Check if number is a prime power number

Here given code implementation process.

// C program
// Check if number is a prime power number
#include <stdio.h>
#include <math.h>
#define SIZE 1000001

//Find all prime numbers under 1000001 
void sieve_of_eratosthenes(int collection[])
{
	// Loop controlling variables
	int i = 0;
	int j = 1;
	// Initial two numbers are not prime (0 and 1)
	collection[i] = 0;
	collection[j] = 0;
	// Set the initial (2 to n element is prime)
	for (i = 2; i < SIZE; ++i)
	{
		collection[i] = 1;
	}
	// Initial 0 and 1 are not prime
	// We start to 2
	for (i = 2; i * i < SIZE; ++i)
	{
		if (collection[i] == 1)
		{
			//When i is prime number
			//Modify the prime status of all next multiplier of location i
			for (j = i * i; j < SIZE; j += i)
			{
				collection[j] = 0;
			}
		}
	}
}
void is_prime_power(int collection[], int num)
{
	int status = 0;
	int num_base = 0;
	int num_power = 0;
	int temp = 0;
	int sqrt_value = sqrt(num);
	for (int i = 2; i <= sqrt_value && num_base == 0; ++i)
	{
		if (collection[i] == 1 && num % i == 0)
		{
			// When [i] is prime number and number is divisible of i
			// We get base
			num_base = i;
			temp = num;
			// Find power
			while (temp % i == 0)
			{
				num_power++;
				temp = temp / i;
			}
			if (temp == 1)
			{
				status = 1;
			}
		}
	}
	if (status == 1)
	{
		printf("\n Number [%d] is prime power number of (%d^%d)", num, num_base, num_power);
	}
	else
	{
		printf("\n Number [%d] is not prime power number", num);
	}
}
int main()
{
	//This is used to store prime number status
	int collection[SIZE];
	//Find find prime number
	sieve_of_eratosthenes(collection);
	//Test case
	is_prime_power(collection, 9);
	is_prime_power(collection, 1331);
	is_prime_power(collection, 2187);
	is_prime_power(collection, 81);
	is_prime_power(collection, 452);
	is_prime_power(collection, 361);
	is_prime_power(collection, 512);
	return 0;
}

Output

 Number [9] is prime power number of (3^2)
 Number [1331] is prime power number of (11^3)
 Number [2187] is prime power number of (3^7)
 Number [81] is prime power number of (3^4)
 Number [452] is not prime power number
 Number [361] is prime power number of (19^2)
 Number [512] is prime power number of (2^9)
// Java program 
// Check if number is a prime power number
class PrimePower
{
	//Determine if the given number is the prime base power or not
	public void is_prime_power(boolean[] collection, int num)
	{
		boolean status = false;
		//Define useful resultant variable
		int num_base = 0;
		int num_power = 0;
		int temp = 0;
		int sqrt_value = (int) Math.sqrt(num);
		for (int i = 2; i <= sqrt_value && num_base == 0; ++i)
		{
			if (collection[i] == true && num % i == 0)
			{
				// When [i] is prime number and number is divisible of i
				// We get base
				num_base = i;
				temp = num;
				// Find power
				while (temp % i == 0)
				{
					num_power++;
					temp = temp / i;
				}
				if (temp == 1)
				{
					status = true;
				}
			}
		}
		if (status == true)
		{
			System.out.print("\n Number [" + num + "] is prime power number of (" + num_base + "^" + num_power + ")");
		}
		else
		{
			System.out.print("\n Number [" + num + "] is not prime power number");
		}
	}
	//Find all prime numbers under 1000001 
	public void sieve_of_eratosthenes(boolean[] collection, int size)
	{
		// Loop controlling variables
		int i = 0;
		int j = 1;
		// Initial two numbers are not prime (0 and 1)
		collection[i] = false;
		collection[j] = false;
		// Set the initial (2 to n element is prime)
		for (i = 2; i < size; ++i)
		{
			collection[i] = true;
		}
		// Initial 0 and 1 are not prime
		// We start to 2
		for (i = 2; i * i < size; ++i)
		{
			if (collection[i] == true)
			{
				//When i is prime number
				//Modify the prime status of all next multiplier of location i
				for (j = i * i; j < size; j += i)
				{
					collection[j] = false;
				}
			}
		}
	}
	public static void main(String[] args)
	{
		PrimePower obj = new PrimePower();
		int size = 1000001;
		//This is used to store prime number status
		boolean[] collection = new boolean[size];
		//Find find prime number
		obj.sieve_of_eratosthenes(collection, size);
		//Test case
		obj.is_prime_power(collection, 9);
		obj.is_prime_power(collection, 1331);
		obj.is_prime_power(collection, 2187);
		obj.is_prime_power(collection, 81);
		obj.is_prime_power(collection, 452);
		obj.is_prime_power(collection, 361);
		obj.is_prime_power(collection, 512);
	}
}

Output

 Number [9] is prime power number of (3^2)
 Number [1331] is prime power number of (11^3)
 Number [2187] is prime power number of (3^7)
 Number [81] is prime power number of (3^4)
 Number [452] is not prime power number
 Number [361] is prime power number of (19^2)
 Number [512] is prime power number of (2^9)
//Include header file
#include <iostream>

#include<math.h>

using namespace std;
// C++ program 
// Check if number is a prime power number
class PrimePower
{
	public:
		//Determine if the given number is the prime base power or not
		void is_prime_power(bool collection[], int num)
		{
			bool status = false;
			//Define useful resultant variable
			int num_base = 0;
			int num_power = 0;
			int temp = 0;
			int sqrt_value = (int) sqrt(num);
			for (int i = 2; i <= sqrt_value && num_base == 0; ++i)
			{
				if (collection[i] == true && num % i == 0)
				{
					// When [i] is prime number and number is divisible of i
					// We get base
					num_base = i;
					temp = num;
					// Find power
					while (temp % i == 0)
					{
						num_power++;
						temp = temp / i;
					}
					if (temp == 1)
					{
						status = true;
					}
				}
			}
			if (status == true)
			{
				cout << "\n Number [" << num << "] is prime power number of (" << num_base << "^" << num_power << ")";
			}
			else
			{
				cout << "\n Number [" << num << "] is not prime power number";
			}
		}
	//Find all prime numbers under 1000001 
	void sieve_of_eratosthenes(bool collection[], int size)
	{
		// Loop controlling variables
		int i = 0;
		int j = 1;
		// Initial two numbers are not prime (0 and 1)
		collection[i] = false;
		collection[j] = false;
		// Set the initial (2 to n element is prime)
		for (i = 2; i < size; ++i)
		{
			collection[i] = true;
		}
		// Initial 0 and 1 are not prime
		// We start to 2
		for (i = 2; i *i < size; ++i)
		{
			if (collection[i] == true)
			{
				//When i is prime number
				//Modify the prime status of all next multiplier of location i
				for (j = i *i; j < size; j += i)
				{
					collection[j] = false;
				}
			}
		}
	}
};
int main()
{
	PrimePower obj = PrimePower();
	int size = 1000001;
	//This is used to store prime number status
	bool collection[size];
	//Find find prime number
	obj.sieve_of_eratosthenes(collection, size);
	//Test case
	obj.is_prime_power(collection, 9);
	obj.is_prime_power(collection, 1331);
	obj.is_prime_power(collection, 2187);
	obj.is_prime_power(collection, 81);
	obj.is_prime_power(collection, 452);
	obj.is_prime_power(collection, 361);
	obj.is_prime_power(collection, 512);
	return 0;
}

Output

 Number [9] is prime power number of (3^2)
 Number [1331] is prime power number of (11^3)
 Number [2187] is prime power number of (3^7)
 Number [81] is prime power number of (3^4)
 Number [452] is not prime power number
 Number [361] is prime power number of (19^2)
 Number [512] is prime power number of (2^9)
//Include namespace system
using System;
// C# program 
// Check if number is a prime power number
class PrimePower
{
	//Determine if the given number is the prime base power or not
	public void is_prime_power(Boolean[] collection, int num)
	{
		Boolean status = false;
		//Define useful resultant variable
		int num_base = 0;
		int num_power = 0;
		int temp = 0;
		int sqrt_value = (int) Math.Sqrt(num);
		for (int i = 2; i <= sqrt_value && num_base == 0; ++i)
		{
			if (collection[i] == true && num % i == 0)
			{
				// When [i] is prime number and number is divisible of i
				// We get base
				num_base = i;
				temp = num;
				// Find power
				while (temp % i == 0)
				{
					num_power++;
					temp = temp / i;
				}
				if (temp == 1)
				{
					status = true;
				}
			}
		}
		if (status == true)
		{
			Console.Write("\n Number [" + num + "] is prime power number of (" + num_base + "^" + num_power + ")");
		}
		else
		{
			Console.Write("\n Number [" + num + "] is not prime power number");
		}
	}
	//Find all prime numbers under 1000001 
	public void sieve_of_eratosthenes(Boolean[] collection, int size)
	{
		// Loop controlling variables
		int i = 0;
		int j = 1;
		// Initial two numbers are not prime (0 and 1)
		collection[i] = false;
		collection[j] = false;
		// Set the initial (2 to n element is prime)
		for (i = 2; i < size; ++i)
		{
			collection[i] = true;
		}
		// Initial 0 and 1 are not prime
		// We start to 2
		for (i = 2; i * i < size; ++i)
		{
			if (collection[i] == true)
			{
				//When i is prime number
				//Modify the prime status of all next multiplier of location i
				for (j = i * i; j < size; j += i)
				{
					collection[j] = false;
				}
			}
		}
	}
	public static void Main(String[] args)
	{
		PrimePower obj = new PrimePower();
		int size = 1000001;
		//This is used to store prime number status
		Boolean[] collection = new Boolean[size];
		//Find find prime number
		obj.sieve_of_eratosthenes(collection, size);
		//Test case
		obj.is_prime_power(collection, 9);
		obj.is_prime_power(collection, 1331);
		obj.is_prime_power(collection, 2187);
		obj.is_prime_power(collection, 81);
		obj.is_prime_power(collection, 452);
		obj.is_prime_power(collection, 361);
		obj.is_prime_power(collection, 512);
	}
}

Output

 Number [9] is prime power number of (3^2)
 Number [1331] is prime power number of (11^3)
 Number [2187] is prime power number of (3^7)
 Number [81] is prime power number of (3^4)
 Number [452] is not prime power number
 Number [361] is prime power number of (19^2)
 Number [512] is prime power number of (2^9)
<?php
// Php program 
// Check if number is a prime power number
class PrimePower
{
    //Determine if the given number is the prime base power or not
    public  function is_prime_power( & $collection, $num)
    {
        $status = false;
        //Define useful resultant variable
        $num_base = 0;
        $num_power = 0;
        $temp = 0;
        $sqrt_value = (sqrt($num));
        for ($i = 2; $i <= $sqrt_value && $num_base == 0; ++$i)
        {
            if ($collection[$i] == true && $num % $i == 0)
            {
                // When [i] is prime number and number is divisible of i
                // We get base
                $num_base = $i;
                $temp = $num;
                // Find power
                while ($temp % $i == 0)
                {
                    $num_power++;
                    $temp = intval($temp / $i);
                }
                if ($temp == 1)
                {
                    $status = true;
                }
            }
        }
        if ($status == true)
        {
            echo "\n Number [". $num ."] is prime power number of (". $num_base ."^". $num_power .")";
        }
        else
        {
            echo "\n Number [". $num ."] is not prime power number";
        }
    }
    //Find all prime numbers under 1000001 
    public  function sieve_of_eratosthenes( & $collection, $size)
    {
        // Loop controlling variables
        $i = 0;
        $j = 1;
        // Initial two numbers are not prime (0 and 1)
        $collection[$i] = false;
        $collection[$j] = false;
        // Initial 0 and 1 are not prime
        // We start to 2
        for ($i = 2; $i * $i < $size; ++$i)
        {
            if ($collection[$i] == true)
            {
                //When i is prime number
                //Modify the prime status of all next multiplier of location i
                for ($j = $i * $i; $j < $size; $j += $i)
                {
                    $collection[$j] = false;
                }
            }
        }
    }
}

function main()
{
    $obj = new PrimePower();
    $size = 1000001;
    //This is used to store prime number status
    $collection = array_fill(0, $size, true);
    //Find find prime number
    $obj->sieve_of_eratosthenes($collection, $size);
    //Test case
    $obj->is_prime_power($collection, 9);
    $obj->is_prime_power($collection, 1331);
    $obj->is_prime_power($collection, 2187);
    $obj->is_prime_power($collection, 81);
    $obj->is_prime_power($collection, 452);
    $obj->is_prime_power($collection, 361);
    $obj->is_prime_power($collection, 512);
}
main();

Output

 Number [9] is prime power number of (3^2)
 Number [1331] is prime power number of (11^3)
 Number [2187] is prime power number of (3^7)
 Number [81] is prime power number of (3^4)
 Number [452] is not prime power number
 Number [361] is prime power number of (19^2)
 Number [512] is prime power number of (2^9)
// Node Js program 
// Check if number is a prime power number

class PrimePower
{
	//Determine if the given number is the prime base power or not
	is_prime_power(collection, num)
	{
		var status = false;
		//Define useful resultant variable
		var num_base = 0;
		var num_power = 0;
		var temp = 0;
		var sqrt_value = (Math.sqrt(num));
		for (var i = 2; i <= sqrt_value && num_base == 0; ++i)
		{
			if (collection[i] == true && num % i == 0)
			{
				// When [i] is prime number and number is divisible of i
				// We get base
				num_base = i;
				temp = num;
				// Find power
				while (temp % i == 0)
				{
					num_power++;
					temp = parseInt(temp / i);
				}
				if (temp == 1)
				{
					status = true;
				}
			}
		}
		if (status == true)
		{
			process.stdout.write("\n Number [" + num + "] is prime power number of (" + num_base + "^" + num_power + ")");
		}
		else
		{
			process.stdout.write("\n Number [" + num + "] is not prime power number");
		}
	}
	//Find all prime numbers under 1000001 
	sieve_of_eratosthenes(collection, size)
	{
		// Loop controlling variables
		var i = 0;
		var j = 1;
		// Initial two numbers are not prime (0 and 1)
		collection[i] = false;
		collection[j] = false;
		// Initial 0 and 1 are not prime
		// We start to 2
		for (i = 2; i * i < size; ++i)
		{
			if (collection[i] == true)
			{
				//When i is prime number
				//Modify the prime status of all next multiplier of location i
				for (j = i * i; j < size; j += i)
				{
					collection[j] = false;
				}
			}
		}
	}
}

function main()
{
	var obj = new PrimePower();
	var size = 1000001;
	//This is used to store prime number status
	var collection = Array(size).fill(true);
	//Find find prime number
	obj.sieve_of_eratosthenes(collection, size);
	//Test case
	obj.is_prime_power(collection, 9);
	obj.is_prime_power(collection, 1331);
	obj.is_prime_power(collection, 2187);
	obj.is_prime_power(collection, 81);
	obj.is_prime_power(collection, 452);
	obj.is_prime_power(collection, 361);
	obj.is_prime_power(collection, 512);
}
main();

Output

 Number [9] is prime power number of (3^2)
 Number [1331] is prime power number of (11^3)
 Number [2187] is prime power number of (3^7)
 Number [81] is prime power number of (3^4)
 Number [452] is not prime power number
 Number [361] is prime power number of (19^2)
 Number [512] is prime power number of (2^9)
import math

#  Python 3 program 
#  Check if number is a prime power number

class PrimePower :
	# Determine if the given number is the prime base power or not
	def is_prime_power(self, collection, num) :
		status = False
		# Define useful resultant variable
		num_base = 0
		num_power = 0
		temp = 0
		sqrt_value = (math.sqrt(num))
		i = 2
		while (i <= sqrt_value and num_base == 0) :
			if (collection[i] == True and num % i == 0) :
				#  When [i] is prime number and number is divisible of i
				#  We get base
				num_base = i
				temp = num
				#  Find power
				while (temp % i == 0) :
					num_power += 1
					temp = int(temp / i)
				
				if (temp == 1) :
					status = True
				
			
			i += 1
		
		if (status == True) :
			print("\n Number [{0}] is prime power number of ({1}^{2})".format(num,num_base,num_power), end = "")
		else :
			print("\n Number [{0}] is not prime power number".format(num), end = "")
		
	
	# Find all prime numbers under 1000001 
	def sieve_of_eratosthenes(self, collection, size) :
		#  Loop controlling variables
		i = 0
		j = 1
		#  Initial two numbers are not prime (0 and 1)
		collection[i] = False
		collection[j] = False
		#  Initial 0 and 1 are not prime
		#  We start to 2
		i = 2
		while (i * i < size) :
			if (collection[i] == True) :
				# When i is prime number
				# Modify the prime status of all next multiplier of location i
				j = i * i
				while (j < size) :
					collection[j] = False
					j += i
				
			
			i += 1
		
	

def main() :
	obj = PrimePower()
	size = 1000001
	# This is used to store prime number status
	collection = [True] * (size)
	# Find find prime number
	obj.sieve_of_eratosthenes(collection, size)
	# Test case
	obj.is_prime_power(collection, 9)
	obj.is_prime_power(collection, 1331)
	obj.is_prime_power(collection, 2187)
	obj.is_prime_power(collection, 81)
	obj.is_prime_power(collection, 452)
	obj.is_prime_power(collection, 361)
	obj.is_prime_power(collection, 512)

if __name__ == "__main__": main()

Output

 Number [9] is prime power number of (3^2)
 Number [1331] is prime power number of (11^3)
 Number [2187] is prime power number of (3^7)
 Number [81] is prime power number of (3^4)
 Number [452] is not prime power number
 Number [361] is prime power number of (19^2)
 Number [512] is prime power number of (2^9)
#  Ruby program 
#  Check if number is a prime power number
class PrimePower 
	# Determine if the given number is the prime base power or not
	def is_prime_power(collection, num) 
		status = false
		# Define useful resultant variable
		num_base = 0
		num_power = 0
		temp = 0
		sqrt_value = (Math.sqrt(num)).to_i
		i = 2
		while (i <= sqrt_value && num_base == 0) 
			if (collection[i] == true && num % i == 0) 
				#  When [i] is prime number and number is divisible of i
				#  We get base
				num_base = i
				temp = num
				#  Find power
				while (temp % i == 0) 
					num_power += 1
					temp = temp / i
				end

				if (temp == 1) 
					status = true
				end

			end

			i += 1
		end

		if (status == true) 
			print("\n Number [", num ,"] is prime power number of (", num_base ,"^", num_power ,")")
		else 
			print("\n Number [", num ,"] is not prime power number")
		end

	end

	# Find all prime numbers under 1000001 
	def sieve_of_eratosthenes(collection, size) 
		#  Loop controlling variables
		i = 0
		j = 1
		#  Initial two numbers are not prime (0 and 1)
		collection[i] = false
		collection[j] = false
		#  Initial 0 and 1 are not prime
		#  We start to 2
		i = 2
		while (i * i < size) 
			if (collection[i] == true) 
				# When i is prime number
				# Modify the prime status of all next multiplier of location i
				j = i * i
				while (j < size) 
					collection[j] = false
					j += i
				end

			end

			i += 1
		end

	end

end

def main() 
	obj = PrimePower.new()
	size = 1000001
	# This is used to store prime number status
	collection = Array.new(size) {true}
	# Find find prime number
	obj.sieve_of_eratosthenes(collection, size)
	# Test case
	obj.is_prime_power(collection, 9)
	obj.is_prime_power(collection, 1331)
	obj.is_prime_power(collection, 2187)
	obj.is_prime_power(collection, 81)
	obj.is_prime_power(collection, 452)
	obj.is_prime_power(collection, 361)
	obj.is_prime_power(collection, 512)
end

main()

Output

 Number [9] is prime power number of (3^2)
 Number [1331] is prime power number of (11^3)
 Number [2187] is prime power number of (3^7)
 Number [81] is prime power number of (3^4)
 Number [452] is not prime power number
 Number [361] is prime power number of (19^2)
 Number [512] is prime power number of (2^9)
// Scala program 
// Check if number is a prime power number
class PrimePower
{
	//Determine if the given number is the prime base power or not
	def is_prime_power(collection: Array[Boolean], num: Int): Unit = {
		var status: Boolean = false;
		//Define useful resultant variable
		var num_base: Int = 0;
		var num_power: Int = 0;
		var temp: Int = 0;
		var sqrt_value: Int = (Math.sqrt(num)).toInt;
		var i: Int = 2;
		while (i <= sqrt_value && num_base == 0)
		{
			if (collection(i) == true && num % i == 0)
			{
				// When [i] is prime number and number is divisible of i
				// We get base
				num_base = i;
				temp = num;
				// Find power
				while (temp % i == 0)
				{
					num_power += 1;
					temp = (temp / i).toInt;
				}
				if (temp == 1)
				{
					status = true;
				}
			}
			i += 1;
		}
		if (status == true)
		{
			print("\n Number [" + num + "] is prime power number of (" + num_base + "^" + num_power + ")");
		}
		else
		{
			print("\n Number [" + num + "] is not prime power number");
		}
	}
	//Find all prime numbers under 1000001 
	def sieve_of_eratosthenes(collection: Array[Boolean], size: Int): Unit = {
		// Loop controlling variables
		var i: Int = 0;
		var j: Int = 1;
		// Initial two numbers are not prime (0 and 1)
		collection(i) = false;
		collection(j) = false;
		// Initial 0 and 1 are not prime
		// We start to 2
		i = 2;
		while (i * i < size)
		{
			if (collection(i) == true)
			{
				//When i is prime number
				//Modify the prime status of all next multiplier of location i
				j = i * i;
				while (j < size)
				{
					collection(j) = false;
					j += i;
				}
			}
			i += 1;
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var obj: PrimePower = new PrimePower();
		var size: Int = 1000001;
		//This is used to store prime number status
		var collection: Array[Boolean] = Array.fill[Boolean](size)(true);
		//Find find prime number
		obj.sieve_of_eratosthenes(collection, size);
		//Test case
		obj.is_prime_power(collection, 9);
		obj.is_prime_power(collection, 1331);
		obj.is_prime_power(collection, 2187);
		obj.is_prime_power(collection, 81);
		obj.is_prime_power(collection, 452);
		obj.is_prime_power(collection, 361);
		obj.is_prime_power(collection, 512);
	}
}

Output

 Number [9] is prime power number of (3^2)
 Number [1331] is prime power number of (11^3)
 Number [2187] is prime power number of (3^7)
 Number [81] is prime power number of (3^4)
 Number [452] is not prime power number
 Number [361] is prime power number of (19^2)
 Number [512] is prime power number of (2^9)
import Foundation
// Swift 4 program 
// Check if number is a prime power number
class PrimePower
{
	//Determine if the given number is the prime base power or not
	func is_prime_power(_ collection: [Bool], _ num: Int)
	{
		var status: Bool = false;
		//Define useful resultant variable
		var num_base: Int = 0;
		var num_power: Int = 0;
		var temp: Int = 0;
		let sqrt_value: Int = Int(sqrt(Double(num)));
		var i: Int = 2;
		while (i <= sqrt_value && num_base == 0)
		{
			if (collection[i] == true && num % i == 0)
			{
				// When [i]is prime number and number is divisible of i
				// We get base
				num_base = i;
				temp = num;
				// Find power
				while (temp % i == 0)
				{
					num_power += 1;
					temp = temp / i;
				}
				if (temp == 1)
				{
					status = true;
				}
			}
			i += 1;
		}
		if (status == true)
		{
			print("\n Number [", num, "] is prime power number of (", num_base, "^", num_power, ")", terminator: "");
		}
		else
		{
			print("\n Number [", num, "] is not prime power number", terminator: "");
		}
	}
	//Find all prime numbers under 1000001 
	func sieve_of_eratosthenes(_ collection: inout[Bool], _ size: Int)
	{
		// Loop controlling variables
		var i: Int = 0;
		var j: Int = 1;
		// Initial two numbers are not prime (0 and 1)
		collection[i] = false;
		collection[j] = false;
		// Initial 0 and 1 are not prime
		// We start to 2
		i = 2;
		while (i * i < size)
		{
			if (collection[i] == true)
			{
				//When i is prime number
				//Modify the prime status of all next multiplier of location i
				j = i * i;
				while (j < size)
				{
					collection[j] = false;
					j += i;
				}
			}
			i += 1;
		}
	}
}
func main()
{
	let obj: PrimePower = PrimePower();
	let size: Int = 1000001;
	//This is used to store prime number status
	var collection: [Bool] = Array(repeating: true, count: size);
	//Find find prime number
	obj.sieve_of_eratosthenes( &collection, size);
	//Test case
	obj.is_prime_power(collection, 9);
	obj.is_prime_power(collection, 1331);
	obj.is_prime_power(collection, 2187);
	obj.is_prime_power(collection, 81);
	obj.is_prime_power(collection, 452);
	obj.is_prime_power(collection, 361);
	obj.is_prime_power(collection, 512);
}
main();

Output

 Number [ 9 ] is prime power number of ( 3 ^ 2 )
 Number [ 1331 ] is prime power number of ( 11 ^ 3 )
 Number [ 2187 ] is prime power number of ( 3 ^ 7 )
 Number [ 81 ] is prime power number of ( 3 ^ 4 )
 Number [ 452 ] is not prime power number
 Number [ 361 ] is prime power number of ( 19 ^ 2 )
 Number [ 512 ] is prime power number of ( 2 ^ 9 )


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