Delete initial n nodes in a doubly linked list

The problem involves deleting the initial n nodes from a doubly linked list. In a doubly linked list, each node contains a data element and two pointers, one pointing to the next node and another pointing to the previous node. The task is to remove the first n nodes from the beginning of the list.

Problem Statement

Given a doubly linked list and an integer n, the objective is to delete the first n nodes from the beginning of the list.

Example

Consider the following doubly linked list:

1 <-> 2 <-> 3 <-> 4 <-> 5 <-> 6 <-> 7 <-> 8

If we want to delete the first 5 nodes from the beginning of the list, the resulting list should be:

6 <-> 7 <-> 8

Idea to Solve

To solve this problem, you need to traverse the list while keeping track of the number of nodes you have visited. Once you have visited n nodes, you can manipulate the pointers of the nodes to remove them from the list.

Pseudocode

function deleteFirstN(n):
    if head is null or n is less than or equal to 0:
        return
    
    temp = head
    counter = 0
    while temp is not null and counter < n:
        increment counter by 1
        move temp to the next node
    
    if counter is greater than or equal to n:
        counter = n
        while counter > 0 and head is not null:
            temp = head
            head = temp.next
            if head is not null:
                head.prev = null
            if temp equals tail:
                tail = null
            temp = null
            decrement counter by 1
    else:
        print "Deleted node " + n + " not exist"

Algorithm Explanation

1. Start by initializing temp to the head of the list and counter to 0.
2. Traverse the doubly linked list using the temp pointer:
   • Increment the counter by 1.
   • Move temp to the next node.
3. After traversing, check if counter is greater than or equal to n:
   • If it is, you have visited at least n nodes.
   • Initialize counter to n.
   • Loop through n times and delete nodes from the beginning:
     • Update the head pointer to point to the next node.
     • If the new head is not null, update its prev pointer.
     • If the node being deleted is the tail, update tail to null.
   • Set temp to null after each deletion.
   • Decrement counter by 1 after each deletion.
4. If counter is less than n, print a message indicating that the node to be deleted doesn't exist.

Program List

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Time Complexity

The time complexity of this algorithm is O(n), where n is the number of nodes in the doubly linked list. In the worst case, you might need to traverse the entire list to delete the initial n nodes.