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Count pairs with Odd XOR occurrence

Here given code implementation process.

// C program for
// Count pairs with Odd XOR occurrence
#include <stdio.h>

// Display array elements
void printData(int arr[], int n)
{
	printf("\n Array : ");
	for (int i = 0; i < n; ++i)
	{
		// print element
		printf("  %d", arr[i]);
	}
}
void countOddXorPair(int arr[], int n)
{
	// Display given array
	printData(arr, n);
	int odd = 0;
	int even = 0;
	// Counting Even and Odd occurrence in array
	for (int i = 0; i < n; ++i)
	{
		if ((arr[i] % 2) == 0)
		{
			// When elements are even
			even++;
		}
		else
		{
			// When elements are odd
			odd++;
		}
	}
	printf("\n Result : %d ", odd *even);
}
int main(int argc, char
	const *argv[])
{
	int arr[] = {
		1 , 6 , 3 , 8 , 3 , 4 , 2
	};
	// Get the number of elements
	int n = sizeof(arr) / sizeof(arr[0]);
	/*
	    (1 ⊕ 6) = 7
	    (1 ⊕ 8) = 9
	    (1 ⊕ 4) = 5
	    (1 ⊕ 2) = 3
	    (6 ⊕ 3) = 5
	    (6 ⊕ 3) = 5
	    (3 ⊕ 8) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    (8 ⊕ 3) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    ---------------
	    Total : 12
	*/
	// Test
	countOddXorPair(arr, n);
	return 0;
}

input

 Array :   1  6  3  8  3  4  2
 Result : 12
/*
    Java program for
    Count pairs with Odd XOR occurrence
*/
public class Counting
{
	// Display array elements
	public void printData(int[] arr, int n)
	{
		System.out.print("\n Array : ");
		for (int i = 0; i < n; ++i)
		{
			// print element
			System.out.print(" " + arr[i]);
		}
	}
	public void countOddXorPair(int[] arr, int n)
	{
		// Display given array
		this.printData(arr, n);
		int odd = 0;
		int even = 0;
		// Counting Even and Odd occurrence in array
		for (int i = 0; i < n; ++i)
		{
			if ((arr[i] % 2) == 0)
			{
				// When elements are even
				even++;
			}
			else
			{
				// When elements are odd
				odd++;
			}
		}
		System.out.print("\n Result : " + odd * even);
	}
	public static void main(String[] args)
	{
		Counting task = new Counting();
		int[] arr = {
			1 , 6 , 3 , 8 , 3 , 4 , 2
		};
		// Get the number of elements
		int n = arr.length;
		/*
		    (1 ⊕ 6) = 7
		    (1 ⊕ 8) = 9
		    (1 ⊕ 4) = 5
		    (1 ⊕ 2) = 3
		    (6 ⊕ 3) = 5
		    (6 ⊕ 3) = 5
		    (3 ⊕ 8) = 11
		    (3 ⊕ 4) = 7
		    (3 ⊕ 2) = 1
		    (8 ⊕ 3) = 11
		    (3 ⊕ 4) = 7
		    (3 ⊕ 2) = 1
		    ---------------
		    Total : 12
		*/
		task.countOddXorPair(arr, n);
	}
}

input

 Array :  1 6 3 8 3 4 2
 Result : 12
// Include header file
#include <iostream>

using namespace std;
/*
    C++ program for
    Count pairs with Odd XOR occurrence
*/
class Counting
{
	public:
		// Display array elements
		void printData(int arr[], int n)
		{
			cout << "\n Array : ";
			for (int i = 0; i < n; ++i)
			{
				// print element
				cout << " " << arr[i];
			}
		}
	void countOddXorPair(int arr[], int n)
	{
		// Display given array
		this->printData(arr, n);
		int odd = 0;
		int even = 0;
		// Counting Even and Odd occurrence in array
		for (int i = 0; i < n; ++i)
		{
			if ((arr[i] % 2) == 0)
			{
				// When elements are even
				even++;
			}
			else
			{
				// When elements are odd
				odd++;
			}
		}
		cout << "\n Result : " << odd *even;
	}
};
int main()
{
	Counting *task = new Counting();
	int arr[] = {
		1 , 6 , 3 , 8 , 3 , 4 , 2
	};
	// Get the number of elements
	int n = sizeof(arr) / sizeof(arr[0]);
	/*
	    (1 ⊕ 6) = 7
	    (1 ⊕ 8) = 9
	    (1 ⊕ 4) = 5
	    (1 ⊕ 2) = 3
	    (6 ⊕ 3) = 5
	    (6 ⊕ 3) = 5
	    (3 ⊕ 8) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    (8 ⊕ 3) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    ---------------
	    Total : 12
	*/
	task->countOddXorPair(arr, n);
	return 0;
}

input

 Array :  1 6 3 8 3 4 2
 Result : 12
// Include namespace system
using System;
/*
    Csharp program for
    Count pairs with Odd XOR occurrence
*/
public class Counting
{
	// Display array elements
	public void printData(int[] arr, int n)
	{
		Console.Write("\n Array : ");
		for (int i = 0; i < n; ++i)
		{
			// print element
			Console.Write(" " + arr[i]);
		}
	}
	public void countOddXorPair(int[] arr, int n)
	{
		// Display given array
		this.printData(arr, n);
		int odd = 0;
		int even = 0;
		// Counting Even and Odd occurrence in array
		for (int i = 0; i < n; ++i)
		{
			if ((arr[i] % 2) == 0)
			{
				// When elements are even
				even++;
			}
			else
			{
				// When elements are odd
				odd++;
			}
		}
		Console.Write("\n Result : " + odd * even);
	}
	public static void Main(String[] args)
	{
		Counting task = new Counting();
		int[] arr = {
			1 , 6 , 3 , 8 , 3 , 4 , 2
		};
		// Get the number of elements
		int n = arr.Length;
		/*
		    (1 ⊕ 6) = 7
		    (1 ⊕ 8) = 9
		    (1 ⊕ 4) = 5
		    (1 ⊕ 2) = 3
		    (6 ⊕ 3) = 5
		    (6 ⊕ 3) = 5
		    (3 ⊕ 8) = 11
		    (3 ⊕ 4) = 7
		    (3 ⊕ 2) = 1
		    (8 ⊕ 3) = 11
		    (3 ⊕ 4) = 7
		    (3 ⊕ 2) = 1
		    ---------------
		    Total : 12
		*/
		task.countOddXorPair(arr, n);
	}
}

input

 Array :  1 6 3 8 3 4 2
 Result : 12
package main
import "fmt"
/*
    Go program for
    Count pairs with Odd XOR occurrence
*/

// Display array elements
func printData(arr[] int, n int) {
	fmt.Print("\n Array : ")
	for i := 0 ; i < n ; i++ {
		// print element
		fmt.Print(" ", arr[i])
	}
}
func countOddXorPair(arr[] int, n int) {
	// Display given array
	printData(arr, n)
	var odd int = 0
	var even int = 0
	// Counting Even and Odd occurrence in array
	for i := 0 ; i < n ; i++ {
		if (arr[i] % 2) == 0 {
			// When elements are even
			even++
		} else {
			// When elements are odd
			odd++
		}
	}
	fmt.Print("\n Result : ", odd * even)
}
func main() {

	var arr = [] int {
		1,
		6,
		3,
		8,
		3,
		4,
		2,
	}
	// Get the number of elements
	var n int = len(arr)
	/*
	    (1 ⊕ 6) = 7
	    (1 ⊕ 8) = 9
	    (1 ⊕ 4) = 5
	    (1 ⊕ 2) = 3
	    (6 ⊕ 3) = 5
	    (6 ⊕ 3) = 5
	    (3 ⊕ 8) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    (8 ⊕ 3) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    ---------------
	    Total : 12
	*/
	countOddXorPair(arr, n)
}

input

 Array :  1 6 3 8 3 4 2
 Result : 12
<?php
/*
    Php program for
    Count pairs with Odd XOR occurrence
*/
class Counting
{
	// Display array elements
	public	function printData($arr, $n)
	{
		echo("\n Array : ");
		for ($i = 0; $i < $n; ++$i)
		{
			// print element
			echo(" ".$arr[$i]);
		}
	}
	public	function countOddXorPair($arr, $n)
	{
		// Display given array
		$this->printData($arr, $n);
		$odd = 0;
		$even = 0;
		// Counting Even and Odd occurrence in array
		for ($i = 0; $i < $n; ++$i)
		{
			if (($arr[$i] % 2) == 0)
			{
				// When elements are even
				$even++;
			}
			else
			{
				// When elements are odd
				$odd++;
			}
		}
		echo("\n Result : ".$odd * $even);
	}
}

function main()
{
	$task = new Counting();
	$arr = array(1, 6, 3, 8, 3, 4, 2);
	// Get the number of elements
	$n = count($arr);
	/*
	    (1 ⊕ 6) = 7
	    (1 ⊕ 8) = 9
	    (1 ⊕ 4) = 5
	    (1 ⊕ 2) = 3
	    (6 ⊕ 3) = 5
	    (6 ⊕ 3) = 5
	    (3 ⊕ 8) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    (8 ⊕ 3) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    ---------------
	    Total : 12
	*/
	$task->countOddXorPair($arr, $n);
}
main();

input

 Array :  1 6 3 8 3 4 2
 Result : 12
/*
    Node JS program for
    Count pairs with Odd XOR occurrence
*/
class Counting
{
	// Display array elements
	printData(arr, n)
	{
		process.stdout.write("\n Array : ");
		for (var i = 0; i < n; ++i)
		{
			// print element
			process.stdout.write(" " + arr[i]);
		}
	}
	countOddXorPair(arr, n)
	{
		// Display given array
		this.printData(arr, n);
		var odd = 0;
		var even = 0;
		// Counting Even and Odd occurrence in array
		for (var i = 0; i < n; ++i)
		{
			if ((arr[i] % 2) == 0)
			{
				// When elements are even
				even++;
			}
			else
			{
				// When elements are odd
				odd++;
			}
		}
		process.stdout.write("\n Result : " + odd * even);
	}
}

function main()
{
	var task = new Counting();
	var arr = [1, 6, 3, 8, 3, 4, 2];
	// Get the number of elements
	var n = arr.length;
	/*
	    (1 ⊕ 6) = 7
	    (1 ⊕ 8) = 9
	    (1 ⊕ 4) = 5
	    (1 ⊕ 2) = 3
	    (6 ⊕ 3) = 5
	    (6 ⊕ 3) = 5
	    (3 ⊕ 8) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    (8 ⊕ 3) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    ---------------
	    Total : 12
	*/
	task.countOddXorPair(arr, n);
}
main();

input

 Array :  1 6 3 8 3 4 2
 Result : 12
#    Python 3 program for
#    Count pairs with Odd XOR occurrence
class Counting :
	#  Display list elements
	def printData(self, arr, n) :
		print("\n Array : ", end = "")
		i = 0
		while (i < n) :
			#  print element
			print(" ", arr[i], end = "")
			i += 1
		
	
	def countOddXorPair(self, arr, n) :
		#  Display given list
		self.printData(arr, n)
		odd = 0
		even = 0
		i = 0
		#  Counting Even and Odd occurrence in list
		while (i < n) :
			if ((arr[i] % 2) == 0) :
				#  When elements are even
				even += 1
			else :
				#  When elements are odd
				odd += 1
			
			i += 1
		
		print("\n Result : ", odd * even, end = "")
	

def main() :
	task = Counting()
	arr = [1, 6, 3, 8, 3, 4, 2]
	#  Get the number of elements
	n = len(arr)
	#    (1 ⊕ 6) = 7
	#    (1 ⊕ 8) = 9
	#    (1 ⊕ 4) = 5
	#    (1 ⊕ 2) = 3
	#    (6 ⊕ 3) = 5
	#    (6 ⊕ 3) = 5
	#    (3 ⊕ 8) = 11
	#    (3 ⊕ 4) = 7
	#    (3 ⊕ 2) = 1
	#    (8 ⊕ 3) = 11
	#    (3 ⊕ 4) = 7
	#    (3 ⊕ 2) = 1
	#    ---------------
	#    Total : 12
	task.countOddXorPair(arr, n)

if __name__ == "__main__": main()

input

 Array :   1  6  3  8  3  4  2
 Result :  12
#    Ruby program for
#    Count pairs with Odd XOR occurrence
class Counting 
	#  Display array elements
	def printData(arr, n) 
		print("\n Array : ")
		i = 0
		while (i < n) 
			#  print element
			print(" ", arr[i])
			i += 1
		end

	end

	def countOddXorPair(arr, n) 
		#  Display given array
		self.printData(arr, n)
		odd = 0
		even = 0
		i = 0
		#  Counting Even and Odd occurrence in array
		while (i < n) 
			if ((arr[i] % 2) == 0) 
				#  When elements are even
				even += 1
			else
 
				#  When elements are odd
				odd += 1
			end

			i += 1
		end

		print("\n Result : ", odd * even)
	end

end

def main() 
	task = Counting.new()
	arr = [1, 6, 3, 8, 3, 4, 2]
	#  Get the number of elements
	n = arr.length
	#    (1 ⊕ 6) = 7
	#    (1 ⊕ 8) = 9
	#    (1 ⊕ 4) = 5
	#    (1 ⊕ 2) = 3
	#    (6 ⊕ 3) = 5
	#    (6 ⊕ 3) = 5
	#    (3 ⊕ 8) = 11
	#    (3 ⊕ 4) = 7
	#    (3 ⊕ 2) = 1
	#    (8 ⊕ 3) = 11
	#    (3 ⊕ 4) = 7
	#    (3 ⊕ 2) = 1
	#    ---------------
	#    Total : 12
	task.countOddXorPair(arr, n)
end

main()

input

 Array :  1 6 3 8 3 4 2
 Result : 12
/*
    Scala program for
    Count pairs with Odd XOR occurrence
*/
class Counting()
{
	// Display array elements
	def printData(arr: Array[Int], n: Int): Unit = {
		print("\n Array : ");
		var i: Int = 0;
		while (i < n)
		{
			// print element
			print(" " + arr(i));
			i += 1;
		}
	}
	def countOddXorPair(arr: Array[Int], n: Int): Unit = {
		// Display given array
		this.printData(arr, n);
		var odd: Int = 0;
		var even: Int = 0;
		var i: Int = 0;
		// Counting Even and Odd occurrence in array
		while (i < n)
		{
			if ((arr(i) % 2) == 0)
			{
				// When elements are even
				even += 1;
			}
			else
			{
				// When elements are odd
				odd += 1;
			}
			i += 1;
		}
		print("\n Result : " + odd * even);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Counting = new Counting();
		var arr: Array[Int] = Array(1, 6, 3, 8, 3, 4, 2);
		// Get the number of elements
		var n: Int = arr.length;
		/*
		    (1 ⊕ 6) = 7
		    (1 ⊕ 8) = 9
		    (1 ⊕ 4) = 5
		    (1 ⊕ 2) = 3
		    (6 ⊕ 3) = 5
		    (6 ⊕ 3) = 5
		    (3 ⊕ 8) = 11
		    (3 ⊕ 4) = 7
		    (3 ⊕ 2) = 1
		    (8 ⊕ 3) = 11
		    (3 ⊕ 4) = 7
		    (3 ⊕ 2) = 1
		    ---------------
		    Total : 12
		*/
		task.countOddXorPair(arr, n);
	}
}

input

 Array :  1 6 3 8 3 4 2
 Result : 12
import Foundation;
/*
    Swift 4 program for
    Count pairs with Odd XOR occurrence
*/
class Counting
{
	// Display array elements
	func printData(_ arr: [Int], _ n: Int)
	{
		print("\n Array : ", terminator: "");
		var i: Int = 0;
		while (i < n)
		{
			// print element
			print(" ", arr[i], terminator: "");
			i += 1;
		}
	}
	func countOddXorPair(_ arr: [Int], _ n: Int)
	{
		// Display given array
		self.printData(arr, n);
		var odd: Int = 0;
		var even: Int = 0;
		var i: Int = 0;
		// Counting Even and Odd occurrence in array
		while (i < n)
		{
			if ((arr[i] % 2) == 0)
			{
				// When elements are even
				even += 1;
			}
			else
			{
				// When elements are odd
				odd += 1;
			}
			i += 1;
		}
		print("\n Result : ", odd * even, terminator: "");
	}
}
func main()
{
	let task: Counting = Counting();
	let arr: [Int] = [1, 6, 3, 8, 3, 4, 2];
	// Get the number of elements
	let n: Int = arr.count;
	/*
	    (1 ⊕ 6) = 7
	    (1 ⊕ 8) = 9
	    (1 ⊕ 4) = 5
	    (1 ⊕ 2) = 3
	    (6 ⊕ 3) = 5
	    (6 ⊕ 3) = 5
	    (3 ⊕ 8) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    (8 ⊕ 3) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    ---------------
	    Total : 12
	*/
	task.countOddXorPair(arr, n);
}
main();

input

 Array :   1  6  3  8  3  4  2
 Result :  12
/*
    Kotlin program for
    Count pairs with Odd XOR occurrence
*/
class Counting
{
	// Display array elements
	fun printData(arr: Array < Int > , n: Int): Unit
	{
		print("\n Array : ");
		var i: Int = 0;
		while (i < n)
		{
			// print element
			print(" " + arr[i]);
			i += 1;
		}
	}
	fun countOddXorPair(arr: Array < Int > , n: Int): Unit
	{
		// Display given array
		this.printData(arr, n);
		var odd: Int = 0;
		var even: Int = 0;
		var i: Int = 0;
		// Counting Even and Odd occurrence in array
		while (i < n)
		{
			if ((arr[i] % 2) == 0)
			{
				// When elements are even
				even += 1;
			}
			else
			{
				// When elements are odd
				odd += 1;
			}
			i += 1;
		}
		print("\n Result : " + odd * even);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: Counting = Counting();
	val arr: Array < Int > = arrayOf(1, 6, 3, 8, 3, 4, 2);
	// Get the number of elements
	val n: Int = arr.count();
	/*
	    (1 ⊕ 6) = 7
	    (1 ⊕ 8) = 9
	    (1 ⊕ 4) = 5
	    (1 ⊕ 2) = 3
	    (6 ⊕ 3) = 5
	    (6 ⊕ 3) = 5
	    (3 ⊕ 8) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    (8 ⊕ 3) = 11
	    (3 ⊕ 4) = 7
	    (3 ⊕ 2) = 1
	    ---------------
	    Total : 12
	*/
	task.countOddXorPair(arr, n);
}

input

 Array :  1 6 3 8 3 4 2
 Result : 12
Last updated on by Kalkicode




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