# Anticlockwise spiral view of diamond matrix elements in golang

Go program for Anticlockwise spiral view of diamond matrix elements. Here mentioned other language solution.

``````package main
import "fmt"
/*
Go program for
Anticlockwise spiral view of diamond element in matrix
*/

// Method which is displaying the Anticlockwise spiral
// Of matrix in diamond(mid) element
func spiralView(matrix[][] int, x int,
y int, p int, q int, k int) {
// Find the middle column
var midCol int = y + ((q - y) / 2)
// Get middle row (valid for odd square matrix)
var midRow int = midCol
// Matrix are divided into 4 section
// Starting of middle row and column in form of top
// Case A
// Top to Left-bottom
var i int = midCol
var j int = 0
for (i > y && k > 0) {
fmt.Print("  ", matrix[x + j][i])
i--
k--
j++
}
// Case B
// Middle left to middle right bottom
i = y
j = 0
for (i <= midCol && k > 0) {
fmt.Print("  ", matrix[(midRow) + j][i])
i++
k--
j++
}
// Case C
// Middle bottom to middle right side
i = midCol + 1
j = 1
for (i <= q && k > 0) {
fmt.Print("  ", matrix[(p) - j][i])
i++
k--
j++
}
// Case D
// Middle right side to  top middle
i = q - 1
j = 1
for (i > midCol && k > 0) {
fmt.Print("  ", matrix[(midRow) - j][i])
i--
k--
j++
}
if x + 1 <= p - 1 && k > 0 {
// Recursive call
spiralView(matrix, x + 1, y + 1, p - 1, q - 1, k)
}
}
func diamondAnticlockwise(matrix[][] int) {
var row int = len(matrix)
var col int = len(matrix[0])
// Check whether the given matrix is a valid odd shape or not
if row != col || col % 2 == 0 {
// When Yes not a valid size
fmt.Println("\nNot a valid perfect Odd square matrix")
return
}
// (row*col)-((col+1)/2)*4 are provide the value of number of
// Diamond element
spiralView(matrix, 0, 0, row - 1, col - 1,
(row * col) - ((col + 1) / 2) * 4)
}
func main() {
// Define matrix
var matrix = [][] int {
{1,  2,  3,  4,  5},
{6,  7,  8,  9,  10},
{11, 12, -1, 15,  16},
{17, 18, 19, 20,  21},
{22, 23, 24, 25,  26}}
diamondAnticlockwise(matrix)
}``````

Output

``   3   7  11  18  24  20  16   9   8  12  19  15  -1``

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