Decimal to roman numeral converter in swift
Swift program for Decimal to roman numeral converter. Here mentioned other language solution.
import Foundation
// Swift program for
// Conversion from Decimal to roman number
class Perform
{
// Display roman value of n
static func result(_ n : Int)
{
switch(n) {
// Test Cases
case 1:
print("I",terminator: "");
case 4:
print("IV",terminator: "");
case 5:
print("V",terminator: "");
case 9:
print("IX",terminator: "");
case 10:
print("X",terminator: "");
case 40:
print("XL",terminator: "");
case 50:
print("L",terminator: "");
case 90:
print("XC",terminator: "");
case 100:
print("C",terminator: "");
case 400:
print("CD",terminator: "");
case 500:
print("D",terminator: "");
case 900:
print("DM",terminator: "");
case 1000:
print("M",terminator: "");
default:
return;
}
}
static func select(_ number : Int, _ collection : [Int], _ size : Int) -> Int
{
var n : Int = 1;
var i : Int = 0;
do
{
i = 0;
while (i < size)
{
if (number >= collection[i])
{
n = collection[i];
}
else
{
break;
}
i += 1;
}
}
Perform.result(n);
// Reduce the value of number
return number - n;
}
static func romanNo(_ num : Int)
{
var number = num;
if (number <= 0)
{
// When is not a natural number
return;
}
// Base case collection
let collection : [Int] =
[1, 4, 5, 9, 10, 40, 50, 90, 100, 400, 500, 900, 1000];
// Get the size of collection
let size : Int = collection.count;
print(" \(number) ",terminator: ": ");
while (number > 0)
{
number = Perform.select(number, collection,size);
}
// Add new line
print();
}
static func main(_ args : inout [String])
{
// Test Case
Perform.romanNo(10);
Perform.romanNo(18);
Perform.romanNo(189);
Perform.romanNo(604);
Perform.romanNo(982);
Perform.romanNo(3000);
}
}
var record : [String] = CommandLine.arguments;
Perform.main(&record);
Output
10 : X
18 : XVIII
189 : CLXXXIX
604 : DCIV
982 : DMLXXXII
3000 : MMM
Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.
New Comment