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Code Binary Tree

# Count complete odd nodes path of binary tree in c++

C++ program for Count complete odd nodes path of binary tree. Here more solutions.

``````// Include header file
#include <iostream>
using namespace std;
/*
C++ program for
Count odd paths in Binary Tree
*/
// Binary Tree node
class TreeNode
{
public:
int data;
TreeNode *left;
TreeNode *right;
TreeNode(int data)
{
// Set node value
this->data = data;
this->left = nullptr;
this->right = nullptr;
}
};
class BinaryTree
{
public:
TreeNode *root;
BinaryTree()
{
this->root = nullptr;
}
// Count all paths from root to leaf
// which containing all Odd nodes
int countOddNodePath(TreeNode *node)
{
if (node == nullptr ||
node->data % 2 == 0)
{
// When tree node is null or
// its contain even value
return 0;
}
else
{
if (node->left == nullptr &&
node->right == nullptr)
{
// When get leaf node And
// path contain all Odd nodes
return 1;
}
return this->countOddNodePath(node->left) +
this->countOddNodePath(node->right);
}
}
};
int main()
{
// New of binary tree
BinaryTree *tree = new BinaryTree();
/*
Construct Binary Tree
-----------------------
5
/  \
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
*/
tree->root = new TreeNode(5);
tree->root->left = new TreeNode(3);
tree->root->right = new TreeNode(9);
tree->root->right->right = new TreeNode(3);
tree->root->left->right = new TreeNode(6);
tree->root->right->left = new TreeNode(1);
tree->root->left->left = new TreeNode(7);
tree->root->left->left->left = new TreeNode(10);
tree->root->left->left->right = new TreeNode(3);
tree->root->right->left->right = new TreeNode(4);
tree->root->right->left->left = new TreeNode(7);
/*
Given Binary Tree
-----------------------
5
/  \
/    \
3      9
/ \    / \
7   6  1   3
/ \    / \
10  3  7   4
Here
Odd path from root to leaf
-----------------------
5
/  \
/    \
3      9
/      / \
7      1   3
\    /
3  7
---------------------
5->3->7->3
5->9->1->7
5->9->3
----------------------
Result : 3 [number of path]
*/
// Count odd nodes paths from root
// to leaf in a binary tree.
cout << tree->countOddNodePath(tree->root) << endl;
return 0;
}``````

Output

``3``

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