# Check for continuous binary tree in scala

Scala program for Check for continuous binary tree. Here problem description and explanation.

``````/*
Scala program for
Check if binary tree is continuous tree
Using recursion
*/
// Binary Tree Node
class TreeNode(var data: Int,
var left: TreeNode,
var right: TreeNode)
{
def this(data: Int)
{
// Set node value
this(data, null, null);
}
}
class BinaryTree(var root: TreeNode)
{
def this()
{
this(null);
}
def absValue(num: Int): Int = {
if (num < 0)
{
return -num;
}
return num;
}
// Check tree is continuous or not
def isContinuous(node: TreeNode): Boolean = {
if (node != null)
{
if ((node.left != null &&
absValue(node.data - node.left.data) != 1) ||
(node.right != null &&
absValue(node.data - node.right.data) != 1))
{
// Case
// When fail continuous tree rule
return false;
}
if (isContinuous(node.left) &&
isContinuous(node.right))
{
return true;
}
// When node value is not satisfied
//  continuous tree properties
return false;
}
return true;
}
}
object Main
{
def main(args: Array[String]): Unit = {
// Create new tree
var tree: BinaryTree = new BinaryTree();
/*
Binary Tree
------------
5
/   \
4     4
/     /  \
3     5    3
\
2

*/
tree.root = new TreeNode(5);
tree.root.left = new TreeNode(4);
tree.root.right = new TreeNode(4);
tree.root.left.left = new TreeNode(3);
tree.root.right.right = new TreeNode(3);
tree.root.right.left = new TreeNode(5);
tree.root.left.left.right = new TreeNode(2);
if (tree.isContinuous(tree.root) == true)
{
println("Continuous Tree ");
}
else
{
println("Not Continuous Tree ");
}
// Case 2
/*
5
/   \
4     4
/     /  \
3     5    3
\
1  <--- change value

*/
tree.root.left.left.right.data = 1;
if (tree.isContinuous(tree.root) == true)
{
println("Continuous Tree ");
}
else
{
println("Not Continuous Tree ");
}
}
}``````

Output

``````Continuous Tree
Not Continuous Tree``````

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