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Check whether a number is duck number or not

In this article, we will explore the concept of Duck Numbers and how to determine whether a given number is a Duck Number or not. A Duck Number is a positive number that contains at least one zero and has all its non-leading digits (digits other than the leftmost non-zero digit) as non-zero. For example, the number 10235 is a Duck Number because it has a zero and all other digits are non-zero. On the other hand, 12345 is not a Duck Number as it lacks a zero.

Problem Statement

The problem is to write a C program that takes a string representation of a number as input and determines whether it is a Duck Number or not. The program should skip any leading zeros and then check if all the remaining digits are non-zero.

Example

Let's take some test cases to better understand the concept:

  1. Input: "529043043" Output: [529043043] is duck number Explanation: The number has a zero (0) and all other digits are non-zero.

  2. Input: "0001234" Output: [0001234] is not duck number Explanation: Although the number has a zero (0), the other non-leading digits are not all non-zero.

  3. Input: "00012304" Output: [00012304] is duck number Explanation: The number has a zero (0) and all other digits are non-zero.

  4. Input: "1000000" Output: [1000000] is duck number Explanation: The number has a zero (0) and all other digits are non-zero.

  5. Input: "-1000000" Output: [-1000000] is not duck number Explanation: The given number is not a positive number.

  6. Input: "2300200100" Output: [2300200100] is duck number Explanation: The number has a zero (0) and all other digits are non-zero.

Pseudocode

is_duck_number(str_num[], size):
    counter = 0
    status = 0
    wrong = 0
    
    # Skip all the beginning zeros
    while counter < size and str_num[counter] == '0':
        counter++

    # Check if the remaining digits are all non-zero
    while counter < size and wrong == 0:
        if str_num[counter] >= '0' and str_num[counter] <= '9':
            if str_num[counter] == '0':
                status = 1
                # Terminate loop if we find a zero
        else:
            wrong = 1
            # Set wrong flag if we encounter a non-digit character
        counter++

    # Determine if the number is a Duck Number or not
    if wrong == 0 and status == 1:
        print "[str_num] is duck number"
    else:
        print "[str_num] is not duck number"

Algorithm Explanation

  1. Start by initializing a counter variable to keep track of the current position in the string and status to 0 (to track if a zero is found).
  2. Initialize wrong to 0 (to track if an invalid digit is found).
  3. Use a while loop to skip all the leading zeros in the string.
  4. Use another while loop to check if the remaining characters are valid digits (0 to 9) and if a zero is found.
  5. If a non-digit character is encountered, set wrong to 1.
  6. After looping through the string, check if wrong is still 0 (no invalid digit found) and status is 1 (a zero is found). If both conditions are met, the number is a Duck Number.
  7. Print the appropriate message based on whether the number is a Duck Number or not.

Code Solution

Here given code implementation process.

// C Program 
// Check Whether a number is duck number or not
#include <stdio.h>

// Determine whether given number is duck number or not
void is_duck_number(char str_num[], int size)
{
	if (size <= 0)
	{
		//When given string number is empty
		return;
	}
	int status = 0;
	int counter = 0;
	//This is used to check valid positive number
	int wrong = 0;
	// Skip the all beginning zeros
	while (counter < size && str_num[counter] == '0')
	{
		counter++;
	}
	while (counter < size && wrong == 0)
	{
		if (str_num[counter] >= '0' && str_num[counter] <= '9')
		{
			if (str_num[counter] == '0')
			{
				//We get zero
				status = 1;
				//Terminate loop when given number always valid number
			}
		}
		else
		{
			//When not a valid digit
			wrong = 1;
		}
		counter++;
	}
	if (wrong == 0 && status == 1)
	{
		printf("\n [%s] is duck number", str_num);
	}
	else
	{
		printf("\n [%s] is not duck number", str_num);
	}
}
int main()
{
	//Test string numbers
	char str_num1[] = "529043043";
	char str_num2[] = "0001234";
	char str_num3[] = "00012304";
	char str_num4[] = "1000000";
	char str_num5[] = "-1000000";
	char str_num6[] = "2300200100";
	int size = 0;
	//Test case 1
	size = sizeof(str_num1) / sizeof(str_num1[0]) - 1;
	is_duck_number(str_num1, size);
	//Test case 2
	size = sizeof(str_num2) / sizeof(str_num2[0]) - 1;
	is_duck_number(str_num2, size);
	//Test case 3
	size = sizeof(str_num3) / sizeof(str_num3[0]) - 1;
	is_duck_number(str_num3, size);
	//Test case 4
	size = sizeof(str_num4) / sizeof(str_num4[0]) - 1;
	is_duck_number(str_num4, size);
	//Test case 5
	size = sizeof(str_num5) / sizeof(str_num5[0]) - 1;
	is_duck_number(str_num5, size);
	//Test case 6
	size = sizeof(str_num6) / sizeof(str_num6[0]) - 1;
	is_duck_number(str_num6, size);
	return 0;
}

Output

 [529043043] is duck number
 [0001234] is not duck number
 [00012304] is duck number
 [1000000] is duck number
 [-1000000] is not duck number
 [2300200100] is duck number
/* 
  Java program 
  Check Whether a number is duck number or not
*/
class DuckNumber
{
	// Determine whether given number is duck number or not
	public void is_duck_number(String str_num, int size)
	{
		if (size <= 0)
		{
			//When given string number is empty
			return;
		}
		int counter = 0;
		//This is used to check valid positive number
		boolean wrong = false;
		boolean status = false;
		// Skip the all beginning zeros
		while (counter < size && str_num.charAt(counter) == '0')
		{
			counter++;
		}
		while (counter < size && wrong == false)
		{
			if (str_num.charAt(counter) >= '0' && str_num.charAt(counter) <= '9')
			{
				//Terminate loop when given number always valid number
				if (str_num.charAt(counter) == '0')
				{
					//We get zero
					status = true;
				}
			}
			else
			{
				//When not a valid digit
				wrong = true;
			}
			counter++;
		}
		if (wrong == false && status == true)
		{
			System.out.print("\n [" + str_num + "] is duck number");
		}
		else
		{
			System.out.print("\n [" + str_num + "] is not duck number");
		}
	}
	public static void main(String[] args)
	{
		DuckNumber obj = new DuckNumber();
		//Test string numbers
		String str_num1 = "529043043";
		String str_num2 = "0001234";
		String str_num3 = "00012304";
		String str_num4 = "1000000";
		String str_num5 = "-1000000";
		String str_num6 = "2300200100";
		int size = 0;
		//Test case 1
		size = str_num1.length();
		obj.is_duck_number(str_num1, size);
		//Test case 2
		size = str_num2.length();
		obj.is_duck_number(str_num2, size);
		//Test case 3
		size = str_num3.length();
		obj.is_duck_number(str_num3, size);
		//Test case 4
		size = str_num4.length();
		obj.is_duck_number(str_num4, size);
		//Test case 5
		size = str_num5.length();
		obj.is_duck_number(str_num5, size);
		//Test case 6
		size = str_num6.length();
		obj.is_duck_number(str_num6, size);
	}
}

Output

 [529043043] is duck number
 [0001234] is not duck number
 [00012304] is duck number
 [1000000] is duck number
 [-1000000] is not duck number
 [2300200100] is duck number
//Include header file
#include <iostream>
#include<string.h>

using namespace std;
/*
  C++ program 
  Check Whether a number is duck number or not
*/
class DuckNumber
{
	public:
		// Determine whether given number is duck number or not
		void is_duck_number(string str_num, int size)
		{
			if (size <= 0)
			{
				//When given string number is empty
				return;
			}
			int counter = 0;
			//This is used to check valid positive number
			bool wrong = false;
			bool status = false;
			// Skip the all beginning zeros
			while (counter < size && str_num[counter] == '0')
			{
				counter++;
			}
			while (counter < size && wrong == false)
			{
				if (str_num[counter] >= '0' && str_num[counter] <= '9')
				{
					//Terminate loop when given number always valid number
					if (str_num[counter] == '0')
					{
						//We get zero
						status = true;
					}
				}
				else
				{
					//When not a valid digit
					wrong = true;
				}
				counter++;
			}
			if (wrong == false && status == true)
			{
				cout << "\n [" << str_num << "] is duck number";
			}
			else
			{
				cout << "\n [" << str_num << "] is not duck number";
			}
		}
};
int main()
{
	DuckNumber obj = DuckNumber();
	//Test string numbers
	string str_num1 = "529043043";
	string str_num2 = "0001234";
	string str_num3 = "00012304";
	string str_num4 = "1000000";
	string str_num5 = "-1000000";
	string str_num6 = "2300200100";
	int size = 0;
	//Test case 1
	size = str_num1.size();
	obj.is_duck_number(str_num1, size);
	//Test case 2
	size = str_num2.size();
	obj.is_duck_number(str_num2, size);
	//Test case 3
	size = str_num3.size();
	obj.is_duck_number(str_num3, size);
	//Test case 4
	size = str_num4.size();
	obj.is_duck_number(str_num4, size);
	//Test case 5
	size = str_num5.size();
	obj.is_duck_number(str_num5, size);
	//Test case 6
	size = str_num6.size();
	obj.is_duck_number(str_num6, size);
	return 0;
}

Output

 [529043043] is duck number
 [0001234] is not duck number
 [00012304] is duck number
 [1000000] is duck number
 [-1000000] is not duck number
 [2300200100] is duck number
//Include namespace system
using System;

/* 
  C# program 
  Check Whether a number is duck number or not
*/

class DuckNumber
{
	// Determine whether given number is duck number or not
	public void is_duck_number(String str_num, int size)
	{
		if (size <= 0)
		{
			//When given string number is empty
			return;
		}
		int counter = 0;
		//This is used to check valid positive number
		Boolean wrong = false;
		Boolean status = false;
		// Skip the all beginning zeros
		while (counter < size && str_num[counter] == '0')
		{
			counter++;
		}
		while (counter < size && wrong == false)
		{
			if (str_num[counter] >= '0' && str_num[counter] <= '9')
			{
				//Terminate loop when given number always valid number
				if (str_num[counter] == '0')
				{
					//We get zero
					status = true;
				}
			}
			else
			{
				//When not a valid digit
				wrong = true;
			}
			counter++;
		}
		if (wrong == false && status == true)
		{
			Console.Write("\n [" + str_num + "] is duck number");
		}
		else
		{
			Console.Write("\n [" + str_num + "] is not duck number");
		}
	}
	public static void Main(String[] args)
	{
		DuckNumber obj = new DuckNumber();
		//Test string numbers
		String str_num1 = "529043043";
		String str_num2 = "0001234";
		String str_num3 = "00012304";
		String str_num4 = "1000000";
		String str_num5 = "-1000000";
		String str_num6 = "2300200100";
		int size = 0;
		//Test case 1
		size = str_num1.Length;
		obj.is_duck_number(str_num1, size);
		//Test case 2
		size = str_num2.Length;
		obj.is_duck_number(str_num2, size);
		//Test case 3
		size = str_num3.Length;
		obj.is_duck_number(str_num3, size);
		//Test case 4
		size = str_num4.Length;
		obj.is_duck_number(str_num4, size);
		//Test case 5
		size = str_num5.Length;
		obj.is_duck_number(str_num5, size);
		//Test case 6
		size = str_num6.Length;
		obj.is_duck_number(str_num6, size);
	}
}

Output

 [529043043] is duck number
 [0001234] is not duck number
 [00012304] is duck number
 [1000000] is duck number
 [-1000000] is not duck number
 [2300200100] is duck number
<?php
/* 
  Php program 
  Check Whether a number is duck number or not
*/
class DuckNumber
{
	// Determine whether given number is duck number or not
	public	function is_duck_number($str_num, $size)
	{
		if ($size <= 0)
		{
			//When given string number is empty
			return;
		}
		$counter = 0;
		//This is used to check valid positive number
		$wrong = false;
		$status = false;
		// Skip the all beginning zeros
		while ($counter < $size && $str_num[$counter] == '0')
		{
			$counter++;
		}
		while ($counter < $size && $wrong == false)
		{
			if (ord($str_num[$counter]) >= ord('0') && ord($str_num[$counter]) <= ord('9'))
			{
				//Terminate loop when given number always valid number
				if ($str_num[$counter] == '0')
				{
					//We get zero
					$status = true;
				}
			}
			else
			{
				//When not a valid digit
				$wrong = true;
			}
			$counter++;
		}
		if ($wrong == false && $status == true)
		{
			echo "\n [". $str_num ."] is duck number";
		}
		else
		{
			echo "\n [". $str_num ."] is not duck number";
		}
	}
}

function main()
{
	$obj = new DuckNumber();
	//Test string numbers
	$str_num1 = "529043043";
	$str_num2 = "0001234";
	$str_num3 = "00012304";
	$str_num4 = "1000000";
	$str_num5 = "-1000000";
	$str_num6 = "2300200100";
	$size = 0;
	//Test case 1
	$size = strlen($str_num1);
	$obj->is_duck_number($str_num1, $size);
	//Test case 2
	$size = strlen($str_num2);
	$obj->is_duck_number($str_num2, $size);
	//Test case 3
	$size = strlen($str_num3);
	$obj->is_duck_number($str_num3, $size);
	//Test case 4
	$size = strlen($str_num4);
	$obj->is_duck_number($str_num4, $size);
	//Test case 5
	$size = strlen($str_num5);
	$obj->is_duck_number($str_num5, $size);
	//Test case 6
	$size = strlen($str_num6);
	$obj->is_duck_number($str_num6, $size);
}
main();

Output

 [529043043] is duck number
 [0001234] is not duck number
 [00012304] is duck number
 [1000000] is duck number
 [-1000000] is not duck number
 [2300200100] is duck number
/* 
  Node Js program 
  Check Whether a number is duck number or not
*/
class DuckNumber
{
	// Determine whether given number is duck number or not
	is_duck_number(str_num, size)
	{
		if (size <= 0)
		{
			//When given string number is empty
			return;
		}
		var counter = 0;
		//This is used to check valid positive number
		var wrong = false;
		var status = false;
		// Skip the all beginning zeros
		while (counter < size && str_num[counter] == '0')
		{
			counter++;
		}
		while (counter < size && wrong == false)
		{
			if ((str_num[counter]).charCodeAt(0) >= ('0').charCodeAt(0) && (str_num[counter]).charCodeAt(0) <= ('9').charCodeAt(0))
			{
				//Terminate loop when given number always valid number
				if (str_num[counter] == '0')
				{
					//We get zero
					status = true;
				}
			}
			else
			{
				//When not a valid digit
				wrong = true;
			}
			counter++;
		}
		if (wrong == false && status == true)
		{
			process.stdout.write("\n [" + str_num + "] is duck number");
		}
		else
		{
			process.stdout.write("\n [" + str_num + "] is not duck number");
		}
	}
}

function main()
{
	var obj = new DuckNumber();
	//Test string numbers
	var str_num1 = "529043043";
	var str_num2 = "0001234";
	var str_num3 = "00012304";
	var str_num4 = "1000000";
	var str_num5 = "-1000000";
	var str_num6 = "2300200100";
	var size = 0;
	//Test case 1
	size = str_num1.length;
	obj.is_duck_number(str_num1, size);
	//Test case 2
	size = str_num2.length;
	obj.is_duck_number(str_num2, size);
	//Test case 3
	size = str_num3.length;
	obj.is_duck_number(str_num3, size);
	//Test case 4
	size = str_num4.length;
	obj.is_duck_number(str_num4, size);
	//Test case 5
	size = str_num5.length;
	obj.is_duck_number(str_num5, size);
	//Test case 6
	size = str_num6.length;
	obj.is_duck_number(str_num6, size);
}
main();

Output

 [529043043] is duck number
 [0001234] is not duck number
 [00012304] is duck number
 [1000000] is duck number
 [-1000000] is not duck number
 [2300200100] is duck number
#   Python 3 program 
#   Check Whether a number is duck number or not

class DuckNumber :
	#  Determine whether given number is duck number or not
	def is_duck_number(self, str_num, size) :
		if (size <= 0) :
			# When given string number is empty
			return
		
		counter = 0
		# This is used to check valid positive number
		wrong = False
		status = False
		#  Skip the all beginning zeros
		while (counter < size and str_num[counter] == '0') :
			counter += 1
		
		while (counter < size and wrong == False) :
			if (ord(str_num[counter]) >= ord('0') and ord(str_num[counter]) <= ord('9')) :
				# Terminate loop when given number always valid number
				if (str_num[counter] == '0') :
					# We get zero
					status = True
				
			else :
				# When not a valid digit
				wrong = True
			
			counter += 1
		
		if (wrong == False and status == True) :
			print("\n [", str_num ,"] is duck number", end = "")
		else :
			print("\n [", str_num ,"] is not duck number", end = "")
		
	

def main() :
	obj = DuckNumber()
	# Test string numbers
	str_num1 = "529043043"
	str_num2 = "0001234"
	str_num3 = "00012304"
	str_num4 = "1000000"
	str_num5 = "-1000000"
	str_num6 = "2300200100"
	size = 0
	# Test case 1
	size = len(str_num1)
	obj.is_duck_number(str_num1, size)
	# Test case 2
	size = len(str_num2)
	obj.is_duck_number(str_num2, size)
	# Test case 3
	size = len(str_num3)
	obj.is_duck_number(str_num3, size)
	# Test case 4
	size = len(str_num4)
	obj.is_duck_number(str_num4, size)
	# Test case 5
	size = len(str_num5)
	obj.is_duck_number(str_num5, size)
	# Test case 6
	size = len(str_num6)
	obj.is_duck_number(str_num6, size)

if __name__ == "__main__": main()

Output

 [ 529043043 ] is duck number
 [ 0001234 ] is not duck number
 [ 00012304 ] is duck number
 [ 1000000 ] is duck number
 [ -1000000 ] is not duck number
 [ 2300200100 ] is duck number
#   Ruby program 
#   Check Whether a number is duck number or not

class DuckNumber 
	#  Determine whether given number is duck number or not
	def is_duck_number(str_num, size) 
		if (size <= 0) 
			# When given string number is empty
			return
		end

		counter = 0
		# This is used to check valid positive number
		wrong = false
		status = false
		#  Skip the all beginning zeros
		while (counter < size && str_num[counter] == '0') 
			counter += 1
		end

		while (counter < size && wrong == false) 
			if ((str_num[counter]).ord >= ('0').ord && (str_num[counter]).ord <= ('9').ord) 
				# Terminate loop when given number always valid number
				if (str_num[counter] == '0') 
					# We get zero
					status = true
				end

			else 
				# When not a valid digit
				wrong = true
			end

			counter += 1
		end

		if (wrong == false && status == true) 
			print("\n [", str_num ,"] is duck number")
		else 
			print("\n [", str_num ,"] is not duck number")
		end

	end

end

def main() 
	obj = DuckNumber.new()
	# Test string numbers
	str_num1 = "529043043"
	str_num2 = "0001234"
	str_num3 = "00012304"
	str_num4 = "1000000"
	str_num5 = "-1000000"
	str_num6 = "2300200100"
	size = 0
	# Test case 1
	size = str_num1.length()
	obj.is_duck_number(str_num1, size)
	# Test case 2
	size = str_num2.length()
	obj.is_duck_number(str_num2, size)
	# Test case 3
	size = str_num3.length()
	obj.is_duck_number(str_num3, size)
	# Test case 4
	size = str_num4.length()
	obj.is_duck_number(str_num4, size)
	# Test case 5
	size = str_num5.length()
	obj.is_duck_number(str_num5, size)
	# Test case 6
	size = str_num6.length()
	obj.is_duck_number(str_num6, size)
end

main()

Output

 [529043043] is duck number
 [0001234] is not duck number
 [00012304] is duck number
 [1000000] is duck number
 [-1000000] is not duck number
 [2300200100] is duck number
/* 
  Scala program 
  Check Whether a number is duck number or not
*/
class DuckNumber
{
	// Determine whether given number is duck number or not
	def is_duck_number(str_num: String, size: Int): Unit = {
		if (size <= 0)
		{
			//When given string number is empty
			return;
		}
		var counter: Int = 0;
		//This is used to check valid positive number
		var wrong: Boolean = false;
		var status: Boolean = false;
		// Skip the all beginning zeros
		while (counter < size && str_num(counter) == '0')
		{
			counter += 1;
		}
		while (counter < size && wrong == false)
		{
			if (str_num(counter) >= '0' && str_num(counter) <= '9')
			{
				//Terminate loop when given number always valid number
				if (str_num(counter) == '0')
				{
					//We get zero
					status = true;
				}
			}
			else
			{
				//When not a valid digit
				wrong = true;
			}
			counter += 1;
		}
		if (wrong == false && status == true)
		{
			print("\n [" + str_num + "] is duck number");
		}
		else
		{
			print("\n [" + str_num + "] is not duck number");
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var obj: DuckNumber = new DuckNumber();
		//Test string numbers
		var str_num1: String = "529043043";
		var str_num2: String = "0001234";
		var str_num3: String = "00012304";
		var str_num4: String = "1000000";
		var str_num5: String = "-1000000";
		var str_num6: String = "2300200100";
		var size: Int = 0;
		//Test case 1
		size = str_num1.length();
		obj.is_duck_number(str_num1, size);
		//Test case 2
		size = str_num2.length();
		obj.is_duck_number(str_num2, size);
		//Test case 3
		size = str_num3.length();
		obj.is_duck_number(str_num3, size);
		//Test case 4
		size = str_num4.length();
		obj.is_duck_number(str_num4, size);
		//Test case 5
		size = str_num5.length();
		obj.is_duck_number(str_num5, size);
		//Test case 6
		size = str_num6.length();
		obj.is_duck_number(str_num6, size);
	}
}

Output

 [529043043] is duck number
 [0001234] is not duck number
 [00012304] is duck number
 [1000000] is duck number
 [-1000000] is not duck number
 [2300200100] is duck number
/* 
  Swift 4 program 
  Check Whether a number is duck number or not
*/
class DuckNumber
{
	// Determine whether given number is duck number or not
	func is_duck_number(_ text: String, _ size: Int)
	{
		if (size <= 0)
		{
			//When given string number is empty
			return;
		}
      	let str_num = Array(text);
		var counter: Int = 0;
		//This is used to check valid positive number
		var wrong: Bool = false;
		var status: Bool = false;
		// Skip the all beginning zeros
		while (counter < size && str_num[counter] == "0")
		{
			counter += 1;
		}
		while (counter < size && wrong == false)
		{
			if (str_num[counter] >= "0" && str_num[counter] <= "9")
			{
				//Terminate loop when given number always valid number
				if (str_num[counter] == "0")
				{
					//We get zero
					status = true;
				}
			}
			else
			{
				//When not a valid digit
				wrong = true;
			}
			counter += 1;
		}
		if (wrong == false && status == true)
		{
			print("\n [", text ,"] is duck number", terminator: "");
		}
		else
		{
			print("\n [", text ,"] is not duck number", terminator: "");
		}
	}
}
func main()
{
	let obj: DuckNumber = DuckNumber();
	//Test string numbers
	let str_num1: String = "529043043";
	let str_num2: String = "0001234";
	let str_num3: String = "00012304";
	let str_num4: String = "1000000";
	let str_num5: String = "-1000000";
	let str_num6: String = "2300200100";
	var size: Int = 0;
	//Test case 1
	size = str_num1.count;
	obj.is_duck_number(str_num1, size);
	//Test case 2
	size = str_num2.count;
	obj.is_duck_number(str_num2, size);
	//Test case 3
	size = str_num3.count;
	obj.is_duck_number(str_num3, size);
	//Test case 4
	size = str_num4.count;
	obj.is_duck_number(str_num4, size);
	//Test case 5
	size = str_num5.count;
	obj.is_duck_number(str_num5, size);
	//Test case 6
	size = str_num6.count;
	obj.is_duck_number(str_num6, size);
}
main();

Output

 [ 529043043 ] is duck number
 [ 0001234 ] is not duck number
 [ 00012304 ] is duck number
 [ 1000000 ] is duck number
 [ -1000000 ] is not duck number
 [ 2300200100 ] is duck number

Time Complexity

Let's analyze the time complexity of the given algorithm. In the worst case, we need to iterate through the entire string to check if all digits are valid and if there is at least one zero. Therefore, the time complexity is O(n), where n is the number of digits in the input string.

Resultant Output Explanation

The provided program uses the is_duck_number function to check whether each given number is a Duck Number or not. The program prints the result for each test case.

  • For the input "529043043", the output is "[529043043] is duck number" because the number contains a zero and all other digits are non-zero.

  • For the input "0001234", the output is "[0001234] is not duck number" as there are leading zeros and not all other digits are non-zero.

  • For the input "00012304", the output is "[00012304] is duck number" as there is a zero and all other digits are non-zero.

  • For the input "1000000", the output is "[1000000] is duck number" as there is a zero and all other digits are non-zero.

  • For the input "-1000000", the output is "[-1000000] is not duck number" as the number is not positive.

  • For the input "2300200100", the output is "[2300200100] is duck number" as there is a zero and all other digits are non-zero.

The program correctly identifies the Duck Numbers among the given test cases and outputs the results accordingly.

Last updated on by Kalkicode




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