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Anticlockwise spiral view of diamond matrix elements in python

Anticlockwise spiral view of matrix

Python program for Anticlockwise spiral view of diamond matrix elements. Here mentioned other language solution.

#  Python 3 program for
#  Anticlockwise spiral view of diamond element in matrix
class SpiralTraversal :
    #  Method which is displaying the Anticlockwise spiral 
    #  Of matrix in diamond(mid) element
    def spiralView(self, matrix,  x,  y,  p,  q,  k) :
        #  Find the middle column
        midCol = y + (int((q - y) / 2))
        #  Get middle row (valid for odd square matrix)
        midRow = midCol
        #  Matrix are divided into 4 section
        #  Starting of middle row and column in form of top
        #  Case A
        #  Top to Left-bottom
        i = midCol
        j = 0
        while (i > y and k > 0) :
            print(matrix[x + j][i], end =" ")
            i -= 1
            k -= 1
            j += 1
        #  Case B
        #  Middle left to middle right bottom
        i = y
        j = 0
        while (i <= midCol and k > 0) :
            print(matrix[(midRow) + j][i], end =" ")
            i += 1
            k -= 1
            j += 1
        #  Case C
        #  Middle bottom to middle right side 
        i = midCol + 1
        j = 1
        while (i <= q and k > 0) :
            print(matrix[(p) - j][i], end =" ")
            i += 1
            k -= 1
            j += 1
        #  Case D
        #  Middle right side to  top middle 
        i = q - 1
        j = 1
        while (i > midCol and k > 0) :
            print(matrix[(midRow) - j][i], end =" ")
            i -= 1
            k -= 1
            j += 1
        if (x + 1 <= p - 1 and k > 0) :
            #  Recursive call
            self.spiralView(matrix, x + 1, y + 1, p - 1, q - 1, k)
    def diamondAnticlockwise(self, matrix) :
        row = len(matrix)
        col = len(matrix[0])
        #  Check whether the given matrix is a valid odd shape or not
        if (row != col or col % 2 == 0) :
            #  When Yes not a valid size
            print("\nNot a valid perfect Odd square matrix")
            return
        #  (row*col)-((col+1)/2)*4 are provide the value of number of 
        #  Diamond element
        self.spiralView(matrix, 0, 0, row - 1, 
            col - 1, (row * col) - (int((col + 1) / 2)) * 4)
def main() :
    task = SpiralTraversal()
    #  Define matrix 
    matrix = [
        [1, 2, 3, 4, 5], 
        [6, 7, 8, 9, 10], 
        [11, 12, -1, 15, 16], 
        [17, 18, 19, 20, 21], 
        [22, 23, 24, 25, 26]
    ]
    task.diamondAnticlockwise(matrix)


if __name__=="__main__":
    main()

Output

3 7 11 18 24 20 16 9 8 12 19 15 -1




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