# Count complete odd nodes path of binary tree in golang

Go program for Count complete odd nodes path of binary tree. Here more solutions.

``````package main
import "fmt"
/*
Go program for
Count odd paths in Binary Tree
*/
// Binary Tree node
type TreeNode struct {
data int
left * TreeNode
right * TreeNode
}
func getTreeNode(data int) * TreeNode {
// return new TreeNode
return &TreeNode {
data,
nil,
nil,
}
}
type BinaryTree struct {
root * TreeNode
}
func getBinaryTree() * BinaryTree {
// return new BinaryTree
return &BinaryTree {
nil,
}
}
// Count all paths from root to leaf
// which containing all Odd nodes
func(this BinaryTree) countOddNodePath(node * TreeNode) int {
if node == nil || node.data % 2 == 0 {
// When tree node is null or
// its contain even value
return 0
} else {
if node.left == nil && node.right == nil {
// When get leaf node And
// path contain all Odd nodes
return 1
}
return this.countOddNodePath(node.left) +
this.countOddNodePath(node.right)
}
}
func main() {
// New of binary tree
var tree * BinaryTree = getBinaryTree()
/*
Construct Binary Tree
-----------------------
5
/  \
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/
tree.root = getTreeNode(5)
tree.root.left = getTreeNode(3)
tree.root.right = getTreeNode(9)
tree.root.right.right = getTreeNode(3)
tree.root.left.right = getTreeNode(6)
tree.root.right.left = getTreeNode(1)
tree.root.left.left = getTreeNode(7)
tree.root.left.left.left = getTreeNode(10)
tree.root.left.left.right = getTreeNode(3)
tree.root.right.left.right = getTreeNode(4)
tree.root.right.left.left = getTreeNode(7)
/*
Given Binary Tree
-----------------------
5
/  \
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
Here
Odd path from root to leaf
-----------------------
5
/  \
/    \
3      9
/      / \
7      1   3
\    /
3  7
---------------------
5->3->7->3
5->9->1->7
5->9->3
----------------------
Result : 3 [number of path]
*/
// Count odd nodes paths from root
// to leaf in a binary tree.
fmt.Println(tree.countOddNodePath(tree.root))
}``````

Output

``3``

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