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Check if given number is emirp number or not

Here given code implementation process.

// C program
// Check if given number is emirp number or not
#include <stdio.h>

//Check that whether given number is prime or not
int is_prime(int number)
{
	if (number == 2 || number == 3 || number == 5)
	{
		// Base case
		return 1;
	}
	else if (number <= 1 || (number % 2 == 0) || (number % 3 == 0) || (number % 5 == 0))
	{
		//When number is divisible by (2,3,5) or less than 2
		return 0;
	}
	int i = 11;
	while ((i * i) <= number)
	{
		if (number % i == 0)
		{
			//When number is divisible of current i value
			return 0;
		}
		else if (number % (i + 2) == 0)
		{
			//When number is divisible of current i + 2 value
			return 0;
		}
		i = i + 6;
	}
	return 1;
}
int reverse_num(int number)
{
	int result = 0;
	while (number != 0)
	{
		result = result * 10 + (number % 10);
		number = number / 10;
	}
	//returning the reversal of number
	return result;
}
void is_emirp_number(int number)
{
	if (is_prime(number) && is_prime(reverse_num(number)))
	{
		//When given number is prime
		//And its reverse is also a prime number
		printf("\n [%d] Is Emirp Number", number);
	}
	else
	{
		printf("\n [%d] Is Not Emirp Number", number);
	}
}
int main()
{
	//Test case
	is_emirp_number(13);
	is_emirp_number(12);
	is_emirp_number(1091);
	is_emirp_number(131);
	is_emirp_number(123);
	is_emirp_number(149);
	is_emirp_number(143);
	is_emirp_number(157);
	return 0;
}

Output

 [13] Is Emirp Number
 [12] Is Not Emirp Number
 [1091] Is Emirp Number
 [131] Is Emirp Number
 [123] Is Not Emirp Number
 [149] Is Emirp Number
 [143] Is Not Emirp Number
 [157] Is Emirp Number
/* 
  Java program 
  Check if given number is emirp number or not
*/
class EmirpNumber
{
	//Check that whether given number is prime or not
	public boolean is_prime(int number)
	{
		if (number == 2 || number == 3 || number == 5)
		{
			// Base case
			return true;
		}
		else if (number <= 1 || (number % 2 == 0) || (number % 3 == 0) || (number % 5 == 0))
		{
			//When number is divisible by (2,3,5) or less than 2
			return false;
		}
		int i = 11;
		while ((i * i) <= number)
		{
			if (number % i == 0)
			{
				//When number is divisible of current i value
				return false;
			}
			else if (number % (i + 2) == 0)
			{
				//When number is divisible of current i + 2 value
				return false;
			}
			i = i + 6;
		}
		return true;
	}
	public int reverse_num(int number)
	{
		int result = 0;
		while (number != 0)
		{
			result = result * 10 + (number % 10);
			number = number / 10;
		}
		//returning the reversal of number
		return result;
	}
	public void is_emirp_number(int number)
	{
		if (is_prime(number) && is_prime(reverse_num(number)))
		{
			//When given number is prime
			//And its reverse is also a prime number
			System.out.print("\n [" + number + "] Is Emirp Number");
		}
		else
		{
			System.out.print("\n [" + number + "] Is Not Emirp Number");
		}
	}
	public static void main(String[] args)
	{
		EmirpNumber obj = new EmirpNumber();
		//Test case
		obj.is_emirp_number(13);
		obj.is_emirp_number(12);
		obj.is_emirp_number(1091);
		obj.is_emirp_number(131);
		obj.is_emirp_number(123);
		obj.is_emirp_number(149);
		obj.is_emirp_number(143);
		obj.is_emirp_number(157);
	}
}

Output

 [13] Is Emirp Number
 [12] Is Not Emirp Number
 [1091] Is Emirp Number
 [131] Is Emirp Number
 [123] Is Not Emirp Number
 [149] Is Emirp Number
 [143] Is Not Emirp Number
 [157] Is Emirp Number
//Include header file
#include <iostream>

using namespace std;
/*
  C++ program 
  Check if given number is emirp number or not
*/
class EmirpNumber
{
	public:
		//Check that whether given number is prime or not
		bool is_prime(int number)
		{
			if (number == 2 || number == 3 || number == 5)
			{
				// Base case
				return true;
			}
			else if (number <= 1 || (number % 2 == 0) || (number % 3 == 0) || (number % 5 == 0))
			{
				//When number is divisible by (2,3,5) or less than 2
				return false;
			}
			int i = 11;
			while ((i *i) <= number)
			{
				if (number % i == 0)
				{
					//When number is divisible of current i value
					return false;
				}
				else if (number % (i + 2) == 0)
				{
					//When number is divisible of current i + 2 value
					return false;
				}
				i = i + 6;
			}
			return true;
		}
	int reverse_num(int number)
	{
		int result = 0;
		while (number != 0)
		{
			result = result *10 + (number % 10);
			number = number / 10;
		}
		//returning the reversal of number
		return result;
	}
	void is_emirp_number(int number)
	{
		if (this->is_prime(number) && this->is_prime(this->reverse_num(number)))
		{
			//When given number is prime
			//And its reverse is also a prime number
			cout << "\n [" << number << "] Is Emirp Number";
		}
		else
		{
			cout << "\n [" << number << "] Is Not Emirp Number";
		}
	}
};
int main()
{
	EmirpNumber obj = EmirpNumber();
	//Test case
	obj.is_emirp_number(13);
	obj.is_emirp_number(12);
	obj.is_emirp_number(1091);
	obj.is_emirp_number(131);
	obj.is_emirp_number(123);
	obj.is_emirp_number(149);
	obj.is_emirp_number(143);
	obj.is_emirp_number(157);
	return 0;
}

Output

 [13] Is Emirp Number
 [12] Is Not Emirp Number
 [1091] Is Emirp Number
 [131] Is Emirp Number
 [123] Is Not Emirp Number
 [149] Is Emirp Number
 [143] Is Not Emirp Number
 [157] Is Emirp Number
//Include namespace system
using System;
/* 
  C# program 
  Check if given number is emirp number or not
*/
class EmirpNumber
{
	//Check that whether given number is prime or not
	public Boolean is_prime(int number)
	{
		if (number == 2 || number == 3 || number == 5)
		{
			// Base case
			return true;
		}
		else if (number <= 1 || (number % 2 == 0) || (number % 3 == 0) || (number % 5 == 0))
		{
			//When number is divisible by (2,3,5) or less than 2
			return false;
		}
		int i = 11;
		while ((i * i) <= number)
		{
			if (number % i == 0)
			{
				//When number is divisible of current i value
				return false;
			}
			else if (number % (i + 2) == 0)
			{
				//When number is divisible of current i + 2 value
				return false;
			}
			i = i + 6;
		}
		return true;
	}
	public int reverse_num(int number)
	{
		int result = 0;
		while (number != 0)
		{
			result = result * 10 + (number % 10);
			number = number / 10;
		}
		//returning the reversal of number
		return result;
	}
	public void is_emirp_number(int number)
	{
		if (is_prime(number) && is_prime(reverse_num(number)))
		{
			//When given number is prime
			//And its reverse is also a prime number
			Console.Write("\n [" + number + "] Is Emirp Number");
		}
		else
		{
			Console.Write("\n [" + number + "] Is Not Emirp Number");
		}
	}
	public static void Main(String[] args)
	{
		EmirpNumber obj = new EmirpNumber();
		//Test case
		obj.is_emirp_number(13);
		obj.is_emirp_number(12);
		obj.is_emirp_number(1091);
		obj.is_emirp_number(131);
		obj.is_emirp_number(123);
		obj.is_emirp_number(149);
		obj.is_emirp_number(143);
		obj.is_emirp_number(157);
	}
}

Output

 [13] Is Emirp Number
 [12] Is Not Emirp Number
 [1091] Is Emirp Number
 [131] Is Emirp Number
 [123] Is Not Emirp Number
 [149] Is Emirp Number
 [143] Is Not Emirp Number
 [157] Is Emirp Number
<?php
/* 
  Php program 
  Check if given number is emirp number or not
*/
class EmirpNumber
{
	//Check that whether given number is prime or not
	public	function is_prime($number)
	{
		if ($number == 2 || $number == 3 || $number == 5)
		{
			// Base case
			return true;
		}
		else if ($number <= 1 || ($number % 2 == 0) || ($number % 3 == 0) || ($number % 5 == 0))
		{
			//When number is divisible by (2,3,5) or less than 2
			return false;
		}
		$i = 11;
		while (($i * $i) <= $number)
		{
			if ($number % $i == 0)
			{
				//When number is divisible of current i value
				return false;
			}
			else if ($number % ($i + 2) == 0)
			{
				//When number is divisible of current i + 2 value
				return false;
			}
			$i = $i + 6;
		}
		return true;
	}
	public	function reverse_num($number)
	{
		$result = 0;
		while ($number != 0)
		{
			$result = $result * 10 + ($number % 10);
			$number = intval($number / 10);
		}
		//returning the reversal of number
		return $result;
	}
	public	function is_emirp_number($number)
	{
		if ($this->is_prime($number) && $this->is_prime($this->reverse_num($number)))
		{
			//When given number is prime
			//And its reverse is also a prime number
			echo "\n [". $number ."] Is Emirp Number";
		}
		else
		{
			echo "\n [". $number ."] Is Not Emirp Number";
		}
	}
}

function main()
{
	$obj = new EmirpNumber();
	//Test case
	$obj->is_emirp_number(13);
	$obj->is_emirp_number(12);
	$obj->is_emirp_number(1091);
	$obj->is_emirp_number(131);
	$obj->is_emirp_number(123);
	$obj->is_emirp_number(149);
	$obj->is_emirp_number(143);
	$obj->is_emirp_number(157);
}
main();

Output

 [13] Is Emirp Number
 [12] Is Not Emirp Number
 [1091] Is Emirp Number
 [131] Is Emirp Number
 [123] Is Not Emirp Number
 [149] Is Emirp Number
 [143] Is Not Emirp Number
 [157] Is Emirp Number
/* 
  Node Js program 
  Check if given number is emirp number or not
*/
class EmirpNumber
{
	//Check that whether given number is prime or not
	is_prime(number)
	{
		if (number == 2 || number == 3 || number == 5)
		{
			// Base case
			return true;
		}
		else if (number <= 1 || (number % 2 == 0) || (number % 3 == 0) || (number % 5 == 0))
		{
			//When number is divisible by (2,3,5) or less than 2
			return false;
		}
		var i = 11;
		while ((i * i) <= number)
		{
			if (number % i == 0)
			{
				//When number is divisible of current i value
				return false;
			}
			else if (number % (i + 2) == 0)
			{
				//When number is divisible of current i + 2 value
				return false;
			}
			i = i + 6;
		}
		return true;
	}
	reverse_num(number)
	{
		var result = 0;
		while (number != 0)
		{
			result = result * 10 + (number % 10);
			number = parseInt(number / 10);
		}
		//returning the reversal of number
		return result;
	}
	is_emirp_number(number)
	{
		if (this.is_prime(number) && this.is_prime(this.reverse_num(number)))
		{
			//When given number is prime
			//And its reverse is also a prime number
			process.stdout.write("\n [" + number + "] Is Emirp Number");
		}
		else
		{
			process.stdout.write("\n [" + number + "] Is Not Emirp Number");
		}
	}
}

function main()
{
	var obj = new EmirpNumber();
	//Test case
	obj.is_emirp_number(13);
	obj.is_emirp_number(12);
	obj.is_emirp_number(1091);
	obj.is_emirp_number(131);
	obj.is_emirp_number(123);
	obj.is_emirp_number(149);
	obj.is_emirp_number(143);
	obj.is_emirp_number(157);
}
main();

Output

 [13] Is Emirp Number
 [12] Is Not Emirp Number
 [1091] Is Emirp Number
 [131] Is Emirp Number
 [123] Is Not Emirp Number
 [149] Is Emirp Number
 [143] Is Not Emirp Number
 [157] Is Emirp Number
#   Python 3 program 
#   Check if given number is emirp number or not

class EmirpNumber :
	# Check that whether given number is prime or not
	def is_prime(self, number) :
		if (number == 2 or number == 3 or number == 5) :
			#  Base case
			return True
		
		elif(number <= 1 or(number % 2 == 0) or(number % 3 == 0) or(number % 5 == 0)) :
			# When number is divisible by (2,3,5) or less than 2
			return False
		
		i = 11
		while ((i * i) <= number) :
			if (number % i == 0) :
				# When number is divisible of current i value
				return False
			
			elif(number % (i + 2) == 0) :
				# When number is divisible of current i + 2 value
				return False
			
			i = i + 6
		
		return True
	
	def reverse_num(self, number) :
		result = 0
		while (number != 0) :
			result = result * 10 + (number % 10)
			number = int(number / 10)
		
		# returning the reversal of number
		return result
	
	def is_emirp_number(self, number) :
		if (self.is_prime(number) and self.is_prime(self.reverse_num(number))) :
			# When given number is prime
			# And its reverse is also a prime number
			print("\n [", number ,"] Is Emirp Number", end = "")
		else :
			print("\n [", number ,"] Is Not Emirp Number", end = "")
		
	

def main() :
	obj = EmirpNumber()
	# Test case
	obj.is_emirp_number(13)
	obj.is_emirp_number(12)
	obj.is_emirp_number(1091)
	obj.is_emirp_number(131)
	obj.is_emirp_number(123)
	obj.is_emirp_number(149)
	obj.is_emirp_number(143)
	obj.is_emirp_number(157)

if __name__ == "__main__": main()

Output

 [ 13 ] Is Emirp Number
 [ 12 ] Is Not Emirp Number
 [ 1091 ] Is Emirp Number
 [ 131 ] Is Emirp Number
 [ 123 ] Is Not Emirp Number
 [ 149 ] Is Emirp Number
 [ 143 ] Is Not Emirp Number
 [ 157 ] Is Emirp Number
#   Ruby program 
#   Check if given number is emirp number or not

class EmirpNumber 
	# Check that whether given number is prime or not
	def is_prime(number) 
		if (number == 2 || number == 3 || number == 5) 
			#  Base case
			return true
		elsif(number <= 1 || (number % 2 == 0) || (number % 3 == 0) || (number % 5 == 0)) 
			# When number is divisible by (2,3,5) or less than 2
			return false
		end

		i = 11
		while ((i * i) <= number) 
			if (number % i == 0) 
				# When number is divisible of current i value
				return false
			elsif(number % (i + 2) == 0) 
				# When number is divisible of current i + 2 value
				return false
			end

			i = i + 6
		end

		return true
	end

	def reverse_num(number) 
		result = 0
		while (number != 0) 
			result = result * 10 + (number % 10)
			number = number / 10
		end

		# returning the reversal of number
		return result
	end

	def is_emirp_number(number) 
		if (self.is_prime(number) && self.is_prime(self.reverse_num(number))) 
			# When given number is prime
			# And its reverse is also a prime number
			print("\n [", number ,"] Is Emirp Number")
		else 
			print("\n [", number ,"] Is Not Emirp Number")
		end

	end

end

def main() 
	obj = EmirpNumber.new()
	# Test case
	obj.is_emirp_number(13)
	obj.is_emirp_number(12)
	obj.is_emirp_number(1091)
	obj.is_emirp_number(131)
	obj.is_emirp_number(123)
	obj.is_emirp_number(149)
	obj.is_emirp_number(143)
	obj.is_emirp_number(157)
end

main()

Output

 [13] Is Emirp Number
 [12] Is Not Emirp Number
 [1091] Is Emirp Number
 [131] Is Emirp Number
 [123] Is Not Emirp Number
 [149] Is Emirp Number
 [143] Is Not Emirp Number
 [157] Is Emirp Number
/* 
  Scala program 
  Check if given number is emirp number or not
*/
class EmirpNumber
{
	//Check that whether given number is prime or not
	def is_prime(number: Int): Boolean = {
		if (number == 2 || number == 3 || number == 5)
		{
			// Base case
			return true;
		}
		else if (number <= 1 || (number % 2 == 0) || (number % 3 == 0) || (number % 5 == 0))
		{
			//When number is divisible by (2,3,5) or less than 2
			return false;
		}
		var i: Int = 11;
		while ((i * i) <= number)
		{
			if (number % i == 0)
			{
				//When number is divisible of current i value
				return false;
			}
			else if (number % (i + 2) == 0)
			{
				//When number is divisible of current i + 2 value
				return false;
			}
			i = i + 6;
		}
		return true;
	}
	def reverse_num(n: Int): Int = {
		var result: Int = 0;
      	var number: Int = n;
		while (number != 0)
		{
			result = result * 10 + (number % 10);
			number = (number / 10).toInt;
		}
		//returning the reversal of number
		return result;
	}
	def is_emirp_number(number: Int): Unit = {
		if (is_prime(number) && is_prime(reverse_num(number)))
		{
			//When given number is prime
			//And its reverse is also a prime number
			print("\n [" + number + "] Is Emirp Number");
		}
		else
		{
			print("\n [" + number + "] Is Not Emirp Number");
		}
	}
}
object Main
{
	def main(args: Array[String]): Unit = {
		var obj: EmirpNumber = new EmirpNumber();
		//Test case
		obj.is_emirp_number(13);
		obj.is_emirp_number(12);
		obj.is_emirp_number(1091);
		obj.is_emirp_number(131);
		obj.is_emirp_number(123);
		obj.is_emirp_number(149);
		obj.is_emirp_number(143);
		obj.is_emirp_number(157);
	}
}

Output

 [13] Is Emirp Number
 [12] Is Not Emirp Number
 [1091] Is Emirp Number
 [131] Is Emirp Number
 [123] Is Not Emirp Number
 [149] Is Emirp Number
 [143] Is Not Emirp Number
 [157] Is Emirp Number
/* 
  Swift 4 program 
  Check if given number is emirp number or not
*/
class EmirpNumber
{
	//Check that whether given number is prime or not
	func is_prime(_ number: Int) -> Bool
	{
		if (number == 2 || number == 3 || number == 5)
		{
			// Base case
			return true;
		}
		else if (number <= 1 || (number % 2 == 0) || (number % 3 == 0) || (number % 5 == 0))
		{
			//When number is divisible by (2,3,5) or less than 2
			return false;
		}
		var i: Int = 11;
		while ((i * i) <= number)
		{
			if (number % i == 0)
			{
				//When number is divisible of current i value
				return false;
			}
			else if (number % (i + 2) == 0)
			{
				//When number is divisible of current i + 2 value
				return false;
			}
			i = i + 6;
		}
		return true;
	}
	func reverse_num(_ n : Int) -> Int
	{
		var result: Int = 0;
      	var number: Int = n;
		while (number != 0)
		{
			result = result * 10 + (number % 10);
			number = number / 10;
		}
		//returning the reversal of number
		return result;
	}
	func is_emirp_number(_ number: Int)
	{
		if (self.is_prime(number) && self.is_prime(self.reverse_num(number)))
		{
			//When given number is prime
			//And its reverse is also a prime number
			print("\n [", number ,"] Is Emirp Number", terminator: "");
		}
		else
		{
			print("\n [", number ,"] Is Not Emirp Number", terminator: "");
		}
	}
}
func main()
{
	let obj: EmirpNumber = EmirpNumber();
	//Test case
	obj.is_emirp_number(13);
	obj.is_emirp_number(12);
	obj.is_emirp_number(1091);
	obj.is_emirp_number(131);
	obj.is_emirp_number(123);
	obj.is_emirp_number(149);
	obj.is_emirp_number(143);
	obj.is_emirp_number(157);
}
main();

Output

 [ 13 ] Is Emirp Number
 [ 12 ] Is Not Emirp Number
 [ 1091 ] Is Emirp Number
 [ 131 ] Is Emirp Number
 [ 123 ] Is Not Emirp Number
 [ 149 ] Is Emirp Number
 [ 143 ] Is Not Emirp Number
 [ 157 ] Is Emirp Number
Last updated on by Kalkicode




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