Count frequency of given node in doubly linked list

In a doubly linked list, each node contains a data value and two pointers - one to the previous node and another to the next node in the list.

To count the frequency of a given node in a doubly linked list, you would need to traverse the entire list, comparing the data value of each node with the given value, and incrementing a count variable each time a match is found. The process would involve starting at the head or tail of the list (depending on which direction is more efficient), and then iterating through each node until the end of the list is reached.

Here's an example algorithm in pseudocode:

1. Initialize a count variable to zero.
2. Set a current pointer to the head (or tail) of the list.
3. While the current pointer is not null, do the following: a. If the data value of the current node matches the given value, increment the count. b. Move the current pointer to the next (or previous) node in the list.
4. Return the count variable as the frequency of the given node in the list.

Note that if the given node contains complex data (e.g. an object or struct), you would need to compare the specific attribute of that node rather than the entire node.

Program Solution

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