Posted on by Kalkicode
Code Conversion

Convert Octal to Binary number

Octal is a number system that uses a base of 8, meaning it has eight digits from 0 to 7. Binary, on the other hand, is a number system that uses a base of 2, with only two digits, 0 and 1.

To convert an octal number to binary, you need to convert each octal digit to a corresponding binary representation. To do this, you can use the following table:

Octal digitBinary equivalent
0000
1001
2010
3011
4100
5101
6110
7111

To convert an octal number to binary, you need to replace each octal digit with its corresponding binary equivalent. For example, let's say you want to convert the octal number 27 to binary.

First, you need to break down 27 into its digits, which are 2 and 7. Then, you can convert each digit to its binary equivalent using the table above.

The digit 2 in octal is equivalent to 010 in binary, and the digit 7 in octal is equivalent to 111 in binary. So the binary equivalent of the octal number 27 is 010111.

Program List

``````//C Program
//Convert Octal to Binary number
#include <stdio.h>

//Get a octal number and returning a decimal number
long long octal_to_decimal(long long number)
{
long long result = 0, multiplier = 1;
int remainder = 0;
while (number != 0)
{
remainder = number % 10;
result = (remainder * multiplier) + result;
multiplier *= 8;
number /= 10;
}
return result;
}
//Display binary of given number
void binary(long long n)
{
long long auxiliary = n;
int bits = 0;
if (n < 0)
{
n = -n;
auxiliary = n;
printf("-");
}
while (auxiliary != 0)
{
auxiliary /= 10;
bits++;
}
bits = bits * 3;
if (bits > 31)
{
//When number exceeds the length of 4 byte integer
return;
}
int flag = 0;
for (bits; bits >= 0; bits--)
{
if ((n >> bits) & 1)
{
printf(" 1 ");
flag = 1;
}
else if (flag == 1)
{
printf(" 0 ");
}
}
printf("\n");
}
void octal_to_binary(long long number)
{
printf("Octal : %lld  Binary : ", number);
//Convert octal to decimal
number = octal_to_decimal(number);
//Convert decimal to binary
binary(number);
}
int main()
{
//Pass a decimal value which is contain octal value
octal_to_binary(17);
octal_to_binary(45);
octal_to_binary(63);
octal_to_binary(12);
octal_to_binary(-45);
return 0;
}``````

Output

``````Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1``````
``````/*
Java Program
Convert Octal to Binary number
*/
class MyNumber
{
//Get a octal number and returning a decimal number
public long octal_to_decimal(long number)
{
long result = 0, multiplier = 1;
long remainder = 0;
while (number != 0)
{
remainder = number % 10;
result = (remainder * multiplier) + result;
multiplier *= 8;
number = number / 10;
}
return result;
}
//Display binary of given number
public void binary(long n)
{
if (n < 0)
{
n = -n;
System.out.print("-");
}
long auxiliary = n;
int size = 0;
while (auxiliary != 0)
{
auxiliary = auxiliary / 10;
size++;
}
size = size * 3;
if (size > 31)
{
//When number exceeds the length of 4 byte integer
return;
}
boolean flag = false;
for (int bits = size; bits >= 0; bits--)
{
if (((n >> bits) & 1) == 0b1)
{
System.out.print(" 1 ");
flag = true;
}
else if (flag == true)
{
System.out.print(" 0 ");
}
}
System.out.print("\n");
}
public void octal_to_binary(long number)
{
System.out.print("Octal : " + number + "  Binary : ");
//Convert octal to decimal
number = octal_to_decimal(number);
//Convert decimal to binary
binary(number);
}
public static void main(String[] args)
{
MyNumber obj = new MyNumber();
//Test Cases
//Pass a decimal value which is indicates a octal number
obj.octal_to_binary(17);
obj.octal_to_binary(45);
obj.octal_to_binary(63);
obj.octal_to_binary(12);
obj.octal_to_binary(-45);
}
}``````

Output

``````Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1``````
``````//Include header file
#include <iostream>

using namespace std;
/*
C++ Program
Convert Octal to Binary number
*/
class MyNumber
{
public:
//Get a octal number and returning a decimal number
long octal_to_decimal(long number)
{
long result = 0, multiplier = 1;
long remainder = 0;
while (number != 0)
{
remainder = number % 10;
result = (remainder * multiplier) + result;
multiplier *= 8;
number = number / 10;
}
return result;
}
//Display binary of given number
void binary(long n)
{
if (n < 0)
{
n = -n;
cout << "-";
}
long auxiliary = n;
int size = 0;
while (auxiliary != 0)
{
auxiliary = auxiliary / 10;
size++;
}
size = size * 3;
if (size > 31)
{
//When number exceeds the length of 4 byte integer
return;
}
bool flag = false;
for (int bits = size; bits >= 0; bits--)
{
if (((n >> bits) & 1) == 0b1)
{
cout << " 1 ";
flag = true;
}
else if (flag == true)
{
cout << " 0 ";
}
}
cout << "\n";
}
void octal_to_binary(long number)
{
cout << "Octal : " << number << "  Binary : ";
//Convert octal to decimal
number = this->octal_to_decimal(number);
//Convert decimal to binary
this->binary(number);
}
};
int main()
{
MyNumber obj = MyNumber();
//Test Cases
//Pass a decimal value which is indicates a octal number
obj.octal_to_binary(17);
obj.octal_to_binary(45);
obj.octal_to_binary(63);
obj.octal_to_binary(12);
obj.octal_to_binary(-45);
return 0;
}``````

Output

``````Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1``````
``````//Include namespace system
using System;
/*
C# Program
Convert Octal to Binary number
*/
class MyNumber
{
//Get a octal number and returning a decimal number
public long octal_to_decimal(long number)
{
long result = 0, multiplier = 1;
long remainder = 0;
while (number != 0)
{
remainder = number % 10;
result = (remainder * multiplier) + result;
multiplier *= 8;
number = number / 10;
}
return result;
}
//Display binary of given number
public void binary(long n)
{
if (n < 0)
{
n = -n;
Console.Write("-");
}
long auxiliary = n;
int size = 0;
while (auxiliary != 0)
{
auxiliary = auxiliary / 10;
size++;
}
size = size * 3;
if (size > 31)
{
//When number exceeds the length of 4 byte integer
return;
}
Boolean flag = false;
for (int bits = size; bits >= 0; bits--)
{
if (((n >> bits) & 1) == 0b1)
{
Console.Write(" 1 ");
flag = true;
}
else if (flag == true)
{
Console.Write(" 0 ");
}
}
Console.Write("\n");
}
public void octal_to_binary(long number)
{
Console.Write("Octal : " + number + "  Binary : ");
//Convert octal to decimal
number = octal_to_decimal(number);
//Convert decimal to binary
binary(number);
}
public static void Main(String[] args)
{
MyNumber obj = new MyNumber();
//Test Cases
//Pass a decimal value which is indicates a octal number
obj.octal_to_binary(17);
obj.octal_to_binary(45);
obj.octal_to_binary(63);
obj.octal_to_binary(12);
obj.octal_to_binary(-45);
}
}``````

Output

``````Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1``````
``````<?php
/*
Php Program
Convert Octal to Binary number
*/
class MyNumber
{
//Get a octal number and returning a decimal number
public	function octal_to_decimal(\$number)
{
\$result = 0;
\$multiplier = 1;
\$remainder = 0;
while (\$number != 0)
{
\$remainder = \$number % 10;
\$result = (\$remainder * \$multiplier) + \$result;
\$multiplier *= 8;
\$number = intval(\$number / 10);
}
return \$result;
}
//Display binary of given number
public	function binary(\$n)
{
if (\$n < 0)
{
\$n = -\$n;
echo "-";
}
\$auxiliary = \$n;
\$size = 0;
while (\$auxiliary != 0)
{
\$auxiliary = intval(\$auxiliary / 10);
\$size++;
}
\$size = \$size * 3;
if (\$size > 31)
{
//When number exceeds the length of 4 byte integer
return;
}
\$flag = false;
for (\$bits = \$size; \$bits >= 0; \$bits--)
{
if (((\$n >> \$bits) & 1) == 0b1)
{
echo " 1 ";
\$flag = true;
}
else if (\$flag == true)
{
echo " 0 ";
}
}
echo "\n";
}
public	function octal_to_binary(\$number)
{
echo "Octal : ". \$number ."  Binary : ";
//Convert octal to decimal
\$number = \$this->octal_to_decimal(\$number);
//Convert decimal to binary
\$this->binary(\$number);
}
}

function main()
{
\$obj = new MyNumber();
//Test Cases
//Pass a decimal value which is indicates a octal number
\$obj->octal_to_binary(17);
\$obj->octal_to_binary(45);
\$obj->octal_to_binary(63);
\$obj->octal_to_binary(12);
\$obj->octal_to_binary(-45);
}
main();``````

Output

``````Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1``````
``````/*
Node Js Program
Convert Octal to Binary number
*/
class MyNumber
{
//Get a octal number and returning a decimal number
octal_to_decimal(number)
{
var result = 0;
var multiplier = 1;
var remainder = 0;
while (number != 0)
{
remainder = number % 10;
result = (remainder * multiplier) + result;
multiplier *= 8;
number = parseInt(number / 10);
}
return result;
}
//Display binary of given number
binary(n)
{
if (n < 0)
{
n = -n;
process.stdout.write("-");
}
var auxiliary = n;
var size = 0;
while (auxiliary != 0)
{
auxiliary = parseInt(auxiliary / 10);
size++;
}
size = size * 3;
if (size > 31)
{
//When number exceeds the length of 4 byte integer
return;
}
var flag = false;
for (var bits = size; bits >= 0; bits--)
{
if (((n >> bits) & 1) == 0b1)
{
process.stdout.write(" 1 ");
flag = true;
}
else if (flag == true)
{
process.stdout.write(" 0 ");
}
}
process.stdout.write("\n");
}
octal_to_binary(number)
{
process.stdout.write("Octal : " + number + "  Binary : ");
//Convert octal to decimal
number = this.octal_to_decimal(number);
//Convert decimal to binary
this.binary(number);
}
}

function main()
{
var obj = new MyNumber();
//Test Cases
//Pass a decimal value which is indicates a octal number
obj.octal_to_binary(17);
obj.octal_to_binary(45);
obj.octal_to_binary(63);
obj.octal_to_binary(12);
obj.octal_to_binary(-45);
}
main();``````

Output

``````Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1``````
``````#   Python 3 Program
#   Convert Octal to Binary number

class MyNumber :
# Get a octal number and returning a decimal number
def octal_to_decimal(self, number) :
result = 0
multiplier = 1
remainder = 0
while (number != 0) :
remainder = number % 10
result = (remainder * multiplier) + result
multiplier *= 8
number = int(number / 10)

return result

# Display binary of given number
def binary(self, n) :
if (n < 0) :
n = -n
print("-", end = "")

auxiliary = n
size = 0
while (auxiliary != 0) :
auxiliary = int(auxiliary / 10)
size += 1

size = size * 3
if (size > 31) :
# When number exceeds the length of 4 byte integer
return

flag = False
bits = size
while (bits >= 0) :
if (((n >> bits) & 1) == 0b1) :
print(" 1 ", end = "")
flag = True

elif(flag == True) :
print(" 0 ", end = "")

bits -= 1

print("\n", end = "")

def octal_to_binary(self, number) :
print("Octal : ", number ,"  Binary : ", end = "")
temp_number = number
if (number<0):
number = -number
# Convert octal to decimal
number = self.octal_to_decimal(number)
if(temp_number<0):
number = - number
# Convert decimal to binary
self.binary(number)

def main() :
obj = MyNumber()
# Test Cases
# Pass a decimal value which is indicates a octal number
obj.octal_to_binary(17)
obj.octal_to_binary(45)
obj.octal_to_binary(63)
obj.octal_to_binary(12)
obj.octal_to_binary(-45)

if __name__ == "__main__": main()``````

Output

``````Octal :  17   Binary :  1  1  1  1
Octal :  45   Binary :  1  0  0  1  0  1
Octal :  63   Binary :  1  1  0  0  1  1
Octal :  12   Binary :  1  0  1  0
Octal :  -45   Binary : - 1  0  0  1  0  1``````
``````/*
Scala Program
Convert Octal to Binary number
*/
class MyNumber
{
//Get a octal number and returning a decimal number
def octal_to_decimal(num: Long): Long = {
var result: Long = 0;
var multiplier: Long = 1;
var remainder: Long = 0;
var number: Long = num;
while (number != 0)
{
remainder = number % 10;
result = (remainder * multiplier) + result;
multiplier *= 8;
number = (number / 10).toInt;
}
return result;
}
//Display binary of given number
def binary(number: Long): Unit = {
var n : Long = number;
if (n < 0)
{
n = -n;
print("-");
}
var auxiliary: Long = n;
var size: Int = 0;
while (auxiliary != 0)
{
auxiliary = (auxiliary / 10).toInt;
size += 1;
}
size = size * 3;
if (size > 31)
{
//When number exceeds the length of 4 byte integer
return;
}
var flag: Boolean = false;
var bits: Int = size;
while (bits >= 0)
{
if (((n >> bits) & 1) == 1)
{
print(" 1 ");
flag = true;
}
else if (flag == true)
{
print(" 0 ");
}
bits -= 1;
}
print("\n");
}
def octal_to_binary(number: Long): Unit = {
print("Octal : " + number + "  Binary : ");
//Convert octal to decimal
var decimal = octal_to_decimal(number);
//Convert decimal to binary
binary(decimal);
}
}
object Main
{
def main(args: Array[String]): Unit = {
var obj: MyNumber = new MyNumber();
//Test Cases
//Pass a decimal value which is indicates a octal number
obj.octal_to_binary(17);
obj.octal_to_binary(45);
obj.octal_to_binary(63);
obj.octal_to_binary(12);
obj.octal_to_binary(-45);
}
}``````

Output

``````Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1``````
``````/*
Swift Program
Convert Octal to Binary number
*/
class MyNumber
{
//Get a octal number and returning a decimal number
func octal_to_decimal(_ n:  Int) -> Int
{
var result: Int = 0;
var multiplier: Int = 1;
var remainder: Int = 0;
var number : Int = n;
while (number != 0)
{
remainder = number % 10;
result = (remainder * multiplier) + result;
multiplier *= 8;
number = number / 10;
}
return result;
}
//Display binary of given number
func binary(_ number: Int)
{
var n = number;
if (n < 0)
{
n = -n;
print("-", terminator: "");
}
var auxiliary: Int = n;
var size: Int = 0;
while (auxiliary != 0)
{
auxiliary = auxiliary / 10;
size += 1;
}
size = size * 3;
if (size > 31)
{
//When number exceeds the length of 4 byte integer
return;
}
var flag: Bool = false;
var bits: Int = size;
while (bits >= 0)
{
if (((n >> bits) & 1) == 0b1)
{
print(" 1 ", terminator: "");
flag = true;
}
else if (flag == true)
{
print(" 0 ", terminator: "");
}
bits -= 1;
}
print("\n", terminator: "");
}
func octal_to_binary(_ number: Int)
{
print("Octal : ", number ,"  Binary : ", terminator: "");
//Convert octal to decimal
let decimal = self.octal_to_decimal(number);
//Convert decimal to binary
self.binary(decimal);
}
}
func main()
{
let obj: MyNumber = MyNumber();
//Test Cases
//Pass a decimal value which is indicates a octal number
obj.octal_to_binary(17);
obj.octal_to_binary(45);
obj.octal_to_binary(63);
obj.octal_to_binary(12);
obj.octal_to_binary(-45);
}
main();``````

Output

``````Octal :  17   Binary :  1  1  1  1
Octal :  45   Binary :  1  0  0  1  0  1
Octal :  63   Binary :  1  1  0  0  1  1
Octal :  12   Binary :  1  0  1  0
Octal :  -45   Binary : - 1  0  0  1  0  1``````
``````#   Ruby Program
#   Convert Octal to Binary number

class MyNumber

# Get a octal number and returning a decimal number
def octal_to_decimal(number)

result = 0
multiplier = 1
remainder = 0
while (number != 0)

remainder = number % 10
result = (remainder * multiplier) + result
multiplier *= 8
number = number / 10
end
return result
end
# Display binary of given number
def binary(n)

if (n < 0)

n = -n
print("-")
end
auxiliary = n
size = 0
while (auxiliary != 0)

auxiliary = auxiliary / 10
size += 1
end
size = size * 3
if (size > 31)

# When number exceeds the length of 4 byte integer
return
end
flag = false
bits = size
while (bits >= 0)

if (((n >> bits) & 1) == 0b1)

print(" 1 ")
flag = true
elsif(flag == true)

print(" 0 ")
end
bits -= 1
end
print("\n")
end
def octal_to_binary(number)

print("Octal : ", number ,"  Binary : ")
temp = number
if (number<0)
number = -number
end
# Convert octal to decimal
number = self.octal_to_decimal(number)
if(temp<0)
number = -number
end
# Convert decimal to binary
self.binary(number)
end
end
def main()

obj = MyNumber.new()
# Test Cases
# Pass a decimal value which is indicates a octal number
obj.octal_to_binary(17)
obj.octal_to_binary(45)
obj.octal_to_binary(63)
obj.octal_to_binary(12)
obj.octal_to_binary(-45)
end
main()``````

Output

``````Octal : 17  Binary :  1  1  1  1
Octal : 45  Binary :  1  0  0  1  0  1
Octal : 63  Binary :  1  1  0  0  1  1
Octal : 12  Binary :  1  0  1  0
Octal : -45  Binary : - 1  0  0  1  0  1
``````

Comment

Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.

Categories
Relative Post