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Count number of positive pairs in an array

Here given code implementation process.

/*
    C program for
    Count number of positive pairs in an array 
*/
#include <stdio.h>

// Display array elements
void printArray(int arr[], int n)
{
	for (int i = 0; i < n; ++i)
	{
		printf(" %d", arr[i]);
	}
}
void positivePairs(int arr[], int n)
{
	if (n <= 0)
	{
		return;
	}
	int count = 0;
	// Outer loop from 0...n
	for (int i = 0; i < n; ++i)
	{
		// Inner loop from i+1...n
		for (int j = i + 1; j < n; ++j)
		{
			if (arr[i] + arr[j] > 0)
			{
				// When pair sum is positive
				count++;
			}
		}
	}
	// Display given array
	printf("\n Given array : ");
	printArray(arr, n);
	// Display calculated result
	printf("\n Number of positive pairs is : %d", count);
}
int main(int argc, char
	const *argv[])
{
	int arr1[] = {
		1 , 2 , -3 , -2 , 1 , 3
	};
	int arr2[] = {
		3 , -2 , 4 , -1
	};
	int arr3[] = {
		1 , 2 , 1
	};
	int arr4[] = {
		1 , -2 , -1
	};
	// Test A
	int n = sizeof(arr1) / sizeof(arr1[0]);
	/*
	    arr = [ 1,  2, -3, -2, 1, 3 ]
	    ----------------------------------
	    (1,2)(1,1)(1,3)
	    (2,1)(2,3)(-2,3)
	    (1,3)
	    -----------------------
	    Positive pairs : 7
	*/
	positivePairs(arr1, n);
	// Test B
	n = sizeof(arr2) / sizeof(arr2[0]);
	/*
	    arr = [3, -2, 4, - 1]
	    ---------------------------------
	    (3,-2)(3,4)(3,-1)
	    (-2,4)(4,-1)
	    -----------------------
	    Positive pairs : 5
	*/
	positivePairs(arr2, n);
	// Test C
	n = sizeof(arr3) / sizeof(arr3[0]);
	/*
	    arr = [1, 2, 1]
	    ----------------
	    (1,2)(1,1)(2,1)
	    -------------------
	    Positive pairs : 3
	*/
	positivePairs(arr3, n);
	// Test D
	n = sizeof(arr4) / sizeof(arr4[0]);
	/*
	    arr = [1, -2, -1]
	    ----------------
	    None
	    -------------------
	    Positive pairs : 0
	*/
	positivePairs(arr4, n);
	return 0;
}

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
// Java program for
// Count number of positive pairs in an array 
public class Pairs
{
	// Display array elements
	public void printArray(int[] arr, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			System.out.print(" " + arr[i]);
		}
	}
	public void positivePairs(int[] arr, int n)
	{
		if (n <= 0)
		{
			return;
		}
		int count = 0;
		// Outer loop from 0...n
		for (int i = 0; i < n; ++i)
		{
			// Inner loop from i+1...n
			for (int j = i + 1; j < n; ++j)
			{
				if (arr[i] + arr[j] > 0)
				{
					// When pair sum is positive
					count++;
				}
			}
		}
		// Display given array
		System.out.print("\n Given array : ");
		printArray(arr, n);
		// Display calculated result
		System.out.print("\n Number of positive pairs is : " + count);
	}
	public static void main(String[] args)
	{
		Pairs task = new Pairs();
		int[] arr1 = {
			1 , 2 , -3 , -2 , 1 , 3
		};
		int[] arr2 = {
			3 , -2 , 4 , -1
		};
		int[] arr3 = {
			1 , 2 , 1
		};
		int[] arr4 = {
			1 , -2 , -1
		};
		// Test A
		int n = arr1.length;
		/*
		    arr = [ 1,  2, -3, -2, 1, 3 ]
		    ----------------------------------
		    (1,2)(1,1)(1,3)
		    (2,1)(2,3)(-2,3)
		    (1,3)
		    -----------------------
		    Positive pairs : 7
		*/
		task.positivePairs(arr1, n);
		// Test B
		n = arr2.length;
		/*
		    arr = [3, -2, 4, - 1]
		    ---------------------------------
		    (3,-2)(3,4)(3,-1)
		    (-2,4)(4,-1)
		    -----------------------
		    Positive pairs : 5
		*/
		task.positivePairs(arr2, n);
		// Test C
		n = arr3.length;
		/*
		    arr = [1, 2, 1]
		    ----------------
		    (1,2)(1,1)(2,1)
		    -------------------
		    Positive pairs : 3
		*/
		task.positivePairs(arr3, n);
		// Test D
		n = arr4.length;
		/*
		    arr = [1, -2, -1]
		    ----------------
		    None
		    -------------------
		    Positive pairs : 0
		*/
		task.positivePairs(arr4, n);
	}
}

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
// Include header file
#include <iostream>

using namespace std;
// C++ program for
// Count number of positive pairs in an array
class Pairs
{
	public:
		// Display array elements
		void printArray(int arr[], int n)
		{
			for (int i = 0; i < n; ++i)
			{
				cout << " " << arr[i];
			}
		}
	void positivePairs(int arr[], int n)
	{
		if (n <= 0)
		{
			return;
		}
		int count = 0;
		// Outer loop from 0...n
		for (int i = 0; i < n; ++i)
		{
			// Inner loop from i+1...n
			for (int j = i + 1; j < n; ++j)
			{
				if (arr[i] + arr[j] > 0)
				{
					// When pair sum is positive
					count++;
				}
			}
		}
		// Display given array
		cout << "\n Given array : ";
		this->printArray(arr, n);
		// Display calculated result
		cout << "\n Number of positive pairs is : " << count;
	}
};
int main()
{
	Pairs *task = new Pairs();
	int arr1[] = {
		1 , 2 , -3 , -2 , 1 , 3
	};
	int arr2[] = {
		3 , -2 , 4 , -1
	};
	int arr3[] = {
		1 , 2 , 1
	};
	int arr4[] = {
		1 , -2 , -1
	};
	// Test A
	int n = sizeof(arr1) / sizeof(arr1[0]);
	/*
	    arr = [ 1,  2, -3, -2, 1, 3 ]
	    ----------------------------------
	    (1,2)(1,1)(1,3)
	    (2,1)(2,3)(-2,3)
	    (1,3)
	    -----------------------
	    Positive pairs : 7
	*/
	task->positivePairs(arr1, n);
	// Test B
	n = sizeof(arr2) / sizeof(arr2[0]);
	/*
	    arr = [3, -2, 4, - 1]
	    ---------------------------------
	    (3,-2)(3,4)(3,-1)
	    (-2,4)(4,-1)
	    -----------------------
	    Positive pairs : 5
	*/
	task->positivePairs(arr2, n);
	// Test C
	n = sizeof(arr3) / sizeof(arr3[0]);
	/*
	    arr = [1, 2, 1]
	    ----------------
	    (1,2)(1,1)(2,1)
	    -------------------
	    Positive pairs : 3
	*/
	task->positivePairs(arr3, n);
	// Test D
	n = sizeof(arr4) / sizeof(arr4[0]);
	/*
	    arr = [1, -2, -1]
	    ----------------
	    None
	    -------------------
	    Positive pairs : 0
	*/
	task->positivePairs(arr4, n);
	return 0;
}

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
// Include namespace system
using System;
// Csharp program for
// Count number of positive pairs in an array
public class Pairs
{
	// Display array elements
	public void printArray(int[] arr, int n)
	{
		for (int i = 0; i < n; ++i)
		{
			Console.Write(" " + arr[i]);
		}
	}
	public void positivePairs(int[] arr, int n)
	{
		if (n <= 0)
		{
			return;
		}
		int count = 0;
		// Outer loop from 0...n
		for (int i = 0; i < n; ++i)
		{
			// Inner loop from i+1...n
			for (int j = i + 1; j < n; ++j)
			{
				if (arr[i] + arr[j] > 0)
				{
					// When pair sum is positive
					count++;
				}
			}
		}
		// Display given array
		Console.Write("\n Given array : ");
		this.printArray(arr, n);
		// Display calculated result
		Console.Write("\n Number of positive pairs is : " + count);
	}
	public static void Main(String[] args)
	{
		Pairs task = new Pairs();
		int[] arr1 = {
			1 , 2 , -3 , -2 , 1 , 3
		};
		int[] arr2 = {
			3 , -2 , 4 , -1
		};
		int[] arr3 = {
			1 , 2 , 1
		};
		int[] arr4 = {
			1 , -2 , -1
		};
		// Test A
		int n = arr1.Length;
		/*
		    arr = [ 1,  2, -3, -2, 1, 3 ]
		    ----------------------------------
		    (1,2)(1,1)(1,3)
		    (2,1)(2,3)(-2,3)
		    (1,3)
		    -----------------------
		    Positive pairs : 7
		*/
		task.positivePairs(arr1, n);
		// Test B
		n = arr2.Length;
		/*
		    arr = [3, -2, 4, - 1]
		    ---------------------------------
		    (3,-2)(3,4)(3,-1)
		    (-2,4)(4,-1)
		    -----------------------
		    Positive pairs : 5
		*/
		task.positivePairs(arr2, n);
		// Test C
		n = arr3.Length;
		/*
		    arr = [1, 2, 1]
		    ----------------
		    (1,2)(1,1)(2,1)
		    -------------------
		    Positive pairs : 3
		*/
		task.positivePairs(arr3, n);
		// Test D
		n = arr4.Length;
		/*
		    arr = [1, -2, -1]
		    ----------------
		    None
		    -------------------
		    Positive pairs : 0
		*/
		task.positivePairs(arr4, n);
	}
}

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
package main
import "fmt"
// Go program for
// Count number of positive pairs in an array

// Display array elements
func printArray(arr[] int, n int) {
	for i := 0 ; i < n ; i++ {
		fmt.Print(" ", arr[i])
	}
}
func positivePairs(arr[] int, n int) {
	if n <= 0 {
		return
	}
	var count int = 0
	// Outer loop from 0...n
	for i := 0 ; i < n ; i++ {
		// Inner loop from i+1...n
		for j := i + 1 ; j < n ; j++ {
			if arr[i] + arr[j] > 0 {
				// When pair sum is positive
				count++
			}
		}
	}
	// Display given array
	fmt.Print("\n Given array : ")
	printArray(arr, n)
	// Display calculated result
	fmt.Print("\n Number of positive pairs is : ", count)
}
func main() {
	
	var arr1 = [] int {1,  2, -3, -2, 1, 3 }
	var arr2 = [] int {3, -2, 4, - 1}
	var arr3 = [] int {1, 2, 1}
	var arr4 = [] int {1, -2, -1}
	// Test A
	var n int = len(arr1)
	/*
	    arr = [ 1,  2, -3, -2, 1, 3 ]
	    ----------------------------------
	    (1,2)(1,1)(1,3)
	    (2,1)(2,3)(-2,3)
	    (1,3)
	    -----------------------
	    Positive pairs : 7
	*/
	positivePairs(arr1, n)
	// Test B
	n = len(arr2)
	/*
	    arr = [3, -2, 4, - 1]
	    ---------------------------------
	    (3,-2)(3,4)(3,-1)
	    (-2,4)(4,-1)
	    -----------------------
	    Positive pairs : 5
	*/
	positivePairs(arr2, n)
	// Test C
	n = len(arr3)
	/*
	    arr = [1, 2, 1]
	    ----------------
	    (1,2)(1,1)(2,1)
	    -------------------
	    Positive pairs : 3
	*/
	positivePairs(arr3, n)
	// Test D
	n = len(arr4)
	/*
	    arr = [1, -2, -1]
	    ----------------
	    None
	    -------------------
	    Positive pairs : 0
	*/
	positivePairs(arr4, n)
}

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
<?php
// Php program for
// Count number of positive pairs in an array
class Pairs
{
	// Display array elements
	public function printArray($arr, $n)
	{
		for ($i = 0; $i < $n; ++$i)
		{
			echo(" ".$arr[$i]);
		}
	}
	public function positivePairs($arr, $n)
	{
		if ($n <= 0)
		{
			return;
		}
		$count = 0;
		// Outer loop from 0...n
		for ($i = 0; $i < $n; ++$i)
		{
			// Inner loop from i+1...n
			for ($j = $i + 1; $j < $n; ++$j)
			{
				if ($arr[$i] + $arr[$j] > 0)
				{
					// When pair sum is positive
					$count++;
				}
			}
		}
		// Display given array
		echo("\n Given array : ");
		$this->printArray($arr, $n);
		// Display calculated result
		echo("\n Number of positive pairs is : ".$count);
	}
}

function main()
{
	$task = new Pairs();
	$arr1 = array(1, 2, -3, -2, 1, 3);
	$arr2 = array(3, -2, 4, -1);
	$arr3 = array(1, 2, 1);
	$arr4 = array(1, -2, -1);
	// Test A
	$n = count($arr1);
	/*
	    arr = [ 1,  2, -3, -2, 1, 3 ]
	    ----------------------------------
	    (1,2)(1,1)(1,3)
	    (2,1)(2,3)(-2,3)
	    (1,3)
	    -----------------------
	    Positive pairs : 7
	*/
	$task->positivePairs($arr1, $n);
	// Test B
	$n = count($arr2);
	/*
	    arr = [3, -2, 4, - 1]
	    ---------------------------------
	    (3,-2)(3,4)(3,-1)
	    (-2,4)(4,-1)
	    -----------------------
	    Positive pairs : 5
	*/
	$task->positivePairs($arr2, $n);
	// Test C
	$n = count($arr3);
	/*
	    arr = [1, 2, 1]
	    ----------------
	    (1,2)(1,1)(2,1)
	    -------------------
	    Positive pairs : 3
	*/
	$task->positivePairs($arr3, $n);
	// Test D
	$n = count($arr4);
	/*
	    arr = [1, -2, -1]
	    ----------------
	    None
	    -------------------
	    Positive pairs : 0
	*/
	$task->positivePairs($arr4, $n);
}
main();

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
// Node JS program for
// Count number of positive pairs in an array
class Pairs
{
	// Display array elements
	printArray(arr, n)
	{
		for (var i = 0; i < n; ++i)
		{
			process.stdout.write(" " + arr[i]);
		}
	}
	positivePairs(arr, n)
	{
		if (n <= 0)
		{
			return;
		}
		var count = 0;
		// Outer loop from 0...n
		for (var i = 0; i < n; ++i)
		{
			// Inner loop from i+1...n
			for (var j = i + 1; j < n; ++j)
			{
				if (arr[i] + arr[j] > 0)
				{
					// When pair sum is positive
					count++;
				}
			}
		}
		// Display given array
		process.stdout.write("\n Given array : ");
		this.printArray(arr, n);
		// Display calculated result
		process.stdout.write("\n Number of positive pairs is : " + count);
	}
}

function main()
{
	var task = new Pairs();
	var arr1 = [1, 2, -3, -2, 1, 3];
	var arr2 = [3, -2, 4, -1];
	var arr3 = [1, 2, 1];
	var arr4 = [1, -2, -1];
	// Test A
	var n = arr1.length;
	/*
	    arr = [ 1,  2, -3, -2, 1, 3 ]
	    ----------------------------------
	    (1,2)(1,1)(1,3)
	    (2,1)(2,3)(-2,3)
	    (1,3)
	    -----------------------
	    Positive pairs : 7
	*/
	task.positivePairs(arr1, n);
	// Test B
	n = arr2.length;
	/*
	    arr = [3, -2, 4, - 1]
	    ---------------------------------
	    (3,-2)(3,4)(3,-1)
	    (-2,4)(4,-1)
	    -----------------------
	    Positive pairs : 5
	*/
	task.positivePairs(arr2, n);
	// Test C
	n = arr3.length;
	/*
	    arr = [1, 2, 1]
	    ----------------
	    (1,2)(1,1)(2,1)
	    -------------------
	    Positive pairs : 3
	*/
	task.positivePairs(arr3, n);
	// Test D
	n = arr4.length;
	/*
	    arr = [1, -2, -1]
	    ----------------
	    None
	    -------------------
	    Positive pairs : 0
	*/
	task.positivePairs(arr4, n);
}
main();

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
#  Python 3 program for
#  Count number of positive pairs in an array
class Pairs :
	#  Display list elements
	def printArray(self, arr, n) :
		i = 0
		while (i < n) :
			print(" ", arr[i], end = "")
			i += 1
		
	
	def positivePairs(self, arr, n) :
		if (n <= 0) :
			return
		
		count = 0
		i = 0
		#  Outer loop from 0...n
		while (i < n) :
			j = i + 1
			#  Inner loop from i+1...n
			while (j < n) :
				if (arr[i] + arr[j] > 0) :
					#  When pair sum is positive
					count += 1
				
				j += 1
			
			i += 1
		
		#  Display given list
		print("\n Given array : ", end = "")
		self.printArray(arr, n)
		#  Display calculated result
		print("\n Number of positive pairs is : ", count, end = "")
	

def main() :
	task = Pairs()
	arr1 = [1, 2, -3, -2, 1, 3]
	arr2 = [3, -2, 4, -1]
	arr3 = [1, 2, 1]
	arr4 = [1, -2, -1]
	#  Test A
	n = len(arr1)
	#    arr = [ 1,  2, -3, -2, 1, 3 ]
	#    ----------------------------------
	#    (1,2)(1,1)(1,3)
	#    (2,1)(2,3)(-2,3)
	#    (1,3)
	#    -----------------------
	#    Positive pairs : 7
	task.positivePairs(arr1, n)
	#  Test B
	n = len(arr2)
	#    arr = [3, -2, 4, - 1]
	#    ---------------------------------
	#    (3,-2)(3,4)(3,-1)
	#    (-2,4)(4,-1)
	#    -----------------------
	#    Positive pairs : 5
	task.positivePairs(arr2, n)
	#  Test C
	n = len(arr3)
	#    arr = [1, 2, 1]
	#    ----------------
	#    (1,2)(1,1)(2,1)
	#    -------------------
	#    Positive pairs : 3
	task.positivePairs(arr3, n)
	#  Test D
	n = len(arr4)
	#    arr = [1, -2, -1]
	#    ----------------
	#    None
	#    -------------------
	#    Positive pairs : 0
	task.positivePairs(arr4, n)

if __name__ == "__main__": main()

Output

 Given array :   1  2  -3  -2  1  3
 Number of positive pairs is :  7
 Given array :   3  -2  4  -1
 Number of positive pairs is :  5
 Given array :   1  2  1
 Number of positive pairs is :  3
 Given array :   1  -2  -1
 Number of positive pairs is :  0
#  Ruby program for
#  Count number of positive pairs in an array
class Pairs 
	#  Display array elements
	def printArray(arr, n) 
		i = 0
		while (i < n) 
			print(" ", arr[i])
			i += 1
		end

	end

	def positivePairs(arr, n) 
		if (n <= 0) 
			return
		end

		count = 0
		i = 0
		#  Outer loop from 0...n
		while (i < n) 
			j = i + 1
			#  Inner loop from i+1...n
			while (j < n) 
				if (arr[i] + arr[j] > 0) 
					#  When pair sum is positive
					count += 1
				end

				j += 1
			end

			i += 1
		end

		#  Display given array
		print("\n Given array : ")
		self.printArray(arr, n)
		#  Display calculated result
		print("\n Number of positive pairs is : ", count)
	end

end

def main() 
	task = Pairs.new()
	arr1 = [1, 2, -3, -2, 1, 3]
	arr2 = [3, -2, 4, -1]
	arr3 = [1, 2, 1]
	arr4 = [1, -2, -1]
	#  Test A
	n = arr1.length
	#    arr = [ 1,  2, -3, -2, 1, 3 ]
	#    ----------------------------------
	#    (1,2)(1,1)(1,3)
	#    (2,1)(2,3)(-2,3)
	#    (1,3)
	#    -----------------------
	#    Positive pairs : 7
	task.positivePairs(arr1, n)
	#  Test B
	n = arr2.length
	#    arr = [3, -2, 4, - 1]
	#    ---------------------------------
	#    (3,-2)(3,4)(3,-1)
	#    (-2,4)(4,-1)
	#    -----------------------
	#    Positive pairs : 5
	task.positivePairs(arr2, n)
	#  Test C
	n = arr3.length
	#    arr = [1, 2, 1]
	#    ----------------
	#    (1,2)(1,1)(2,1)
	#    -------------------
	#    Positive pairs : 3
	task.positivePairs(arr3, n)
	#  Test D
	n = arr4.length
	#    arr = [1, -2, -1]
	#    ----------------
	#    None
	#    -------------------
	#    Positive pairs : 0
	task.positivePairs(arr4, n)
end

main()

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
// Scala program for
// Count number of positive pairs in an array
class Pairs()
{
	// Display array elements
	def printArray(arr: Array[Int], n: Int): Unit = {
		var i: Int = 0;
		while (i < n)
		{
			print(" " + arr(i));
			i += 1;
		}
	}
	def positivePairs(arr: Array[Int], n: Int): Unit = {
		if (n <= 0)
		{
			return;
		}
		var count: Int = 0;
		var i: Int = 0;
		// Outer loop from 0...n
		while (i < n)
		{
			var j: Int = i + 1;
			// Inner loop from i+1...n
			while (j < n)
			{
				if (arr(i) + arr(j) > 0)
				{
					// When pair sum is positive
					count += 1;
				}
				j += 1;
			}
			i += 1;
		}
		// Display given array
		print("\n Given array : ");
		printArray(arr, n);
		// Display calculated result
		print("\n Number of positive pairs is : " + count);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Pairs = new Pairs();
		var arr1: Array[Int] = Array(1, 2, -3, -2, 1, 3);
		var arr2: Array[Int] = Array(3, -2, 4, -1);
		var arr3: Array[Int] = Array(1, 2, 1);
		var arr4: Array[Int] = Array(1, -2, -1);
		// Test A
		var n: Int = arr1.length;
		/*
		    arr = [ 1,  2, -3, -2, 1, 3 ]
		    ----------------------------------
		    (1,2)(1,1)(1,3)
		    (2,1)(2,3)(-2,3)
		    (1,3)
		    -----------------------
		    Positive pairs : 7
		*/
		task.positivePairs(arr1, n);
		// Test B
		n = arr2.length;
		/*
		    arr = [3, -2, 4, - 1]
		    ---------------------------------
		    (3,-2)(3,4)(3,-1)
		    (-2,4)(4,-1)
		    -----------------------
		    Positive pairs : 5
		*/
		task.positivePairs(arr2, n);
		// Test C
		n = arr3.length;
		/*
		    arr = [1, 2, 1]
		    ----------------
		    (1,2)(1,1)(2,1)
		    -------------------
		    Positive pairs : 3
		*/
		task.positivePairs(arr3, n);
		// Test D
		n = arr4.length;
		/*
		    arr = [1, -2, -1]
		    ----------------
		    None
		    -------------------
		    Positive pairs : 0
		*/
		task.positivePairs(arr4, n);
	}
}

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
import Foundation;
// Swift 4 program for
// Count number of positive pairs in an array
class Pairs
{
	// Display array elements
	func printArray(_ arr: [Int], _ n: Int)
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" ", arr[i], terminator: "");
			i += 1;
		}
	}
	func positivePairs(_ arr: [Int], _ n: Int)
	{
		if (n <= 0)
		{
			return;
		}
		var count: Int = 0;
		var i: Int = 0;
		// Outer loop from 0...n
		while (i < n)
		{
			var j: Int = i + 1;
			// Inner loop from i+1...n
			while (j < n)
			{
				if (arr[i] + arr[j] > 0)
				{
					// When pair sum is positive
					count += 1;
				}
				j += 1;
			}
			i += 1;
		}
		// Display given array
		print("\n Given array : ", terminator: "");
		self.printArray(arr, n);
		// Display calculated result
		print("\n Number of positive pairs is : ", count, terminator: "");
	}
}
func main()
{
	let task: Pairs = Pairs();
	let arr1: [Int] = [1, 2, -3, -2, 1, 3];
	let arr2: [Int] = [3, -2, 4, -1];
	let arr3: [Int] = [1, 2, 1];
	let arr4: [Int] = [1, -2, -1];
	// Test A
	var n: Int = arr1.count;
	/*
	    arr = [ 1,  2, -3, -2, 1, 3 ]
	    ----------------------------------
	    (1,2)(1,1)(1,3)
	    (2,1)(2,3)(-2,3)
	    (1,3)
	    -----------------------
	    Positive pairs : 7
	*/
	task.positivePairs(arr1, n);
	// Test B
	n = arr2.count;
	/*
	    arr = [3, -2, 4, - 1]
	    ---------------------------------
	    (3,-2)(3,4)(3,-1)
	    (-2,4)(4,-1)
	    -----------------------
	    Positive pairs : 5
	*/
	task.positivePairs(arr2, n);
	// Test C
	n = arr3.count;
	/*
	    arr = [1, 2, 1]
	    ----------------
	    (1,2)(1,1)(2,1)
	    -------------------
	    Positive pairs : 3
	*/
	task.positivePairs(arr3, n);
	// Test D
	n = arr4.count;
	/*
	    arr = [1, -2, -1]
	    ----------------
	    None
	    -------------------
	    Positive pairs : 0
	*/
	task.positivePairs(arr4, n);
}
main();

Output

 Given array :   1  2  -3  -2  1  3
 Number of positive pairs is :  7
 Given array :   3  -2  4  -1
 Number of positive pairs is :  5
 Given array :   1  2  1
 Number of positive pairs is :  3
 Given array :   1  -2  -1
 Number of positive pairs is :  0
// Kotlin program for
// Count number of positive pairs in an array
class Pairs
{
	// Display array elements
	fun printArray(arr: Array < Int > , n: Int): Unit
	{
		var i: Int = 0;
		while (i < n)
		{
			print(" " + arr[i]);
			i += 1;
		}
	}
	fun positivePairs(arr: Array < Int > , n: Int): Unit
	{
		if (n <= 0)
		{
			return;
		}
		var count: Int = 0;
		var i: Int = 0;
		// Outer loop from 0...n
		while (i < n)
		{
			var j: Int = i + 1;
			// Inner loop from i+1...n
			while (j < n)
			{
				if (arr[i] + arr[j] > 0)
				{
					// When pair sum is positive
					count += 1;
				}
				j += 1;
			}
			i += 1;
		}
		// Display given array
		print("\n Given array : ");
		this.printArray(arr, n);
		// Display calculated result
		print("\n Number of positive pairs is : " + count);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: Pairs = Pairs();
	val arr1: Array < Int > = arrayOf(1, 2, -3, -2, 1, 3);
	val arr2: Array < Int > = arrayOf(3, -2, 4, -1);
	val arr3: Array < Int > = arrayOf(1, 2, 1);
	val arr4: Array < Int > = arrayOf(1, -2, -1);
	// Test A
	var n: Int = arr1.count();
	/*
	    arr = [ 1,  2, -3, -2, 1, 3 ]
	    ----------------------------------
	    (1,2)(1,1)(1,3)
	    (2,1)(2,3)(-2,3)
	    (1,3)
	    -----------------------
	    Positive pairs : 7
	*/
	task.positivePairs(arr1, n);
	// Test B
	n = arr2.count();
	/*
	    arr = [3, -2, 4, - 1]
	    ---------------------------------
	    (3,-2)(3,4)(3,-1)
	    (-2,4)(4,-1)
	    -----------------------
	    Positive pairs : 5
	*/
	task.positivePairs(arr2, n);
	// Test C
	n = arr3.count();
	/*
	    arr = [1, 2, 1]
	    ----------------
	    (1,2)(1,1)(2,1)
	    -------------------
	    Positive pairs : 3
	*/
	task.positivePairs(arr3, n);
	// Test D
	n = arr4.count();
	/*
	    arr = [1, -2, -1]
	    ----------------
	    None
	    -------------------
	    Positive pairs : 0
	*/
	task.positivePairs(arr4, n);
}

Output

 Given array :  1 2 -3 -2 1 3
 Number of positive pairs is : 7
 Given array :  3 -2 4 -1
 Number of positive pairs is : 5
 Given array :  1 2 1
 Number of positive pairs is : 3
 Given array :  1 -2 -1
 Number of positive pairs is : 0
Last updated on by Kalkicode




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