Count complete odd nodes path of binary tree in php

Php program for Count complete odd nodes path of binary tree. Here more solutions.
<?php
/*
Php program for
Count odd paths in Binary Tree
*/
// Binary Tree node
class TreeNode
{
public $data;
public $left;
public $right;
public function __construct($data)
{
// Set node value
$this->data = $data;
$this->left = NULL;
$this->right = NULL;
}
}
class BinaryTree
{
public $root;
public function __construct()
{
$this->root = NULL;
}
// Count all paths from root to leaf
// which containing all Odd nodes
public function countOddNodePath($node)
{
if ($node == NULL ||
$node->data % 2 == 0)
{
// When tree node is null or
// its contain even value
return 0;
}
else
{
if ($node->left == NULL &&
$node->right == NULL)
{
// When get leaf node And
// path contain all Odd nodes
return 1;
}
return $this->countOddNodePath($node->left) +
$this->countOddNodePath($node->right);
}
}
public static function main()
{
// New of binary tree
$tree = new BinaryTree();
/*
Construct Binary Tree
-----------------------
5
/ \
/ \
3 9
/ \ / \
7 6 1 3
/ \ / \
10 3 7 4
*/
// Add tree node
$tree->root = new TreeNode(5);
$tree->root->left = new TreeNode(3);
$tree->root->right = new TreeNode(9);
$tree->root->right->right = new TreeNode(3);
$tree->root->left->right = new TreeNode(6);
$tree->root->right->left = new TreeNode(1);
$tree->root->left->left = new TreeNode(7);
$tree->root->left->left->left = new TreeNode(10);
$tree->root->left->left->right = new TreeNode(3);
$tree->root->right->left->right = new TreeNode(4);
$tree->root->right->left->left = new TreeNode(7);
/*
Given Binary Tree
-----------------------
5
/ \
/ \
3 9
/ \ / \
7 6 1 3
/ \ / \
10 3 7 4
Here
Odd path from root to leaf
-----------------------
5
/ \
/ \
3 9
/ / \
7 1 3
\ /
3 7
---------------------
5->3->7->3
5->9->1->7
5->9->3
----------------------
Result : 3 [number of path]
*/
// Count odd nodes paths from root
// to leaf in a binary tree.
printf("%d\n", $tree->countOddNodePath($tree->root));
}
}
BinaryTree::main();
Output
3
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