Count valid unset bits in numbers from 1 to n in php

Php program for Count valid unset bits in numbers from 1 to n. Here mentioned other language solution.

<?php
/*
   Php program for
   Count valid unset bits in all numbers from 1 to n
*/
class BitCount
{
	// Returns number of set bits of given number
	public	function countSetBit($num)
	{
		$x = $num;
		$x = $x - (($x >> 1) & 1431655765);
		$x = ($x & 858993459) + (($x >> 2) & 858993459);
		$x = ($x + ($x >> 4)) & 252645135;
		$x = $x + ($x >> 8);
		$x = $x + ($x >> 16);
		$x = $x & 63;
		// Number of set bit
		return $x;
	}
	// Handles the request of count the all 
	// unset bits from (1 to n)
	public	function countUnsetBit($n)
	{
		$result = 0;
		// Execute loop from 1 to n
		for ($i = 1; $i <= $n; ++$i)
		{
			// Total bits - Active bits
			$result += ((int)(log($i) / log(2.0) + 1.0)) - 
              $this->countSetBit($i);
		}
		// Display result
		echo " Unset bits from (1 to ".($n).
		") : ".($result), "\n";
	}
	public static function main()
	{
		$task = new BitCount();
		// Test A
		// number(1-7)  Un-setbit
		// ----------------
		// 1  = 1         0
		// 2  = 10        1
		// 3  = 11        0   
		// 4  = 100       2
		// 5  = 101       1
		// 6  = 110       1 
		// 7  = 111       0
		// --------------------
		//                5
		$task->countUnsetBit(7);
		// Test B
		// number(1-10)  Setbit
		// ----------------
		// 1  = 1         0
		// 2  = 10        1
		// 3  = 11        0   
		// 4  = 100       2
		// 5  = 101       1
		// 6  = 110       1 
		// 7  = 111       0
		// 8  = 1000      3
		// 9  = 1001      2 
		// 10  = 1010     2 
		// --------------------
		//                12
		$task->countUnsetBit(10);
	}
}
BitCount::main();

Output

 Unset bits from (1 to 7) : 5
 Unset bits from (1 to 10) : 12