, 4)
# partition n = 5
task.nEqualPartition(text, 5)
# partition n = 3
task.nEqualPartition(text, 3)
if __name__ == "__main__": main()
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
# Ruby program for
# Divide a string into n equal parts
class Partition
def nEqualPartition(text, n)
# Get the length of given text
length = text.length
# Display Given text
print("\n Given text : ", text)
# Display partition size
print("\n Partition size : ", n ," \n ")
if (length == 0 || n <= 0 || (length % n) != 0)
# When of partition not possible
print("\n Equal partition not possible of size ", n)
else
# Get length of each part
part = length / n
i = 0
# Display result
while (i < length)
print(text[i])
if ((i + 1) % part == 0)
# Separate the result by new line
print("\n ")
end
i += 1
end
end
end
end
def main()
task = Partition.new()
text = "abcdefghijklmnopqrst"
# partition n = 4
task.nEqualPartition(text, 4)
# partition n = 5
task.nEqualPartition(text, 5)
# partition n = 3
task.nEqualPartition(text, 3)
end
main()
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
// Scala program for
// Divide a string into n equal parts
class Partition()
{
def nEqualPartition(text: String, n: Int): Unit = {
// Get the length of given text
var length: Int = text.length();
// Display Given text
print("\n Given text : " + text);
// Display partition size
print("\n Partition size : " + n + " \n ");
if (length == 0 || n <= 0 || (length % n) != 0)
{
// When of partition not possible
print("\n Equal partition not possible of size " + n);
}
else
{
// Get length of each part
var part: Int = length / n;
var i: Int = 0;
// Display result
while (i < length)
{
print(text.charAt(i));
if ((i + 1) % part == 0)
{
// Separate the result by new line
print("\n ");
}
i += 1;
}
}
}
}
object Main
{
def main(args: Array[String]): Unit = {
var task: Partition = new Partition();
var text: String = "abcdefghijklmnopqrst";
// partition n = 4
task.nEqualPartition(text, 4);
// partition n = 5
task.nEqualPartition(text, 5);
// partition n = 3
task.nEqualPartition(text, 3);
}
}
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
// Swift 4 program for
// Divide a string into n equal parts
class Partition
{
func nEqualPartition(_ s: String, _ n: Int)
{
let text = Array(s);
// Get the length of given text
let length: Int = text.count;
// Display Given text
print("\n Given text : ", s, terminator: "");
// Display partition size
print("\n Partition size : ", n ," \n ", terminator: "");
if (length == 0 || n <= 0 || (length % n) != 0)
{
// When of partition not possible
print("\n Equal partition not possible of size ", n, terminator: "");
}
else
{
// Get length of each part
let part: Int = length / n;
var i: Int = 0;
// Display result
while (i < length)
{
print(text[i], terminator: "");
if ((i + 1) % part == 0)
{
// Separate the result by new line
print("\n ", terminator: "");
}
i += 1;
}
}
}
}
func main()
{
let task: Partition = Partition();
let text: String = "abcdefghijklmnopqrst";
// partition n = 4
task.nEqualPartition(text, 4);
// partition n = 5
task.nEqualPartition(text, 5);
// partition n = 3
task.nEqualPartition(text, 3);
}
main();
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
// Kotlin program for
// Divide a string into n equal parts
class Partition
{
fun nEqualPartition(text: String, n: Int): Unit
{
// Get the length of given text
val length: Int = text.length;
// Display Given text
print("\n Given text : " + text);
// Display partition size
print("\n Partition size : " + n + " \n ");
if (length == 0 || n <= 0 || (length % n) != 0)
{
// When of partition not possible
print("\n Equal partition not possible of size " + n);
}
else
{
// Get length of each part
val part: Int = length / n;
var i: Int = 0;
// Display result
while (i < length)
{
print(text.get(i));
if ((i + 1) % part == 0)
{
// Separate the result by new line
print("\n ");
}
i += 1;
}
}
}
}
fun main(args: Array < String > ): Unit
{
val task: Partition = Partition();
val text: String = "abcdefghijklmnopqrst";
// partition n = 4
task.nEqualPartition(text, 4);
// partition n = 5
task.nEqualPartition(text, 5);
// partition n = 3
task.nEqualPartition(text, 3);
}
Output
Given text : abcdefghijklmnopqrst
Partition size : 4
abcde
fghij
klmno
pqrst
Given text : abcdefghijklmnopqrst
Partition size : 5
abcd
efgh
ijkl
mnop
qrst
Given text : abcdefghijklmnopqrst
Partition size : 3
Equal partition not possible of size 3
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