Delete last node of linked list in java
Java program for Delete last node of linked list. Here problem description and explanation.
/*
Java program for
Delete the last node of singly linked list
*/
// Linked list node
class LinkNode
{
public int data;
public LinkNode next;
public LinkNode(int data)
{
this.data = data;
this.next = null;
}
}
public class SingleLL
{
public LinkNode head;
public LinkNode tail;
public SingleLL()
{
this.head = null;
this.tail = null;
}
// Add new node at the end of linked list
public void addNode(int value)
{
// Create a new node
LinkNode node = new LinkNode(value);
if (this.head == null)
{
this.head = node;
}
else
{
this.tail.next = node;
}
this.tail = node;
}
// Display linked list element
public void display()
{
if (this.head == null)
{
System.out.println("Empty Linked List");
return;
}
LinkNode temp = this.head;
// iterating linked list elements
while (temp != null)
{
System.out.print(temp.data + " → ");
// Visit to next node
temp = temp.next;
}
System.out.println("NULL");
}
// Delete last node of singly linked list
public void deleteLastNode()
{
if (this.head == null)
{
System.out.println("Empty Linked List");
return;
}
else
{
LinkNode temp = this.head;
LinkNode find = null;
// Find second last node
while (temp.next != null)
{
find = temp;
temp = temp.next;
}
if (find == null)
{
// Delete head node of linked list
this.head = null;
this.tail = null;
}
else
{
// Set new last node
this.tail = find;
find.next = null;
}
}
}
public static void main(String[] args)
{
SingleLL sll = new SingleLL();
// Linked list
// 1 → 2 → 3 → 4 → 5 → 6 → NULL
sll.addNode(1);
sll.addNode(2);
sll.addNode(3);
sll.addNode(4);
sll.addNode(5);
sll.addNode(6);
System.out.println("Before Delete ");
sll.display();
sll.deleteLastNode();
System.out.println("After Delete ");
sll.display();
}
}

Output
Before Delete
1 → 2 → 3 → 4 → 5 → 6 → NULL
After Delete
1 → 2 → 3 → 4 → 5 → NULL
Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.
New Comment