Delete last node of linked list in swift
Swift program for Delete last node of linked list. Here problem description and explanation.
import Foundation
/*
Swift 4 program for
Delete the last node of singly linked list
*/
// Linked list node
class LinkNode
{
var data: Int;
var next: LinkNode? ;
init(_ data: Int)
{
self.data = data;
self.next = nil;
}
}
class SingleLL
{
var head: LinkNode? ;
var tail: LinkNode? ;
init()
{
self.head = nil;
self.tail = nil;
}
// Add new node at the end of linked list
func addNode(_ value: Int)
{
// Create a new node
let node: LinkNode? = LinkNode(value);
if (self.head == nil)
{
self.head = node;
}
else
{
self.tail!.next = node;
}
// Set new last node
self.tail = node;
}
// Display linked list element
func display()
{
if (self.head == nil)
{
print("Empty Linked List");
return;
}
var temp: LinkNode? = self.head;
// iterating linked list elements
while (temp != nil)
{
print(temp!.data, terminator: " → ");
// Visit to next node
temp = temp!.next;
}
print("NULL");
}
// Delete last node of singly linked list
func deleteLastNode()
{
if (self.head == nil)
{
print("Empty Linked List");
return;
}
else
{
var temp: LinkNode? = self.head;
var find: LinkNode? = nil;
// Find second last node
while (temp!.next != nil)
{
find = temp;
temp = temp!.next;
}
if (find == nil)
{
// Delete head node of linked list
self.head = nil;
self.tail = nil;
}
else
{
// Set new last node
self.tail = find;
find!.next = nil;
}
}
}
static func main(_ args: [String])
{
let sll: SingleLL? = SingleLL();
// Linked list
// 1 → 2 → 3 → 4 → 5 → 6 → NULL
sll!.addNode(1);
sll!.addNode(2);
sll!.addNode(3);
sll!.addNode(4);
sll!.addNode(5);
sll!.addNode(6);
print("Before Delete ");
sll!.display();
sll!.deleteLastNode();
print("After Delete ");
sll!.display();
}
}
SingleLL.main([String]());
Output
Before Delete
1 → 2 → 3 → 4 → 5 → 6 → NULL
After Delete
1 → 2 → 3 → 4 → 5 → NULL
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