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Count the number of array elements whose digit sum are equal to K

Here given code implementation process.

// C Program for
// Count the number of array elements whose digit sum are equal to K
#include <stdio.h>

int digitSum(int number)
{
	int n = number;
	if (n < 0)
	{
		// Convert negative number to positive number
		n = -n;
	}
	int result = 0;
	while (n != 0)
	{
		// Adding last digit of a given number
		result = result + (n % 10);
		// Remove last digit
		n = n / 10;
	}
	return result;
}
void countKDigitSum(int arr[], int n, int k)
{
	int count = 0;
	for (int i = 0; i < n; ++i)
	{
		if (digitSum(arr[i]) == k)
		{
			// Increase counter
			count++;
		}
	}
	printf("\n %d", count);
}
int main()
{
	int arr[] = {
		17 , 123 , 16 , 60 , 11 , 23 , 42
	};
	// Get the number of elements
	int n = sizeof(arr) / sizeof(arr[0]);
	// k = 6
	// ----------
	// 1 + 2 + 3 = 6
	// 6 + 0   = 6
	// 4 + 2   = 4
	// [123,60,42]
	// Result = 3
	countKDigitSum(arr, n, 6);
	return 0;
}

Output

 3
/*
    Java program for
    Count the number of array elements whose digit sum are equal to K
*/
public class Counting
{
	public int digitSum(int number)
	{
		int n = number;
		if (n < 0)
		{
			// Convert negative number to positive number
			n = -n;
		}
		int result = 0;
		while (n != 0)
		{
			// Adding last digit of a given number
			result = result + (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	public void countKDigitSum(int[] arr, int n, int k)
	{
		int count = 0;
		for (int i = 0; i < n; ++i)
		{
			if (digitSum(arr[i]) == k)
			{
				// Increase counter
				count++;
			}
		}
		System.out.print("\n " + count);
	}
	public static void main(String[] args)
	{
		Counting task = new Counting();
		int[] arr = {
			17 , 123 , 16 , 60 , 11 , 23 , 42
		};
		// Get the number of elements
		int n = arr.length;
		// k = 6
		// ----------
		// 1 + 2 + 3 = 6
		// 6 + 0   = 6
		// 4 + 2   = 4
		// [123,60,42]
		// Result = 3
		task.countKDigitSum(arr, n, 6);
	}
}

Output

 3
// Include header file
#include <iostream>
using namespace std;
/*
    C++ program for
    Count the number of array elements whose digit sum are equal to K
*/
class Counting
{
	public: int digitSum(int number)
	{
		int n = number;
		if (n < 0)
		{
			// Convert negative number to positive number
			n = -n;
		}
		int result = 0;
		while (n != 0)
		{
			// Adding last digit of a given number
			result = result + (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	void countKDigitSum(int arr[], int n, int k)
	{
		int count = 0;
		for (int i = 0; i < n; ++i)
		{
			if (this->digitSum(arr[i]) == k)
			{
				// Increase counter
				count++;
			}
		}
		cout << "\n " << count;
	}
};
int main()
{
	Counting *task = new Counting();
	int arr[] = {
		17 , 123 , 16 , 60 , 11 , 23 , 42
	};
	// Get the number of elements
	int n = sizeof(arr) / sizeof(arr[0]);
	// k = 6
	// ----------
	// 1 + 2 + 3 = 6
	// 6 + 0   = 6
	// 4 + 2   = 4
	// [123,60,42]
	// Result = 3
	task->countKDigitSum(arr, n, 6);
	return 0;
}

Output

 3
// Include namespace system
using System;
/*
    Csharp program for
    Count the number of array elements whose digit sum are equal to K
*/
public class Counting
{
	public int digitSum(int number)
	{
		int n = number;
		if (n < 0)
		{
			// Convert negative number to positive number
			n = -n;
		}
		int result = 0;
		while (n != 0)
		{
			// Adding last digit of a given number
			result = result + (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	public void countKDigitSum(int[] arr, int n, int k)
	{
		int count = 0;
		for (int i = 0; i < n; ++i)
		{
			if (this.digitSum(arr[i]) == k)
			{
				// Increase counter
				count++;
			}
		}
		Console.Write("\n " + count);
	}
	public static void Main(String[] args)
	{
		Counting task = new Counting();
		int[] arr = {
			17 , 123 , 16 , 60 , 11 , 23 , 42
		};
		// Get the number of elements
		int n = arr.Length;
		// k = 6
		// ----------
		// 1 + 2 + 3 = 6
		// 6 + 0   = 6
		// 4 + 2   = 4
		// [123,60,42]
		// Result = 3
		task.countKDigitSum(arr, n, 6);
	}
}

Output

 3
package main
import "fmt"
/*
    Go program for
    Count the number of array elements whose digit sum are equal to K
*/
func digitSum(number int) int {
	var n int = number
	if n < 0 {
		// Convert negative number to positive number
		n = -n
	}
	var result int = 0
	for (n != 0) {
		// Adding last digit of a given number
		result = result + (n % 10)
		// Remove last digit
		n = n / 10
	}
	return result
}
func countKDigitSum(arr[] int, n int, k int) {
	var count int = 0
	for i := 0 ; i < n ; i++ {
		if digitSum(arr[i]) == k {
			// Increase counter
			count++
		}
	}
	fmt.Print("\n ", count)
}
func main() {

	var arr = [] int {17 , 123 , 16 , 60 , 11 , 23 , 42}
	// Get the number of elements
	var n int = len(arr)
	// k = 6
	// ----------
	// 1 + 2 + 3 = 6
	// 6 + 0   = 6
	// 4 + 2   = 4
	// [123,60,42]
	// Result = 3
	countKDigitSum(arr, n, 6)
}

Output

 3
<?php
/*
    Php program for
    Count the number of array elements whose digit sum are equal to K
*/
class Counting
{
	public	function digitSum($number)
	{
		$n = $number;
		if ($n < 0)
		{
			// Convert negative number to positive number
			$n = -$n;
		}
		$result = 0;
		while ($n != 0)
		{
			// Adding last digit of a given number
			$result = $result + ($n % 10);
			// Remove last digit
			$n = (int)($n / 10);
		}
		return $result;
	}
	public	function countKDigitSum($arr, $n, $k)
	{
		$count = 0;
		for ($i = 0; $i < $n; ++$i)
		{
			if ($this->digitSum($arr[$i]) == $k)
			{
				// Increase counter
				$count++;
			}
		}
		echo("\n ".$count);
	}
}

function main()
{
	$task = new Counting();
	$arr = array(17, 123, 16, 60, 11, 23, 42);
	// Get the number of elements
	$n = count($arr);
	// k = 6
	// ----------
	// 1 + 2 + 3 = 6
	// 6 + 0   = 6
	// 4 + 2   = 4
	// [123,60,42]
	// Result = 3
	$task->countKDigitSum($arr, $n, 6);
}
main();

Output

 3
/*
    Node JS program for
    Count the number of array elements whose digit sum are equal to K
*/
class Counting
{
	digitSum(number)
	{
		var n = number;
		if (n < 0)
		{
			// Convert negative number to positive number
			n = -n;
		}
		var result = 0;
		while (n != 0)
		{
			// Adding last digit of a given number
			result = result + (n % 10);
			// Remove last digit
			n = parseInt(n / 10);
		}
		return result;
	}
	countKDigitSum(arr, n, k)
	{
		var count = 0;
		for (var i = 0; i < n; ++i)
		{
			if (this.digitSum(arr[i]) == k)
			{
				// Increase counter
				count++;
			}
		}
		process.stdout.write("\n " + count);
	}
}

function main()
{
	var task = new Counting();
	var arr = [17, 123, 16, 60, 11, 23, 42];
	// Get the number of elements
	var n = arr.length;
	// k = 6
	// ----------
	// 1 + 2 + 3 = 6
	// 6 + 0   = 6
	// 4 + 2   = 4
	// [123,60,42]
	// Result = 3
	task.countKDigitSum(arr, n, 6);
}
main();

Output

 3
#    Python 3 program for
#    Count the number of array elements whose digit sum are equal to K
class Counting :
	def digitSum(self, number) :
		n = number
		if (n < 0) :
			#  Convert negative number to positive number
			n = -n
		
		result = 0
		while (n != 0) :
			#  Adding last digit of a given number
			result = result + (n % 10)
			#  Remove last digit
			n = int(n / 10)
		
		return result
	
	def countKDigitSum(self, arr, n, k) :
		count = 0
		i = 0
		while (i < n) :
			if (self.digitSum(arr[i]) == k) :
				#  Increase counter
				count += 1
			
			i += 1
		
		print("\n ", count, end = "")
	

def main() :
	task = Counting()
	arr = [17, 123, 16, 60, 11, 23, 42]
	#  Get the number of elements
	n = len(arr)
	#  k = 6
	#  ----------
	#  1 + 2 + 3 = 6
	#  6 + 0   = 6
	#  4 + 2   = 4
	#  [123,60,42]
	#  Result = 3
	task.countKDigitSum(arr, n, 6)

if __name__ == "__main__": main()

Output

  3
#    Ruby program for
#    Count the number of array elements whose digit sum are equal to K
class Counting 
	def digitSum(number) 
		n = number
		if (n < 0) 
			#  Convert negative number to positive number
			n = -n
		end

		result = 0
		while (n != 0) 
			#  Adding last digit of a given number
			result = result + (n % 10)
			#  Remove last digit
			n = n / 10
		end

		return result
	end

	def countKDigitSum(arr, n, k) 
		count = 0
		i = 0
		while (i < n) 
			if (self.digitSum(arr[i]) == k) 
				#  Increase counter
				count += 1
			end

			i += 1
		end

		print("\n ", count)
	end

end

def main() 
	task = Counting.new()
	arr = [17, 123, 16, 60, 11, 23, 42]
	#  Get the number of elements
	n = arr.length
	#  k = 6
	#  ----------
	#  1 + 2 + 3 = 6
	#  6 + 0   = 6
	#  4 + 2   = 4
	#  [123,60,42]
	#  Result = 3
	task.countKDigitSum(arr, n, 6)
end

main()

Output

 3
/*
    Scala program for
    Count the number of array elements whose digit sum are equal to K
*/
class Counting()
{
	def digitSum(number: Int): Int = {
		var n: Int = number;
		if (n < 0)
		{
			// Convert negative number to positive number
			n = -n;
		}
		var result: Int = 0;
		while (n != 0)
		{
			// Adding last digit of a given number
			result = result + (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	def countKDigitSum(arr: Array[Int], n: Int, k: Int): Unit = {
		var count: Int = 0;
		var i: Int = 0;
		while (i < n)
		{
			if (digitSum(arr(i)) == k)
			{
				// Increase counter
				count += 1;
			}
			i += 1;
		}
		print("\n " + count);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: Counting = new Counting();
		var arr: Array[Int] = Array(17, 123, 16, 60, 11, 23, 42);
		// Get the number of elements
		var n: Int = arr.length;
		// k = 6
		// ----------
		// 1 + 2 + 3 = 6
		// 6 + 0   = 6
		// 4 + 2   = 4
		// [123,60,42]
		// Result = 3
		task.countKDigitSum(arr, n, 6);
	}
}

Output

 3
import Foundation;
/*
    Swift 4 program for
    Count the number of array elements whose digit sum are equal to K
*/
class Counting
{
	func digitSum(_ number: Int) -> Int
	{
		var n: Int = number;
		if (n < 0)
		{
			// Convert negative number to positive number
			n = -n;
		}
		var result: Int = 0;
		while (n  != 0)
		{
			// Adding last digit of a given number
			result = result + (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	func countKDigitSum(_ arr: [Int], _ n: Int, _ k: Int)
	{
		var count: Int = 0;
		var i: Int = 0;
		while (i < n)
		{
			if (self.digitSum(arr[i]) == k)
			{
				// Increase counter
				count += 1;
			}
			i += 1;
		}
		print("\n ", count, terminator: "");
	}
}
func main()
{
	let task: Counting = Counting();
	let arr: [Int] = [17, 123, 16, 60, 11, 23, 42];
	// Get the number of elements
	let n: Int = arr.count;
	// k = 6
	// ----------
	// 1 + 2 + 3 = 6
	// 6 + 0   = 6
	// 4 + 2   = 4
	// [123,60,42]
	// Result = 3
	task.countKDigitSum(arr, n, 6);
}
main();

Output

  3
/*
    Kotlin program for
    Count the number of array elements whose digit sum are equal to K
*/
class Counting
{
	fun digitSum(number: Int): Int
	{
		var n: Int = number;
		if (n < 0)
		{
			// Convert negative number to positive number
			n = -n;
		}
		var result: Int = 0;
		while (n != 0)
		{
			// Adding last digit of a given number
			result = result + (n % 10);
			// Remove last digit
			n = n / 10;
		}
		return result;
	}
	fun countKDigitSum(arr: Array < Int > , n: Int, k: Int): Unit
	{
		var count: Int = 0;
		var i: Int = 0;
		while (i < n)
		{
			if (this.digitSum(arr[i]) == k)
			{
				// Increase counter
				count += 1;
			}
			i += 1;
		}
		print("\n " + count);
	}
}
fun main(args: Array < String > ): Unit
{
	val task: Counting = Counting();
	val arr: Array < Int > = arrayOf(17, 123, 16, 60, 11, 23, 42);
	// Get the number of elements
	val n: Int = arr.count();
	// k = 6
	// ----------
	// 1 + 2 + 3 = 6
	// 6 + 0   = 6
	// 4 + 2   = 4
	// [123,60,42]
	// Result = 3
	task.countKDigitSum(arr, n, 6);
}

Output

 3
Last updated on by Kalkicode




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