Check for continuous binary tree in c#
Csharp program for Check for continuous binary tree. Here problem description and other solutions.
// Include namespace system
using System;
/*
Csharp program for
Check if binary tree is continuous tree
Using recursion
*/
// Binary Tree Node
public class TreeNode
{
public int data;
public TreeNode left;
public TreeNode right;
public TreeNode(int data)
{
// Set node value
this.data = data;
this.left = null;
this.right = null;
}
}
public class BinaryTree
{
public TreeNode root;
public BinaryTree()
{
// Set initial tree root
this.root = null;
}
public int absValue(int num)
{
if (num < 0)
{
return -num;
}
return num;
}
// Check tree is continuous or not
public bool isContinuous(TreeNode node)
{
if (node != null)
{
if ((node.left != null &&
this.absValue(node.data - node.left.data) != 1) ||
(node.right != null &&
this.absValue(node.data - node.right.data) != 1))
{
// Case
// When fail continuous tree rule
return false;
}
if (this.isContinuous(node.left) &&
this.isContinuous(node.right))
{
return true;
}
// When node value is not satisfied
// continuous tree properties
return false;
}
return true;
}
public static void Main(String[] args)
{
// Create new tree
var tree = new BinaryTree();
/*
Binary Tree
------------
5
/ \
4 4
/ / \
3 5 3
\
2
*/
// Add tree node
tree.root = new TreeNode(5);
tree.root.left = new TreeNode(4);
tree.root.right = new TreeNode(4);
tree.root.left.left = new TreeNode(3);
tree.root.right.right = new TreeNode(3);
tree.root.right.left = new TreeNode(5);
tree.root.left.left.right = new TreeNode(2);
if (tree.isContinuous(tree.root) == true)
{
Console.WriteLine("Continuous Tree ");
}
else
{
Console.WriteLine("Not Continuous Tree ");
}
// Case 2
/*
5
/ \
4 4
/ / \
3 5 3
\
1 <--- change value
*/
tree.root.left.left.right.data = 1;
if (tree.isContinuous(tree.root) == true)
{
Console.WriteLine("Continuous Tree ");
}
else
{
Console.WriteLine("Not Continuous Tree ");
}
}
}
Output
Continuous Tree
Not Continuous Tree
Please share your knowledge to improve code and content standard. Also submit your doubts, and test case. We improve by your feedback. We will try to resolve your query as soon as possible.
New Comment