# Count odd paths in Binary Tree

Here given code implementation process.

``````// C program
// Count odd paths in Binary Tree

#include <stdio.h>
#include <stdlib.h>

//Binary Tree node
struct Node
{
int data;
struct Node *left, *right;
};

//This is creating a binary tree node and return this
struct Node *get_node(int data)
{
// Create dynamic node
struct Node *new_node = (struct Node *) malloc(sizeof(struct Node));
if (new_node != NULL)
{
//Set data and pointer values
new_node->data = data;
new_node->left = NULL;
new_node->right = NULL;
}
else
{
//This is indicates, segmentation fault or memory overflow problem
printf("Memory Overflow\n");
}
//return new node
return new_node;
}

// Count all paths from root to leaf which containing all Odd nodes
int count_odd_path(struct Node*root)
{

if(root == NULL || root->data % 2 == 0)
{
//When tree node is null or its contain Even value
return 0;
}
else
{
if(root->left==NULL && root->right == NULL)
{
//When get leaf node
return 1;
}
return count_odd_path(root->left) + count_odd_path(root->right);
}
}

int main()
{

struct Node *root = NULL;

/*
Construct Binary Tree
-----------------------
5
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/

root = get_node(5);
root->left = get_node(3);
root->right = get_node(9);
root->right->right = get_node(3);
root->left->right = get_node(6);
root->right->left = get_node(1);
root->left->left = get_node(7);
root->left->left->left = get_node(10);
root->left->left->right = get_node(3);
root->right->left->right = get_node(4);
root->right->left->left = get_node(7);

int counter = count_odd_path(root);

printf("Total Odd path in this tree are : %d \n",counter);

return 0;
}``````

#### Output

``Total Odd path in this tree are : 3``
``````/*
Java Program
Count odd paths in Binary Tree
*/

//Binary Tree node
class Node
{
public int data;
public Node left;
public Node right;
public Node(int data)
{
// Set node value
this.data = data;
this.left = null;
this.right = null;
}
}
class BinaryTree
{
public Node root;
public BinaryTree()
{
//Set initial tree root to null
this.root = null;
}
// Count all paths from root to leaf which containing all Odd nodes
public int count_odd_path(Node root)
{
if (root == null || root.data % 2 == 0)
{
//When tree node is null or its contain Even value
return 0;
}
else
{
if (root.left == null && root.right == null)
{
//When get leaf node
return 1;
}
return count_odd_path(root.left) + count_odd_path(root.right);
}
}
public static void main(String[] args)
{
//Make object of binary tree
BinaryTree tree = new BinaryTree();
/*
Construct Binary Tree
-----------------------
5
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/
tree.root = new Node(5);
tree.root.left = new Node(3);
tree.root.right = new Node(9);
tree.root.right.right = new Node(3);
tree.root.left.right = new Node(6);
tree.root.right.left = new Node(1);
tree.root.left.left = new Node(7);
tree.root.left.left.left = new Node(10);
tree.root.left.left.right = new Node(3);
tree.root.right.left.right = new Node(4);
tree.root.right.left.left = new Node(7);

int counter = tree.count_odd_path(tree.root);
// Display calculated result
System.out.print("Total Odd path in this tree are : " + counter + " \n");
}
}``````

#### Output

``Total Odd path in this tree are : 3``
``````//Include header file
#include <iostream>
using namespace std;

/*
C++ Program
Count odd paths in Binary Tree
*/

//Binary Tree node
class Node
{
public:
int data;
Node *left;
Node *right;
Node(int data)
{
// Set node value
this->data = data;
this->left = NULL;
this->right = NULL;
}
};
class BinaryTree
{
public:
Node *root;
BinaryTree()
{
//Set initial tree root to null
this->root = NULL;
}
// Count all paths from root to leaf which containing all Odd nodes
int count_odd_path(Node *root)
{
if (root == NULL || root->data % 2 == 0)
{
//When tree node is null or its contain Even value
return 0;
}
else
{
if (root->left == NULL && root->right == NULL)
{
//When get leaf node
return 1;
}
return this->count_odd_path(root->left) + this->count_odd_path(root->right);
}
}
};
int main()
{
//Make object of binary tree
BinaryTree tree = BinaryTree();
/*
Construct Binary Tree
-----------------------
5
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/
tree.root = new Node(5);
tree.root->left = new Node(3);
tree.root->right = new Node(9);
tree.root->right->right = new Node(3);
tree.root->left->right = new Node(6);
tree.root->right->left = new Node(1);
tree.root->left->left = new Node(7);
tree.root->left->left->left = new Node(10);
tree.root->left->left->right = new Node(3);
tree.root->right->left->right = new Node(4);
tree.root->right->left->left = new Node(7);
int counter = tree.count_odd_path(tree.root);
// Display calculated result
cout << "Total Odd path in this tree are : " << counter << " \n";
return 0;
}``````

#### Output

``Total Odd path in this tree are : 3``
``````//Include namespace system
using System;

/*
C# Program
Count odd paths in Binary Tree
*/

//Binary Tree node
class Node
{
public int data;
public Node left;
public Node right;
public Node(int data)
{
// Set node value
this.data = data;
this.left = null;
this.right = null;
}
}
class BinaryTree
{
public Node root;
public BinaryTree()
{
//Set initial tree root to null
this.root = null;
}
// Count all paths from root to leaf which containing all Odd nodes
public int count_odd_path(Node root)
{
if (root == null || root.data % 2 == 0)
{
//When tree node is null or its contain Even value
return 0;
}
else
{
if (root.left == null && root.right == null)
{
//When get leaf node
return 1;
}
return count_odd_path(root.left) + count_odd_path(root.right);
}
}
public static void Main(String[] args)
{
//Make object of binary tree
BinaryTree tree = new BinaryTree();
/*
Construct Binary Tree
-----------------------
5
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/
tree.root = new Node(5);
tree.root.left = new Node(3);
tree.root.right = new Node(9);
tree.root.right.right = new Node(3);
tree.root.left.right = new Node(6);
tree.root.right.left = new Node(1);
tree.root.left.left = new Node(7);
tree.root.left.left.left = new Node(10);
tree.root.left.left.right = new Node(3);
tree.root.right.left.right = new Node(4);
tree.root.right.left.left = new Node(7);
int counter = tree.count_odd_path(tree.root);
// Display calculated result
Console.Write("Total Odd path in this tree are : " + counter + " \n");
}
}``````

#### Output

``Total Odd path in this tree are : 3``
``````<?php
/*
Php Program
Count odd paths in Binary Tree
*/

// Binary Tree node
class Node
{
public \$data;
public \$left;
public \$right;

function __construct(\$data)
{
// Set node value
\$this->data = \$data;
\$this->left = null;
\$this->right = null;
}
}
class BinaryTree
{
public \$root;

function __construct()
{
//Set initial tree root to null
\$this->root = null;
}
// Count all paths from root to leaf which containing all Odd nodes
public	function count_odd_path(\$root)
{
if (\$root == null || \$root->data % 2 == 0)
{
//When tree node is null or its contain Even value
return 0;
}
else
{
if (\$root->left == null && \$root->right == null)
{
//When get leaf node
return 1;
}
return \$this->count_odd_path(\$root->left) + \$this->count_odd_path(\$root->right);
}
}
}

function main()
{
//Make object of binary tree
\$tree = new BinaryTree();
/*
Construct Binary Tree
-----------------------
5
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/
\$tree->root = new Node(5);
\$tree->root->left = new Node(3);
\$tree->root->right = new Node(9);
\$tree->root->right->right = new Node(3);
\$tree->root->left->right = new Node(6);
\$tree->root->right->left = new Node(1);
\$tree->root->left->left = new Node(7);
\$tree->root->left->left->left = new Node(10);
\$tree->root->left->left->right = new Node(3);
\$tree->root->right->left->right = new Node(4);
\$tree->root->right->left->left = new Node(7);
\$counter = \$tree->count_odd_path(\$tree->root);
// Display calculated result
echo "Total Odd path in this tree are : ". \$counter ." \n";
}
main();``````

#### Output

``Total Odd path in this tree are : 3``
``````/*
Node Js Program
Count odd paths in Binary Tree
*/

//Binary Tree node
class Node
{
constructor(data)
{
// Set node value
this.data = data;
this.left = null;
this.right = null;
}
}

class BinaryTree
{
constructor()
{
//Set initial tree root to null
this.root = null;
}
// Count all paths from root to leaf which containing all Odd nodes
count_odd_path(root)
{
if (root == null || root.data % 2 == 0)
{
//When tree node is null or its contain Even value
return 0;
}
else
{
if (root.left == null && root.right == null)
{
//When get leaf node
return 1;
}
return this.count_odd_path(root.left) + this.count_odd_path(root.right);
}
}
}

function main()
{
//Make object of binary tree
var tree = new BinaryTree();
/*
Construct Binary Tree
-----------------------
5
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/
tree.root = new Node(5);
tree.root.left = new Node(3);
tree.root.right = new Node(9);
tree.root.right.right = new Node(3);
tree.root.left.right = new Node(6);
tree.root.right.left = new Node(1);
tree.root.left.left = new Node(7);
tree.root.left.left.left = new Node(10);
tree.root.left.left.right = new Node(3);
tree.root.right.left.right = new Node(4);
tree.root.right.left.left = new Node(7);
var counter = tree.count_odd_path(tree.root);
// Display calculated result
process.stdout.write("Total Odd path in this tree are : " + counter + " \n");
}
main();``````

#### Output

``Total Odd path in this tree are : 3``
``````#   Python 3 Program
#   Count odd paths in Binary Tree

# Binary Tree node
class Node :

def __init__(self, data) :
#  Set node value
self.data = data
self.left = None
self.right = None

class BinaryTree :

def __init__(self) :
# Set initial tree root to null
self.root = None

#  Count all paths from root to leaf which containing all Odd nodes
def count_odd_path(self, root) :
if (root == None or root.data % 2 == 0) :
# When tree node is null or its contain Even value
return 0
else :
if (root.left == None and root.right == None) :
# When get leaf node
return 1

return self.count_odd_path(root.left) + self.count_odd_path(root.right)

def main() :
# Make object of binary tree
tree = BinaryTree()
#
# 		Construct Binary Tree
# 		-----------------------
# 		         5
# 		       /    \
# 		      3      9
# 		     / \    / \
# 		    7   6  1   3
# 		   / \    / \
# 		  10  3  7   4
#

tree.root = Node(5)
tree.root.left = Node(3)
tree.root.right = Node(9)
tree.root.right.right = Node(3)
tree.root.left.right = Node(6)
tree.root.right.left = Node(1)
tree.root.left.left = Node(7)
tree.root.left.left.left = Node(10)
tree.root.left.left.right = Node(3)
tree.root.right.left.right = Node(4)
tree.root.right.left.left = Node(7)
counter = tree.count_odd_path(tree.root)
#  Display calculated result
print("Total Odd path in this tree are : ", counter ," \n", end = "")

if __name__ == "__main__": main()``````

#### Output

``Total Odd path in this tree are :  3``
``````#   Ruby Program
#   Count odd paths in Binary Tree

# Binary Tree node
class Node
# Define the accessor and reader of class Node
attr_accessor :data, :left, :right

def initialize(data)
#  Set node value
self.data = data
self.left = nil
self.right = nil
end

end

class BinaryTree
# Define the accessor and reader of class BinaryTree
attr_accessor :root

def initialize()
# Set initial tree root to null
self.root = nil
end

#  Count all paths from root to leaf which containing all Odd nodes
def count_odd_path(root)
if (root == nil || root.data % 2 == 0)
# When tree node is null or its contain Even value
return 0
else
if (root.left == nil && root.right == nil)
# When get leaf node
return 1
end

return self.count_odd_path(root.left) + self.count_odd_path(root.right)
end

end

end

def main()
# Make object of binary tree
tree = BinaryTree.new()
#
# 		Construct Binary Tree
# 		-----------------------
# 		         5
# 		       /    \
# 		      3      9
# 		     / \    / \
# 		    7   6  1   3
# 		   / \    / \
# 		  10  3  7   4
#

tree.root = Node.new(5)
tree.root.left = Node.new(3)
tree.root.right = Node.new(9)
tree.root.right.right = Node.new(3)
tree.root.left.right = Node.new(6)
tree.root.right.left = Node.new(1)
tree.root.left.left = Node.new(7)
tree.root.left.left.left = Node.new(10)
tree.root.left.left.right = Node.new(3)
tree.root.right.left.right = Node.new(4)
tree.root.right.left.left = Node.new(7)
counter = tree.count_odd_path(tree.root)
#  Display calculated result
print("Total Odd path in this tree are : ", counter ," \n")
end

main()``````

#### Output

``````Total Odd path in this tree are : 3
``````
``````/*
Scala Program
Count odd paths in Binary Tree
*/

//Binary Tree node
class Node(var data: Int,
var left: Node,
var right: Node)
{
def this(data: Int)
{
this(data, null, null);
}
}
class BinaryTree(var root: Node)
{
def this()
{
this(null);
}
// Count all paths from root to leaf which containing all Odd nodes
def count_odd_path(root: Node): Int = {
if (root == null || root.data % 2 == 0)
{
//When tree node is null or its contain Even value
return 0;
}
else
{
if (root.left == null && root.right == null)
{
//When get leaf node
return 1;
}
return count_odd_path(root.left) + count_odd_path(root.right);
}
}
}
object Main
{
def main(args: Array[String]): Unit = {
//Make object of binary tree
var tree: BinaryTree = new BinaryTree();
/*
Construct Binary Tree
-----------------------
5
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/
tree.root = new Node(5);
tree.root.left = new Node(3);
tree.root.right = new Node(9);
tree.root.right.right = new Node(3);
tree.root.left.right = new Node(6);
tree.root.right.left = new Node(1);
tree.root.left.left = new Node(7);
tree.root.left.left.left = new Node(10);
tree.root.left.left.right = new Node(3);
tree.root.right.left.right = new Node(4);
tree.root.right.left.left = new Node(7);
var counter: Int = tree.count_odd_path(tree.root);
// Display calculated result
print("Total Odd path in this tree are : " + counter + " \n");
}
}``````

#### Output

``Total Odd path in this tree are : 3``
``````/*
Swift 4 Program
Count odd paths in Binary Tree
*/

//Binary Tree node
class Node
{
var data: Int;
var left: Node? ;
var right: Node? ;
init(_ data: Int)
{
// Set node value
self.data = data;
self.left = nil;
self.right = nil;
}
}
class BinaryTree
{
var root: Node? ;
init()
{
//Set initial tree root to null
self.root = nil;
}
// Count all paths from root to leaf which containing all Odd nodes
func count_odd_path(_ root: Node? ) -> Int
{
if (root == nil || root!.data % 2 == 0)
{
//When tree node is null or its contain Even value
return 0;
}
else
{
if (root!.left == nil && root!.right == nil)
{
//When get leaf node
return 1;
}
return self.count_odd_path(root!.left) + self.count_odd_path(root!.right);
}
}
}
func main()
{
//Make object of binary tree
let tree: BinaryTree = BinaryTree();
/*
Construct Binary Tree
-----------------------
5
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/
tree.root = Node(5);
tree.root!.left = Node(3);
tree.root!.right = Node(9);
tree.root!.right!.right = Node(3);
tree.root!.left!.right = Node(6);
tree.root!.right!.left = Node(1);
tree.root!.left!.left = Node(7);
tree.root!.left!.left!.left = Node(10);
tree.root!.left!.left!.right = Node(3);
tree.root!.right!.left!.right = Node(4);
tree.root!.right!.left!.left = Node(7);
let counter: Int = tree.count_odd_path(tree.root);
// Display calculated result
print("Total Odd path in this tree are : ", counter ," \n", terminator: "");
}
main();``````

#### Output

``Total Odd path in this tree are :  3``

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