Alternating split of singly linked list in python

Python program for Alternating split of singly linked list. Here problem description and explanation.

#  Python 3 program for
#  Alternating split of a given singly linked list

#  Node of LinkedList
class LinkNode :
	def __init__(self, data) :
		#  Set node value
		self.data = data
		self.next = None
	

class MyLinkedList :
	def __init__(self) :
		self.head = None
	
	#  Add new node at the end of linked list
	def insert(self, value) :
		#  Create a new node
		node = LinkNode(value)
		if (self.head == None) :
			self.head = node
		else :
			temp = self.head
			#  Find last node
			while (temp.next != None) :
				#  Visit to next node
				temp = temp.next
			
			#  Add node at last position
			temp.next = node
		
	
	#  Display all Linked List elements
	def display(self) :
		if (self.head != None) :
			temp = self.head
			while (temp != None) :
				#  Display node value
				print(temp.data, end = "  ")
				#  Visit to next node
				temp = temp.next
			
		else :
			print("Empty Linked list")
		
	
	#  Split the linked list by alternating nodes
	def splitting(self) :
		result = None
		if (self.head != None) :
			#  Some auxiliary variables
			temp = self.head
			tail = None
			current = None
			prev = self.head
			while (temp != None and temp.next != None) :
				current = temp.next
				prev = temp
				temp = temp.next.next
				if (result == None) :
					#  When first node of second linked list
					current.next = result
					result = current
					tail = current
				else :
					#  Add Alternating node to end of 
					#  second linked list
					current.next = tail.next
					tail.next = current
					tail = current
				
				prev.next = temp
			
		
		return result
	

def main() :
	l1 = MyLinkedList()
	l2 = MyLinkedList()
	#  Add node in l1 linked list
	l1.insert(1)
	l1.insert(2)
	l1.insert(3)
	l1.insert(4)
	l1.insert(5)
	l1.insert(6)
	l1.insert(7)
	l1.insert(8)
	#  Before splitting l1
	print("L1 list : ", end = "")
	l1.display()
	l2.head = l1.splitting()
	print("\nAfter splitting ")
	print("L1 list : ", end = "")
	l1.display()
	print("\nL2 list : ", end = "")
	l2.display()

if __name__ == "__main__": main()

Output

L1 list : 1  2  3  4  5  6  7  8
After splitting
L1 list : 1  3  5  7
L2 list : 2  4  6  8