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Check if string contains only 0 and 1

Here given code implementation process.

// C Program for
// Check if string contains only 0 and 1
#include <stdio.h>
#include <string.h>

void isBinaryText(char *text)
{
	int n = strlen(text);
	printf("\n Given text  : %s ", text);
	int i = 0;
	while (i < n)
	{
		if (!(text[i] == '0' || text[i] == '1'))
		{
			printf("\n  No ");
			return;
		}
		i++;
	}
	printf("\n  Yes ");
}
int main(int argc, char const *argv[])
{
	// Test
	isBinaryText("0200011");
	isBinaryText("010100111");
	return 0;
}

Output

 Given text  : 0200011
  No
 Given text  : 010100111
  Yes
// Java program for
// Check if string contains only 0 and 1
public class BinaryText
{
	public void isBinaryText(String text)
	{
		int n = text.length();
		System.out.print("\n Given text : " + text);
		int i = 0;
		while (i < n)
		{
			if (!(text.charAt(i) == '0' || text.charAt(i) == '1'))
			{
				System.out.print("\n No ");
				return;
			}
			i++;
		}
		System.out.print("\n Yes ");
	}
	public static void main(String[] args)
	{
		BinaryText task = new BinaryText();
		// Test
		task.isBinaryText("0200011");
		task.isBinaryText("010100111");
	}
}

Output

 Given text : 0200011
 No
 Given text : 010100111
 Yes
// Include header file
#include <iostream>
#include <string>

using namespace std;
// C++ program for
// Check if string contains only 0 and 1
class BinaryText
{
	public: void isBinaryText(string text)
	{
		int n = text.length();
		cout << "\n Given text : " << text;
		int i = 0;
		while (i < n)
		{
			if (!(text[i] == '0' || text[i] == '1'))
			{
				cout << "\n No ";
				return;
			}
			i++;
		}
		cout << "\n Yes ";
	}
};
int main()
{
	BinaryText *task = new BinaryText();
	// Test
	task->isBinaryText("0200011");
	task->isBinaryText("010100111");
	return 0;
}

Output

 Given text : 0200011
 No
 Given text : 010100111
 Yes
package main
import "fmt"
// Go program for
// Check if string contains only 0 and 1
type BinaryText struct {}
func getBinaryText() * BinaryText {
	var me *BinaryText = &BinaryText {}
	return me
}
func(this BinaryText) isBinaryText(text string) {
	var n int = len(text)
	fmt.Print("\n Given text : ", text)
	var i int = 0
	for (i < n) {
		if !(text[i] == '0' || text[i] == '1') {
			fmt.Print("\n No ")
			return
		}
		i++
	}
	fmt.Print("\n Yes ")
}
func main() {
	var task * BinaryText = getBinaryText()
	// Test
	task.isBinaryText("0200011")
	task.isBinaryText("010100111")
}

Output

 Given text : 0200011
 No
 Given text : 010100111
 Yes
// Include namespace system
using System;
// Csharp program for
// Check if string contains only 0 and 1
public class BinaryText
{
	public void isBinaryText(String text)
	{
		int n = text.Length;
		Console.Write("\n Given text : " + text);
		int i = 0;
		while (i < n)
		{
			if (!(text[i] == '0' || text[i] == '1'))
			{
				Console.Write("\n No ");
				return;
			}
			i++;
		}
		Console.Write("\n Yes ");
	}
	public static void Main(String[] args)
	{
		BinaryText task = new BinaryText();
		// Test
		task.isBinaryText("0200011");
		task.isBinaryText("010100111");
	}
}

Output

 Given text : 0200011
 No
 Given text : 010100111
 Yes
<?php
// Php program for
// Check if string contains only 0 and 1
class BinaryText
{
	public	function isBinaryText($text)
	{
		$n = strlen($text);
		echo("\n Given text : ".$text);
		$i = 0;
		while ($i < $n)
		{
			if (!($text[$i] == '0' || $text[$i] == '1'))
			{
				echo("\n No ");
				return;
			}
			$i++;
		}
		echo("\n Yes ");
	}
}

function main()
{
	$task = new BinaryText();
	// Test
	$task->isBinaryText("0200011");
	$task->isBinaryText("010100111");
}
main();

Output

 Given text : 0200011
 No
 Given text : 010100111
 Yes
// Node JS program for
// Check if string contains only 0 and 1
class BinaryText
{
	isBinaryText(text)
	{
		var n = text.length;
		process.stdout.write("\n Given text : " + text);
		var i = 0;
		while (i < n)
		{
			if (!(text.charAt(i) == '0' || text.charAt(i) == '1'))
			{
				process.stdout.write("\n No ");
				return;
			}
			i++;
		}
		process.stdout.write("\n Yes ");
	}
}

function main()
{
	var task = new BinaryText();
	// Test
	task.isBinaryText("0200011");
	task.isBinaryText("010100111");
}
main();

Output

 Given text : 0200011
 No
 Given text : 010100111
 Yes
#  Python 3 program for
#  Check if string contains only 0 and 1
class BinaryText :
	def isBinaryText(self, text) :
		n = len(text)
		print("\n Given text : ", text, end = "")
		i = 0
		while (i < n) :
			if (not(text[i] == '0'
					or text[i] == '1')) :
				print("\n No ", end = "")
				return
			
			i += 1
		
		print("\n Yes ", end = "")
	

def main() :
	task = BinaryText()
	#  Test
	task.isBinaryText("0200011")
	task.isBinaryText("010100111")

if __name__ == "__main__": main()

Output

 Given text :  0200011
 No
 Given text :  010100111
 Yes
#  Ruby program for
#  Check if string contains only 0 and 1
class BinaryText 
	def isBinaryText(text) 
		n = text.length
		print("\n Given text : ", text)
		i = 0
		while (i < n) 
			if (!(text[i] == '0' || text[i] == '1')) 
				print("\n No ")
				return
			end

			i += 1
		end

		print("\n Yes ")
	end

end

def main() 
	task = BinaryText.new()
	#  Test
	task.isBinaryText("0200011")
	task.isBinaryText("010100111")
end

main()

Output

 Given text : 0200011
 No 
 Given text : 010100111
 Yes 
import scala.collection.mutable._;
// Scala program for
// Check if string contains only 0 and 1
class BinaryText()
{
	def isBinaryText(text: String): Unit = {
		var n: Int = text.length();
		print("\n Given text : " + text);
		var i: Int = 0;
		while (i < n)
		{
			if (!(text.charAt(i) == '0' || text.charAt(i) == '1'))
			{
				print("\n No ");
				return;
			}
			i += 1;
		}
		print("\n Yes ");
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var task: BinaryText = new BinaryText();
		// Test
		task.isBinaryText("0200011");
		task.isBinaryText("010100111");
	}
}

Output

 Given text : 0200011
 No
 Given text : 010100111
 Yes
import Foundation;
// Swift 4 program for
// Check if string contains only 0 and 1
class BinaryText
{
	func isBinaryText(_ data: String)
	{
      	let text = Array(data);
		let n: Int = text.count;
		print("\n Given text : ", data, terminator: "");
		var i: Int = 0;
		while (i < n)
		{
			if (!(text[i] == "0" || text[i] == "1"))
			{
				print("\n No ", terminator: "");
				return;
			}
			i += 1;
		}
		print("\n Yes ", terminator: "");
	}
}
func main()
{
	let task: BinaryText = BinaryText();
	// Test
	task.isBinaryText("0200011");
	task.isBinaryText("010100111");
}
main();

Output

 Given text :  0200011
 No
 Given text :  010100111
 Yes
// Kotlin program for
// Check if string contains only 0 and 1
class BinaryText
{
	fun isBinaryText(text: String): Unit
	{
		val n: Int = text.length;
		print("\n Given text : " + text);
		var i: Int = 0;
		while (i < n)
		{
			if (!(text.get(i) == '0' || text.get(i) == '1'))
			{
				print("\n No ");
				return;
			}
			i += 1;
		}
		print("\n Yes ");
	}
}
fun main(args: Array < String > ): Unit
{
	val task: BinaryText = BinaryText();
	// Test
	task.isBinaryText("0200011");
	task.isBinaryText("010100111");
}

Output

 Given text : 0200011
 No
 Given text : 010100111
 Yes
Last updated on by Kalkicode




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