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Convert Octal to Binary number

Here given code implementation process.

//C Program
//Convert Octal to Binary number
#include <stdio.h>

//Get a octal number and returning a decimal number
long long octal_to_decimal(long long number)
{
	long long result = 0, multiplier = 1;
	int remainder = 0;
	while (number != 0)
	{
		remainder = number % 10;
		result = (remainder * multiplier) + result;
		multiplier *= 8;
		number /= 10;
	}
	return result;
}
//Display binary of given number
void binary(long long n)
{
	long long auxiliary = n;
	int bits = 0;
	if (n < 0)
	{
		n = -n;
		auxiliary = n;
		printf("-");
	}
	while (auxiliary != 0)
	{
		auxiliary /= 10;
		bits++;
	}
	bits = bits * 3;
	if (bits > 31)
	{
		//When number exceeds the length of 4 byte integer
		return;
	}
	int flag = 0;
	for (bits; bits >= 0; bits--)
	{
		if ((n >> bits) & 1)
		{
			printf(" 1 ");
			flag = 1;
		}
		else if (flag == 1)
		{
			printf(" 0 ");
		}
	}
	printf("\n");
}
void octal_to_binary(long long number)
{
	printf("Octal : %lld  Binary : ", number);
	//Convert octal to decimal
	number = octal_to_decimal(number);
	//Convert decimal to binary
	binary(number);
}
int main()
{
	//Pass a decimal value which is contain octal value
	octal_to_binary(17);
	octal_to_binary(45);
	octal_to_binary(63);
	octal_to_binary(12);
	octal_to_binary(-45);
	return 0;
}

Output

Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1
/*
  Java Program
  Convert Octal to Binary number
*/
class MyNumber
{
	//Get a octal number and returning a decimal number
	public long octal_to_decimal(long number)
	{
		long result = 0, multiplier = 1;
		long remainder = 0;
		while (number != 0)
		{
			remainder = number % 10;
			result = (remainder * multiplier) + result;
			multiplier *= 8;
			number = number / 10;
		}
		return result;
	}
	//Display binary of given number
	public void binary(long n)
	{
		if (n < 0)
		{
			n = -n;
			System.out.print("-");
		}
		long auxiliary = n;
		int size = 0;
		while (auxiliary != 0)
		{
			auxiliary = auxiliary / 10;
			size++;
		}
		size = size * 3;
		if (size > 31)
		{
			//When number exceeds the length of 4 byte integer
			return;
		}
		boolean flag = false;
		for (int bits = size; bits >= 0; bits--)
		{
			if (((n >> bits) & 1) == 0b1)
			{
				System.out.print(" 1 ");
				flag = true;
			}
			else if (flag == true)
			{
				System.out.print(" 0 ");
			}
		}
		System.out.print("\n");
	}
	public void octal_to_binary(long number)
	{
		System.out.print("Octal : " + number + "  Binary : ");
		//Convert octal to decimal
		number = octal_to_decimal(number);
		//Convert decimal to binary
		binary(number);
	}
	public static void main(String[] args)
	{
		MyNumber obj = new MyNumber();
		//Test Cases
		//Pass a decimal value which is indicates a octal number
		obj.octal_to_binary(17);
		obj.octal_to_binary(45);
		obj.octal_to_binary(63);
		obj.octal_to_binary(12);
		obj.octal_to_binary(-45);
	}
}

Output

Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1
//Include header file
#include <iostream>

using namespace std;
/*
  C++ Program
  Convert Octal to Binary number
*/
class MyNumber
{
	public:
		//Get a octal number and returning a decimal number
		long octal_to_decimal(long number)
		{
			long result = 0, multiplier = 1;
			long remainder = 0;
			while (number != 0)
			{
				remainder = number % 10;
				result = (remainder * multiplier) + result;
				multiplier *= 8;
				number = number / 10;
			}
			return result;
		}
	//Display binary of given number
	void binary(long n)
	{
		if (n < 0)
		{
			n = -n;
			cout << "-";
		}
		long auxiliary = n;
		int size = 0;
		while (auxiliary != 0)
		{
			auxiliary = auxiliary / 10;
			size++;
		}
		size = size * 3;
		if (size > 31)
		{
			//When number exceeds the length of 4 byte integer
			return;
		}
		bool flag = false;
		for (int bits = size; bits >= 0; bits--)
		{
			if (((n >> bits) & 1) == 0b1)
			{
				cout << " 1 ";
				flag = true;
			}
			else if (flag == true)
			{
				cout << " 0 ";
			}
		}
		cout << "\n";
	}
	void octal_to_binary(long number)
	{
		cout << "Octal : " << number << "  Binary : ";
		//Convert octal to decimal
		number = this->octal_to_decimal(number);
		//Convert decimal to binary
		this->binary(number);
	}
};
int main()
{
	MyNumber obj = MyNumber();
	//Test Cases
	//Pass a decimal value which is indicates a octal number
	obj.octal_to_binary(17);
	obj.octal_to_binary(45);
	obj.octal_to_binary(63);
	obj.octal_to_binary(12);
	obj.octal_to_binary(-45);
	return 0;
}

Output

Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1
//Include namespace system
using System;
/*
  C# Program
  Convert Octal to Binary number
*/
class MyNumber
{
	//Get a octal number and returning a decimal number
	public long octal_to_decimal(long number)
	{
		long result = 0, multiplier = 1;
		long remainder = 0;
		while (number != 0)
		{
			remainder = number % 10;
			result = (remainder * multiplier) + result;
			multiplier *= 8;
			number = number / 10;
		}
		return result;
	}
	//Display binary of given number
	public void binary(long n)
	{
		if (n < 0)
		{
			n = -n;
			Console.Write("-");
		}
		long auxiliary = n;
		int size = 0;
		while (auxiliary != 0)
		{
			auxiliary = auxiliary / 10;
			size++;
		}
		size = size * 3;
		if (size > 31)
		{
			//When number exceeds the length of 4 byte integer
			return;
		}
		Boolean flag = false;
		for (int bits = size; bits >= 0; bits--)
		{
			if (((n >> bits) & 1) == 0b1)
			{
				Console.Write(" 1 ");
				flag = true;
			}
			else if (flag == true)
			{
				Console.Write(" 0 ");
			}
		}
		Console.Write("\n");
	}
	public void octal_to_binary(long number)
	{
		Console.Write("Octal : " + number + "  Binary : ");
		//Convert octal to decimal
		number = octal_to_decimal(number);
		//Convert decimal to binary
		binary(number);
	}
	public static void Main(String[] args)
	{
		MyNumber obj = new MyNumber();
		//Test Cases
		//Pass a decimal value which is indicates a octal number
		obj.octal_to_binary(17);
		obj.octal_to_binary(45);
		obj.octal_to_binary(63);
		obj.octal_to_binary(12);
		obj.octal_to_binary(-45);
	}
}

Output

Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1
<?php
/*
  Php Program
  Convert Octal to Binary number
*/
class MyNumber
{
	//Get a octal number and returning a decimal number
	public	function octal_to_decimal($number)
	{
		$result = 0;
		$multiplier = 1;
		$remainder = 0;
		while ($number != 0)
		{
			$remainder = $number % 10;
			$result = ($remainder * $multiplier) + $result;
			$multiplier *= 8;
			$number = intval($number / 10);
		}
		return $result;
	}
	//Display binary of given number
	public	function binary($n)
	{
		if ($n < 0)
		{
			$n = -$n;
			echo "-";
		}
		$auxiliary = $n;
		$size = 0;
		while ($auxiliary != 0)
		{
			$auxiliary = intval($auxiliary / 10);
			$size++;
		}
		$size = $size * 3;
		if ($size > 31)
		{
			//When number exceeds the length of 4 byte integer
			return;
		}
		$flag = false;
		for ($bits = $size; $bits >= 0; $bits--)
		{
			if ((($n >> $bits) & 1) == 0b1)
			{
				echo " 1 ";
				$flag = true;
			}
			else if ($flag == true)
			{
				echo " 0 ";
			}
		}
		echo "\n";
	}
	public	function octal_to_binary($number)
	{
		echo "Octal : ". $number ."  Binary : ";
		//Convert octal to decimal
		$number = $this->octal_to_decimal($number);
		//Convert decimal to binary
		$this->binary($number);
	}
}

function main()
{
	$obj = new MyNumber();
	//Test Cases
	//Pass a decimal value which is indicates a octal number
	$obj->octal_to_binary(17);
	$obj->octal_to_binary(45);
	$obj->octal_to_binary(63);
	$obj->octal_to_binary(12);
	$obj->octal_to_binary(-45);
}
main();

Output

Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1
/*
  Node Js Program
  Convert Octal to Binary number
*/
class MyNumber
{
	//Get a octal number and returning a decimal number
	octal_to_decimal(number)
	{
		var result = 0;
		var multiplier = 1;
		var remainder = 0;
		while (number != 0)
		{
			remainder = number % 10;
			result = (remainder * multiplier) + result;
			multiplier *= 8;
			number = parseInt(number / 10);
		}
		return result;
	}
	//Display binary of given number
	binary(n)
	{
		if (n < 0)
		{
			n = -n;
			process.stdout.write("-");
		}
		var auxiliary = n;
		var size = 0;
		while (auxiliary != 0)
		{
			auxiliary = parseInt(auxiliary / 10);
			size++;
		}
		size = size * 3;
		if (size > 31)
		{
			//When number exceeds the length of 4 byte integer
			return;
		}
		var flag = false;
		for (var bits = size; bits >= 0; bits--)
		{
			if (((n >> bits) & 1) == 0b1)
			{
				process.stdout.write(" 1 ");
				flag = true;
			}
			else if (flag == true)
			{
				process.stdout.write(" 0 ");
			}
		}
		process.stdout.write("\n");
	}
	octal_to_binary(number)
	{
		process.stdout.write("Octal : " + number + "  Binary : ");
		//Convert octal to decimal
		number = this.octal_to_decimal(number);
		//Convert decimal to binary
		this.binary(number);
	}
}

function main()
{
	var obj = new MyNumber();
	//Test Cases
	//Pass a decimal value which is indicates a octal number
	obj.octal_to_binary(17);
	obj.octal_to_binary(45);
	obj.octal_to_binary(63);
	obj.octal_to_binary(12);
	obj.octal_to_binary(-45);
}
main();

Output

Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1
#   Python 3 Program
#   Convert Octal to Binary number

class MyNumber :
    # Get a octal number and returning a decimal number
    def octal_to_decimal(self, number) :
        result = 0
        multiplier = 1
        remainder = 0
        while (number != 0) :
            remainder = number % 10
            result = (remainder * multiplier) + result
            multiplier *= 8
            number = int(number / 10)
        
        return result
    
    # Display binary of given number
    def binary(self, n) :
        if (n < 0) :
            n = -n
            print("-", end = "")
        
        auxiliary = n
        size = 0
        while (auxiliary != 0) :
            auxiliary = int(auxiliary / 10)
            size += 1
        
        size = size * 3
        if (size > 31) :
            # When number exceeds the length of 4 byte integer
            return
        
        flag = False
        bits = size
        while (bits >= 0) :
            if (((n >> bits) & 1) == 0b1) :
                print(" 1 ", end = "")
                flag = True
            
            elif(flag == True) :
                print(" 0 ", end = "")
            
            bits -= 1
        
        print("\n", end = "")
    
    def octal_to_binary(self, number) :
        print("Octal : ", number ,"  Binary : ", end = "")
        temp_number = number
        if (number<0):
            number = -number
        # Convert octal to decimal
        number = self.octal_to_decimal(number)
        if(temp_number<0):
            number = - number
        # Convert decimal to binary
        self.binary(number)
    

def main() :
    obj = MyNumber()
    # Test Cases
    # Pass a decimal value which is indicates a octal number
    obj.octal_to_binary(17)
    obj.octal_to_binary(45)
    obj.octal_to_binary(63)
    obj.octal_to_binary(12)
    obj.octal_to_binary(-45)

if __name__ == "__main__": main()

Output

Octal :  17   Binary :  1  1  1  1
Octal :  45   Binary :  1  0  0  1  0  1
Octal :  63   Binary :  1  1  0  0  1  1
Octal :  12   Binary :  1  0  1  0
Octal :  -45   Binary : - 1  0  0  1  0  1
/*
  Scala Program
  Convert Octal to Binary number
*/
class MyNumber
{
	//Get a octal number and returning a decimal number
	def octal_to_decimal(num: Long): Long = {
		var result: Long = 0;
		var multiplier: Long = 1;
		var remainder: Long = 0;
      	var number: Long = num;
		while (number != 0)
		{
			remainder = number % 10;
			result = (remainder * multiplier) + result;
			multiplier *= 8;
			number = (number / 10).toInt;
		}
		return result;
	}
	//Display binary of given number
	def binary(number: Long): Unit = {
      	var n : Long = number;
		if (n < 0)
		{
			n = -n;
			print("-");
		}
		var auxiliary: Long = n;
		var size: Int = 0;
		while (auxiliary != 0)
		{
			auxiliary = (auxiliary / 10).toInt;
			size += 1;
		}
		size = size * 3;
		if (size > 31)
		{
			//When number exceeds the length of 4 byte integer
			return;
		}
		var flag: Boolean = false;
		var bits: Int = size;
		while (bits >= 0)
		{
			if (((n >> bits) & 1) == 1)
			{
				print(" 1 ");
				flag = true;
			}
			else if (flag == true)
			{
				print(" 0 ");
			}
			bits -= 1;
		}
		print("\n");
	}
	def octal_to_binary(number: Long): Unit = {
		print("Octal : " + number + "  Binary : ");
		//Convert octal to decimal
		var decimal = octal_to_decimal(number);
		//Convert decimal to binary
		binary(decimal);
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var obj: MyNumber = new MyNumber();
		//Test Cases
		//Pass a decimal value which is indicates a octal number
		obj.octal_to_binary(17);
		obj.octal_to_binary(45);
		obj.octal_to_binary(63);
		obj.octal_to_binary(12);
		obj.octal_to_binary(-45);
	}
}

Output

Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1
/*
  Swift Program
  Convert Octal to Binary number
*/
class MyNumber
{
	//Get a octal number and returning a decimal number
	func octal_to_decimal(_ n:  Int) -> Int
	{
		var result: Int = 0;
		var multiplier: Int = 1;
		var remainder: Int = 0;
        var number : Int = n;
		while (number != 0)
		{
			remainder = number % 10;
			result = (remainder * multiplier) + result;
			multiplier *= 8;
			number = number / 10;
		}
		return result;
	}
	//Display binary of given number
	func binary(_ number: Int)
	{
        var n = number;
		if (n < 0)
		{
			n = -n;
			print("-", terminator: "");
		}
		var auxiliary: Int = n;
		var size: Int = 0;
		while (auxiliary != 0)
		{
			auxiliary = auxiliary / 10;
			size += 1;
		}
		size = size * 3;
		if (size > 31)
		{
			//When number exceeds the length of 4 byte integer
			return;
		}
		var flag: Bool = false;
		var bits: Int = size;
		while (bits >= 0)
		{
			if (((n >> bits) & 1) == 0b1)
			{
				print(" 1 ", terminator: "");
				flag = true;
			}
			else if (flag == true)
			{
				print(" 0 ", terminator: "");
			}
			bits -= 1;
		}
		print("\n", terminator: "");
	}
	func octal_to_binary(_ number: Int)
	{
		print("Octal : ", number ,"  Binary : ", terminator: "");
		//Convert octal to decimal
		let decimal = self.octal_to_decimal(number);
		//Convert decimal to binary
		self.binary(decimal);
	}
}
func main()
{
	let obj: MyNumber = MyNumber();
	//Test Cases
	//Pass a decimal value which is indicates a octal number
	obj.octal_to_binary(17);
	obj.octal_to_binary(45);
	obj.octal_to_binary(63);
	obj.octal_to_binary(12);
	obj.octal_to_binary(-45);
}
main();

Output

Octal :  17   Binary :  1  1  1  1
Octal :  45   Binary :  1  0  0  1  0  1
Octal :  63   Binary :  1  1  0  0  1  1
Octal :  12   Binary :  1  0  1  0
Octal :  -45   Binary : - 1  0  0  1  0  1
#   Ruby Program
#   Convert Octal to Binary number

class MyNumber

	# Get a octal number and returning a decimal number
	def octal_to_decimal(number)
	
		result = 0
		multiplier = 1
		remainder = 0
		while (number != 0)
		
			remainder = number % 10
			result = (remainder * multiplier) + result
			multiplier *= 8
			number = number / 10
		end
		return result
	end
	# Display binary of given number
	def binary(n)
	
		if (n < 0)
		
			n = -n
			print("-")
		end
		auxiliary = n
		size = 0
		while (auxiliary != 0)
		
			auxiliary = auxiliary / 10
			size += 1
		end
		size = size * 3
		if (size > 31)
		
			# When number exceeds the length of 4 byte integer
			return
		end
		flag = false
		bits = size
		while (bits >= 0)
		
			if (((n >> bits) & 1) == 0b1)
			
				print(" 1 ")
				flag = true
			elsif(flag == true)
			
				print(" 0 ")
			end
			bits -= 1
		end
		print("\n")
	end
	def octal_to_binary(number)
	
		print("Octal : ", number ,"  Binary : ")
		temp = number
		if (number<0)
        	number = -number
		end
		# Convert octal to decimal
		number = self.octal_to_decimal(number)
		if(temp<0)
        	number = -number
        end
		# Convert decimal to binary
		self.binary(number)
	end
end
def main()

	obj = MyNumber.new()
	# Test Cases
	# Pass a decimal value which is indicates a octal number
	obj.octal_to_binary(17)
	obj.octal_to_binary(45)
	obj.octal_to_binary(63)
	obj.octal_to_binary(12)
	obj.octal_to_binary(-45)
end
main()

Output

Octal : 17  Binary :  1  1  1  1 
Octal : 45  Binary :  1  0  0  1  0  1 
Octal : 63  Binary :  1  1  0  0  1  1 
Octal : 12  Binary :  1  0  1  0 
Octal : -45  Binary : - 1  0  0  1  0  1
Last updated on by Kalkicode




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